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Rules : Everyone must attempt to answer each question. Show your work on a separate sheet of paper. Keep track of your points. Winners receive prize. continue. Go BACK. You need to click on a number to proceed to the questions. Click here. continue. Really!!

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slide1

Rules:

  • Everyone must attempt to answer each question.
  • Show your work on a separate sheet of paper.
  • Keep track of your points.
  • Winners receive prize.

continue

slide4

Really!!

Go BACK. You need to click on a number to proceed to the questions.

Click here

continue

slide6

Displacement = 27.4m + 3m -3m

Distance = 27.4m + 3m +3m

continue

slide7

2) This object in freefall accelerates at 9.8 m/s/s. Every second the velocity changes by 9.8 m/s

continue

slide8

A ball rolls down an incline from rest. How far does it travel in 3 seconds if it accelerates at 5 m/s2?

Show Work for Credit

d = vit + ½ at2

d = 0 + ½ (5 m/s2) (3s)2

d = 22.5 m

continue

slide9

4) Vavg = (Vf + Vi)/2

Vavg= (10m/s +25m/s)/2

Vavg = 17.5 m/s

continue

slide10

1) d = vit + ½ at2

-6m = ½ a (2.7s)2

a = 1.6 m/s/s down

continue

slide11

The acceleration of a projectile

is always 9.81 m/s2downward because the only force acting on the object is gravity.

continue

slide12

2)d = vit + ½ at2

-22m = ½ a (3.0s)2

a = 4.9 m/s/s down

continue

slide13

VERTICAL

d = vit + ½ at2

-45m = 0 + ½ (-9.81m/s2) t2

t = 3.0 s

HORIZONTAL

d = vit + ½ at2

d = (25 m/s)(3.0 s) + 0

d = 75 m

continue

Show Work for Credit

slide14

2) v vs. t graphs are always linear.

Slope = accel. =

-9.81 m/s2

continue

slide15

vf = vi + at

0 = 98 m/s + (-9.81m/s2)t

t = 10. s

continue

slide16

3) g = Fg/m

continue

slide17

Fnet = ma

12 N = (2kg+1kg)a

a = 4 m/s2

continue

slide18

A

B

C

D

E

Which graph(s) depict an object that is accelerating?

DAILY DOUBLE

Select an amount of points you want to wager before going on to the question.

You can only wager up to as many points as you currently have

B and C only

continue

slide20

Newton’s 3rd Law: the forces are equal in magnitude, opposite in direction.

Fnail on hammer = - Fhammer on nail

continue

slide21

Fnet = ma

50N – Ff = (4 kg)(10 m/s2)

Ff= 10N

continue

slide22

Fnet = ma

Fapplied – Ffriction = 0

Fapplied= Ffriction

Fapplied= μFN = (0.05)(80kg x 9.81m/s2)

Fapplied= 40N

continue

slide23

(C) If the net force is zero, the acceleration must also be zero.

The slope of the speed graph = accel. = 0.

Constant speed = constant slope of distance graph.

continue

slide24

Show Work for Credit

Fnet = ma

Fapplied – Ffriction = 0

Fapplied = Ffriction

Fapplied= μFN = (0.67)(60 N)

Fapplied= 40N

continue

slide25

Fnet = ma = 0

F – Ffriction– Fparallel = 0

F = Ffriction+ Fparallel

F = Ffriction + Fg sinθ

F = 3N + (10N)sin30°

F= 3N + 5N

F= 8N

continue

slide26

B

(4)

Add vectors head to tail

continue

slide27

List 3 scalar quantities and 3 vector quantities. Include units.

DAILY DOUBLE

Select an amount of points you want to wager before going on to the question.

You can only wager up to as many points as you currently have

Scalar: distance (m), speed (m/s), mass (kg), time (s),temp (°C)

Vector: displacement (m), velocity (m/s), acceleration (m/s2), Force (N), impulse (N·s), momentum (kg·m/s)

continue

slide28

(4)

FH = Fcosθ

FH =(24N)cos35°

FH = 20. N

FV= Fsinθ

FV=(24N)sin35°

FV= 14. N

continue

slide29

A

B

R

(1)

continue

slide30

(4) Arrange 30N vectors to be head-to-tail, resultant starts at the tail of the first and ends at the head of the last.

30N

30N

R

continue

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