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12.3 Surface Area of Pyramids and Cones

12.3 Surface Area of Pyramids and Cones. Geometry Ms. Reser. Objectives/Assignment. Find the surface area of a pyramid. Find the surface area of a cone. Assignment: WS 12.3A. Finding the surface area of a pyramid.

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12.3 Surface Area of Pyramids and Cones

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  1. 12.3 Surface Area of Pyramids and Cones Geometry Ms. Reser

  2. Objectives/Assignment • Find the surface area of a pyramid. • Find the surface area of a cone. • Assignment: WS 12.3A

  3. Finding the surface area of a pyramid • A pyramid is a polyhedron in which the base is a polygon and the lateral faces are triangles with a common vertex. The intersection of two lateral faces is a lateral edge. The intersection of the base and a lateral face is a base edge. The altitude or height of a pyramid is the perpendicular distance between the base and the vertex.

  4. A regular pyramid has a regular polygon for a base and its height meets the base at its center. The slant height of a regular pyramid is the altitude of any lateral face. A nonregular pyramid does not have a slant height. More on pyramids

  5. Pyramid Arena

  6. Ex. 1: Finding the Area of a Lateral Face • Architecture. The lateral faces of the Pyramid Arena in Memphis, Tennessee, are covered with steal panels. Use the diagram of the arena to find the area of each lateral face of this regular pyramid.

  7. A regular hexagonal pyramid and its net are shown at the right. Let b represent the length of a base edge, and let l represent the slant height of the pyramid. The area of each lateral face is 1/2bl and the perimeter of the base if P = 6b. So the surface area is as follows: Hexagonal Pyramids

  8. Hexagonal pyramid S = (Area of base) + 6(Area of lateral face) S = B + 6( ½ bl) Substitute Rewrite 6( ½ bl) as ½ (6b)l. S = B + (6b)l Substitute P for 6b S = B + Pl Surface Area of a Regular Pyramid The surface area S of a regular pyramid is: S = B + ½ Pl, where B is the area of the base, P is the perimeter of the base, and l is the slant height.

  9. To find the surface area of the regular pyramid shown, start by finding the area of the base. Use the formula for the area of a regular polygon, ½ (apothem)(perimeter). A diagram of the base is shown to the right. Ex. 2: Finding the surface area of a pyramid

  10. Ex. 2: Finding the surface area of a pyramid After substituting, the area of the base is ½ (3 )(6• 6), or • square meters.

  11. Surface area • Now you can find the surface area by using 54 for the area of the base, B.

  12. A circular cone, or cone, has a circular base and a vertex that is NOT in the same plane as the base. The altitude, or height, is the perpendicular distance between the vertex and the base. In a right cone, the height meets the base at its center and the slant height is the distance between the vertex and a point on the base edge. Finding the Surface Area of a Cone

  13. The lateral surface of a cone consists of all segments that connect the vertex with points on the base edge. When you cut along the slant height and like the cone flat, you get the net shown at the right. In the net, the circular base has an area of r2 and the lateral surface area is the sector of a circle. Finding the Surface Area of a Cone

  14. More on cones . . . • You can find the area of this sector by using a proportion, as shown below. Area of sector Arc length = Set up proportion Area of circle Circumference 2r Area of sector Substitute = l2 2l 2r Multiply each side by l2 Area of sector = l2• 2l Area of sector = rl Simplify The surface area of a cone is the sum of the base area and the lateral area, rl.

  15. Surface Area of a Right Cone The surface area S of a right cone is S = r2 + rl, where r is the radius of the base and l is the slant height Theorem

  16. Ex. 3: Finding the surface area of a cone • To find the surface area of the right cone shown, use the formula for the surface area. S = r2 + rl Write formula S = 42 + (4)(6) Substitute S = 16 + 24 Simplify S = 40 Simplify The surface area is 40 square inches or about 125.7 square inches.

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