I.  Review Distribute (aka F.O.I.L.)
Sponsored Links
This presentation is the property of its rightful owner.
1 / 126

I. Review Distribute (aka F.O.I.L.) PowerPoint PPT Presentation


  • 88 Views
  • Uploaded on
  • Presentation posted in: General

I. Review Distribute (aka F.O.I.L.) II. Review Trial and Error III. Review Grouping III. Factoring Quadratics. I. Review Distribute (aka F.O.I.L.). ( x + 3 ) (x + 2 ). First. ( x + 3 ) (x + 2 ). x 2. First. Outside. ( x + 3 ) (x + 2 ). x 2 + 2x. First. Outside.

Download Presentation

I. Review Distribute (aka F.O.I.L.)

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Presentation Transcript


I. Review Distribute (aka F.O.I.L.)II. Review Trial and ErrorIII. Review GroupingIII. Factoring Quadratics


I. Review Distribute (aka F.O.I.L.)


( x + 3 ) (x + 2 )


First

( x + 3 ) (x + 2 )

x2


First

Outside

( x + 3 ) (x + 2 )

x2+ 2x


First

Outside

( x + 3 ) (x + 2 )

Inside

x2+ 2x + 3x


First

Outside

( x + 3 ) (x + 2 )

Inside

Last

x2+ 2x + 3x + 6


First

Outside

( x + 3 ) (x + 2 )

Inside

Last

x2+ 2x + 3x + 6

x2+ 5x + 6


( 3x + 2 ) (2x + 1 )


First

( 3x + 2 ) (2x + 1 )

6x2


First

Outside

( 3x + 2 ) (2x + 1 )

6x2+ 3x


First

Outside

( 3x + 2 ) (2x + 1 )

Inside

6x2+ 3x + 4x


First

Outside

( 3x + 2 ) (2x + 1 )

Inside

Last

6x2+ 3x + 4x + 2


First

Outside

( 3x + 2 ) (2x + 1 )

Inside

Last

6x2+ 3x + 4x+ 2

6x2+ 7x + 2


II. Review Trial and Error


Factoring Steps for Trial and Error

x2 + 5x + 6


Factoring Steps for Trial and Error

x2 + 5x + 6

1x2 + 5x + 6


Factoring Steps for Trial and Error

x2 + 5x + 6

1x2 + 5x + 6

(1x ____ ) (1x ____ )


Factoring Steps for Trial and Error

x2 + 5x + 6

1x2 + 5x + 6

(1x – 1) (1x + 6 )


Factoring Steps for Trial and Error

x2 + 5x + 6

1x2 + 5x + 6

(1x – 1) (1x + 6 ) F.O.I.L. to check answer


Factoring Steps for Trial and Error

x2 + 5x + 6

1x2 + 5x + 6

(1x – 1) (1x + 6 )F.O.I.L. to check answer

(1x – 1) (1x + 6 ) = x2 + 5x – 6Error, Try Again


Factoring Steps for Trial and Error

x2 + 5x + 6


Factoring Steps for Trial and Error

x2 + 5x + 6

1x2 + 5x + 6


Factoring Steps for Trial and Error

x2 + 5x + 6

1x2 + 5x + 6

(1x + 2) (1x + 3) F.O.I.L. to check answer


Factoring Steps for Trial and Error

x2 + 5x + 6

1x2 + 5x + 6

(1x + 2) (1x + 3) F.O.I.L. to check answer

(x + 2) (x + 3) = x2 + 5x + 6 Correct!


Factoring Steps for Trial and Error

3x2 – 4x – 4


Factoring Steps for Trial and Error

3x2 – 4x – 4

(3x + 1) (1x – 4 ) F.O.I.L. to check answer


Factoring Steps for Trial and Error

3x2 – 4x – 4

(3x + 1) (1x – 4 ) F.O.I.L. to check answer

(3x + 1) (1x – 4) = 3x2 – 11x – 4 Error, Try Again


Factoring Steps for Trial and Error

3x2 – 4x – 4


Factoring Steps for Trial and Error

3x2 – 4x – 4

(3x – 1) (1x + 4) F.O.I.L. to check answer


Factoring Steps for Trial and Error

3x2 – 4x – 4

(3x – 1) (1x + 4) F.O.I.L. to check answer

(3x – 1) (1x + 4) = 3x2 + 11x – 4 Error, Try Again


Factoring Steps for Trial and Error

3x2 – 4x – 4


Factoring Steps for Trial and Error

3x2 – 4x – 4

(3x + 2) (1x – 2 ) F.O.I.L. to check answer


Factoring Steps for Trial and Error

3x2 – 4x – 4

(3x + 2) (1x – 2 ) F.O.I.L. to check answer

(3x + 2) (1x – 2) = 3x2 – 4x – 4 Correct!


