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Rules : Everyone must attempt to answer each question.PowerPoint Presentation

Rules : Everyone must attempt to answer each question.

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- Rules:
- Everyone must attempt to answer each question.
- Show your work on a separate sheet of paper.
- Keep track of your points.
- Winners receive prize.

continue

2) This object in freefall accelerates at 9.8 m/s/s. Every second the velocity changes by 9.8 m/s

continue

A ball rolls down an incline from rest. How far does it travel in 3 seconds if it accelerates at 5 m/s2?

Show Work for Credit

d = vit + ½ at2

d = 0 + ½ (5 m/s2) (3s)2

d = 22.5 m

continue

4) travel in 3 seconds if it accelerates at 5 m/sVavg = (Vf + Vi)/2

Vavg= (10m/s +25m/s)/2

Vavg = 17.5 m/s

continue

1) travel in 3 seconds if it accelerates at 5 m/s d = vit + ½ at2

-6m = ½ a (2.7s)2

a = 1.6 m/s/s down

continue

The acceleration of a projectile travel in 3 seconds if it accelerates at 5 m/s

is always 9.81 m/s2downward because the only force acting on the object is gravity.

continue

2) travel in 3 seconds if it accelerates at 5 m/sd = vit + ½ at2

-22m = ½ a (3.0s)2

a = 4.9 m/s/s down

continue

VERTICAL travel in 3 seconds if it accelerates at 5 m/s

d = vit + ½ at2

-45m = 0 + ½ (-9.81m/s2) t2

t = 3.0 s

HORIZONTAL

d = vit + ½ at2

d = (25 m/s)(3.0 s) + 0

d = 75 m

continue

Show Work for Credit

2) v vs. t graphs are always linear. travel in 3 seconds if it accelerates at 5 m/s

Slope = accel. =

-9.81 m/s2

continue

v travel in 3 seconds if it accelerates at 5 m/sf = vi + at

0 = 98 m/s + (-9.81m/s2)t

t = 10. s

continue

3) g = F travel in 3 seconds if it accelerates at 5 m/sg/m

continue

A travel in 3 seconds if it accelerates at 5 m/s

B

C

D

E

Which graph(s) depict an object that is accelerating?

DAILY DOUBLE

Select an amount of points you want to wager before going on to the question.

You can only wager up to as many points as you currently have

B and C only

continue

2) An object in equilibrium has an acceleration equal to zero.

continue

Newton’s 3 zero.rd Law: the forces are equal in magnitude, opposite in direction.

Fnail on hammer = - Fhammer on nail

continue

F zero.net = ma

Fapplied – Ffriction = 0

Fapplied= Ffriction

Fapplied= μFN = (0.05)(80kg x 9.81m/s2)

Fapplied= 40N

continue

(C) zero.If the net force is zero, the acceleration must also be zero.

The slope of the speed graph = accel. = 0.

Constant speed = constant slope of distance graph.

continue

Show Work for Credit zero.

Fnet = ma

Fapplied – Ffriction = 0

Fapplied = Ffriction

Fapplied= μFN = (0.67)(60 N)

Fapplied= 40N

continue

F zero.net = ma = 0

F – Ffriction– Fparallel = 0

F = Ffriction+ Fparallel

F = Ffriction + Fg sinθ

F = 3N + (10N)sin30°

F= 3N + 5N

F= 8N

continue

List zero.3 scalar quantities and 3 vector quantities. Include units.

DAILY DOUBLE

Select an amount of points you want to wager before going on to the question.

You can only wager up to as many points as you currently have

Scalar: distance (m), speed (m/s), mass (kg), time (s),temp (°C)

Vector: displacement (m), velocity (m/s), acceleration (m/s2), Force (N), impulse (N·s), momentum (kg·m/s)

continue

(4) zero.Arrange 30N vectors to be head-to-tail, resultant starts at the tail of the first and ends at the head of the last.

30N

30N

R

continue

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