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Answers of Exercise 2

Answers of Exercise 2. 1. Use Nyquist's Theorem to determine the maximum rate in bits per second at which data can be send across a transmission system that has a bandwidth of 4000 Hz and use four values of voltage to encode information. What's the maximum rate when encoding the

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Answers of Exercise 2

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  1. Answers of Exercise 2 1. Use Nyquist's Theorem to determine the maximum rate in bits per second at which data can be send across a transmission system that has a bandwidth of 4000 Hz and use four values of voltage to encode information. What's the maximum rate when encoding the information with 16 values of voltage? Answer: When M=4, D=2x4000xlog24 =16000bps=16kbps When M=16, D=2x4000xlog216=32000bps=32kbps 2. Is it possible to increase a number of the encoded values without limit in order to increase transmission speed of system? Why? Assume a bandwidth of a system is 4000 Hz and a signal-to-noise ratio S/N=1023, What's the maximum rate of the system? Answer: No, due to existence of noise. C=4000xlog2(1+1023)=40kbps 3. (True/false) A digital modulator using ASK, PSK or QAM is a digital-to-digital system. Answer: False! A digital modulator is a digital-to-analogy system. 4. (1) If the bit rate of 4-PSK signal is 2400bps, what’s its baud rate? Answer: 1200 baud (2) If the baud rate of 256-QAM is 2400 baud, what’s its bit rate? Answer: 19.2kbps 5. The bite rate of one digital telephone channel is 64Kbps. If the transmission capacity of a single optical fiber is 2Gbps, how many telephone channel can be multiplexed to the fiber? Assume TDM is used. Answer: 2x109/(64x103)=31250 telephone channels

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