Rules : Everyone must attempt to answer each question.

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Rules : Everyone must attempt to answer each question.

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Rules : Everyone must attempt to answer each question.

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- Rules:
- Everyone must attempt to answer each question.
- Show your work on a separate sheet of paper.
- Keep track of your points.
- Winners receive prize.

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Go BACK. You need to click on a number to proceed to the questions.

Click here

continue

Really!!

Go BACK. You need to click on a number to proceed to the questions.

Click here

continue

Displacement = 27.4m + 3m -3m

Distance = 27.4m + 3m +3m

continue

2) This object in freefall accelerates at 9.8 m/s/s. Every second the velocity changes by 9.8 m/s

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A ball rolls down an incline from rest. How far does it travel in 3 seconds if it accelerates at 5 m/s2?

Show Work for Credit

d = vit + ½ at2

d = 0 + ½ (5 m/s2) (3s)2

d = 22.5 m

continue

4) Vavg = (Vf + Vi)/2

Vavg= (10m/s +25m/s)/2

Vavg = 17.5 m/s

continue

1) d = vit + ½ at2

-6m = ½ a (2.7s)2

a = 1.6 m/s/s down

continue

The acceleration of a projectile

is always 9.81 m/s2downward because the only force acting on the object is gravity.

continue

2)d = vit + ½ at2

-22m = ½ a (3.0s)2

a = 4.9 m/s/s down

continue

VERTICAL

d = vit + ½ at2

-45m = 0 + ½ (-9.81m/s2) t2

t = 3.0 s

HORIZONTAL

d = vit + ½ at2

d = (25 m/s)(3.0 s) + 0

d = 75 m

continue

Show Work for Credit

2) v vs. t graphs are always linear.

Slope = accel. =

-9.81 m/s2

continue

vf = vi + at

0 = 98 m/s + (-9.81m/s2)t

t = 10. s

continue

3) g = Fg/m

continue

Fnet = ma

12 N = (2kg+1kg)a

a = 4 m/s2

continue

A

B

C

D

E

Which graph(s) depict an object that is accelerating?

DAILY DOUBLE

Select an amount of points you want to wager before going on to the question.

You can only wager up to as many points as you currently have

B and C only

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2) An object in equilibrium has an acceleration equal to zero.

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Newton’s 3rd Law: the forces are equal in magnitude, opposite in direction.

Fnail on hammer = - Fhammer on nail

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Fnet = ma

50N – Ff = (4 kg)(10 m/s2)

Ff= 10N

continue

Fnet = ma

Fapplied – Ffriction = 0

Fapplied= Ffriction

Fapplied= μFN = (0.05)(80kg x 9.81m/s2)

Fapplied= 40N

continue

(C) If the net force is zero, the acceleration must also be zero.

The slope of the speed graph = accel. = 0.

Constant speed = constant slope of distance graph.

continue

Show Work for Credit

Fnet = ma

Fapplied – Ffriction = 0

Fapplied = Ffriction

Fapplied= μFN = (0.67)(60 N)

Fapplied= 40N

continue

Fnet = ma = 0

F – Ffriction– Fparallel = 0

F = Ffriction+ Fparallel

F = Ffriction + Fg sinθ

F = 3N + (10N)sin30°

F= 3N + 5N

F= 8N

continue

B

(4)

Add vectors head to tail

continue

List 3 scalar quantities and 3 vector quantities. Include units.

DAILY DOUBLE

Select an amount of points you want to wager before going on to the question.

You can only wager up to as many points as you currently have

Scalar: distance (m), speed (m/s), mass (kg), time (s),temp (°C)

Vector: displacement (m), velocity (m/s), acceleration (m/s2), Force (N), impulse (N·s), momentum (kg·m/s)

continue

(4)

FH = Fcosθ

FH =(24N)cos35°

FH = 20. N

FV= Fsinθ

FV=(24N)sin35°

FV= 14. N

continue

A

B

R

(1)

continue

(4) Arrange 30N vectors to be head-to-tail, resultant starts at the tail of the first and ends at the head of the last.

30N

30N

R

continue