1 / 20

Day of Wrath

Day of Wrath. Tuesday June 16 9:30-11:30 am CNH-104 30 MC Questions, Cumulative. Fluid Mechanics. Pressure Buoyancy. Buoyancy. The fluid exerts an upward force on the object equal to the weight of fluid displaced.

Download Presentation

Day of Wrath

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Day of Wrath Tuesday June 169:30-11:30 amCNH-104 30 MC Questions, Cumulative Physics 1B03summer-Lecture 12

  2. Fluid Mechanics • Pressure • Buoyancy Physics 1B03summer-Lecture 12

  3. Buoyancy The fluid exerts an upward force on the object equal to the weight of fluid displaced. This force is result of pressure differences in the fluid; the pressure is greater at the bottom than at the top.This is why objects can ‘float’: the magnitude of the buoyant force equals that of the force of gravity: P1 h P2 B = Fgso:B = mg = ρoVog Physics 1B03summer-Lecture 12

  4. ? Archimedes’s Principle: the magnitude of the buoyant force always equals the weight of the fluid displaced by the object. Question: A boat filled with bricks floats in a swimming pool. If the bricks are dumped overboard does the water level in the pool rise, or fall? Physics 1B03summer-Lecture 12

  5. Totally Submerged Object For an object submerged in a fluid with ρf the upward force is B=ρfVog (=weight of fluid displaced) and so the net force is:B – Fg = ρfVog - ρoVog = (ρf – ρo)Vog Floating Object For a floating object, it displaces a volume of fluid equal to its own volume, and so: B = Fg ρfVfg = ρoVog Physics 1B03summer-Lecture 12

  6. Example A giant ice cube (r= 917 kg/m3) floats in a pail of cold water. If the cube is 100.0 mm on each side, how far is the top surface of the ice above the water? When the ice melts, does the level of water in the pail rise or fall? Physics 1B03summer-Lecture 12

  7. Example A beach ball of mass 0.05 kg and radius of 0.2 m is filled with air (density = 1.29 kg/m3) and placed under water. a) What is the net force on the ball? b) What is the acceleration of the ball? Physics 1B03summer-Lecture 12

  8. Example:How heavy a balloon can 100 litres of helium lift? (ρHe=0.18kg/m3) Physics 1B03summer-Lecture 12

  9. ExampleA 10-kg rock (density 2500 kg/m3) is suspended in a large bucket of water by a cord. What is the tension in the cord? tension = ? Physics 1B03summer-Lecture 12

  10. 10 min rest Physics 1B03summer-Lecture 12

  11. Fluid Dynamics • Equation of Continuity • Bernoulli’s equation and examples Physics 1B03summer-Lecture 12

  12. Fluid Dynamics • Approximations: • no viscosity (frictionless flow) • steady, “laminar” flow. If the flow is turbulent, mechanical energy is lost (converted to thermal energy). • “incompressible” fluid. Sufficiently accurate for gases if pressure differences are small. Physics 1B03summer-Lecture 12

  13. Streamlines • -the paths followed by particles in steady flow • velocity is parallel to the streamline • particles never cross streamlines; the streamlines mark out imaginary “tubes of flow” area A1 speed v1 area A2 speed v2 Physics 1B03summer-Lecture 12

  14. Equation of Continuity “Volume flow rate” (volume per unit time) = (cross-sectional area)  (linear velocity) “Mass flow rate” (mass per unit time) = (density)  (volume flow rate) So, if mass in = mass out, then rAv =mass flow rate=constant r1A1v1 =r2A2v2 or for steady flow. “Incompressible” fluids (density remains uniform): cancel out density to get A1v1 =A2v2 or Volume flow rate =constant Physics 1B03summer-Lecture 12

  15. A fluid if flowing through a pipe of 10mm radius at a velocity of 10m/s. How fast will it be flowing if the pipe narrows to 5mm in radius ? radius r2 = 5mm radius r1 = 10mm Physics 1B03summer-Lecture 12

  16. Bernoulli’s Equation: work and energy in fluids Conditions: steady flow, incompressible fluid. Look at energy balance along a streamline: Change in (kinetic energy/volume) + change in (potential energy/volume) = (net work by pressure)/volume then, or, Note: the above equation looks similar what we have seen before if we replace ρ by m. Physics 1B03summer-Lecture 12

  17. Examplea) What is the velocity of the water leaving the little hole b) How far (horizontally) from the hole does the water hit the ground? d h x Physics 1B03summer-Lecture 12

  18. Example What is the speed of the water leaving the hole in the tank? gauge pressure P0 h v Physics 1B03summer-Lecture 12

  19. Example Water moving at 10m/s through a 1m radius pipe at a pressure of 50kPa. It then falls 50m and goes into a 0.3m radius pipe. What is the water pressure at the bottom ? h Physics 1B03summer-Lecture 12

  20. Exam Tips + Course Evaluations Physics 1B03summer-Lecture 12

More Related