Factoring Steps for Trial and Error

– 6x2 – x + 2


Factoring Steps for Trial and Error

– 6x2 – x + 2

Wow! How are we going to factor this??


Factoring Steps for Trial and Error

– 6x2 – x + 2

Wow! How are we going to factor this??

Well, let’s try another method and see if that

will help with this problem.

We can try Factoring by Grouping.


III. Factoring by Grouping


Factoring Steps for Grouping

x2 + 5x + 6


Factoring Steps for Grouping

x2 + 5x + 6

x2 + 2x + 3x + 6


Factoring Steps for Grouping

x2 + 5x + 6

x2 + 2x + 3x + 6

x2 + 2x + 3x + 6


Factoring Steps for Grouping

x2 + 5x + 6

x2 + 2x + 3x + 6

x2 + 2x + 3x + 6

x(x + 2) +3(x + 2)


Factoring Steps for Grouping

x2 + 5x + 6

x2 + 2x + 3x + 6

x2 + 2x + 3x + 6

x(x + 2) +3(x + 2)

(x + 2) (x + 3)


Factoring Steps for Grouping

3x2 – 4x – 4


Factoring Steps for Grouping

3x2 – 4x – 4

3x2 – 6x + 2x – 4


Factoring Steps for Grouping

3x2 – 4x – 4

3x2 – 6x + 2x – 4

3x2 – 6x + 2x – 4


Factoring Steps for Grouping

3x2 – 4x – 4

3x2 – 6x + 2x – 4

3x2 – 6x + 2x – 4

3x(x – 2) 2(x – 2)


Factoring Steps for Grouping

3x2 – 4x – 4

3x2 – 6x + 2x – 4

3x2 – 6x + 2x – 4

3x(x – 2) + 2(x – 2)

(x – 2) (3x + 2)


Factoring Steps for Grouping

3x2 – 4x – 4

3x2 – 6x + 2x – 4

3x2 – 6x + 2x – 4

3x(x – 2) 2(x – 2)

(x – 2) (3x + 2)

Or it can be factored this way . . .


Factoring Steps for Grouping

3x2 – 4x – 4


Factoring Steps for Grouping

3x2 – 4x – 4

3x2 + 2x – 6x – 4


Factoring Steps for Grouping

3x2 – 4x – 4

3x2 + 2x – 6x – 4

3x2 + 2x – 6x – 4


Factoring Steps for Grouping

3x2 – 4x – 4

3x2 + 2x – 6x – 4

3x2 + 2x – 6x – 4

x(3x + 2) – 2(3x + 2)


Factoring Steps for Grouping

3x2 – 4x – 4

3x2 + 2x – 6x – 4

3x2 + 2x – 6x – 4

x(3x + 2) – 2(3x + 2)

(3x + 2) (x – 2)


Factoring Steps for Grouping

– 6x2 – x + 2


Factoring Steps for Grouping

– 6x2 – x + 2

Oh, we are back to this problem again!


Factoring Steps for Grouping

– 6x2 – x + 2

Oh, we are back to this problem again!

Do you think Trial & Error or Grouping

will work easily on this problem?


Factoring Steps for Grouping

– 6x2 – x + 2

If you don’t think so, most people would agree with you.

What if I told you there was a different way that would work for the simple problems as well

as for problems like the one above?


Factoring Steps for Grouping

– 6x2 – x + 2

Well, let’s try the “Front times the Back” Method!!


IV. Factoring Quadratics


Factoring Steps

1A. Factor out GCF, if necessary.

1B. Make x2 term positive, if necessary.

• Carry the GCF and / or – sign and put in front of ( ) ( ) in answer.


Factoring Steps

Do “Front times the Back” and get an answer.

“Front times the Back” means to multiply coefficient

of the x2 term (NUMBER ONLY NOT SIGN)

and the constant (NUMBER ONLY NOT SIGN).


Factoring Steps

3. Find the factors of the “Front times the Back’s”

answer that will add or subtract

to equal the middle term.


When these factors are multiplied,

the sign of that answer

must equal the

sign of the constant.

This step is very important because it

will eliminate the extraneous (extra) solutions.


5A. Separate the x2 into x • x.

5B. Write one x in the front of each ( )( ).

5C. Then write the factors in the back of each ( )( ).

example of answer:

(x + 3) (x + 5)


Divide only the numbers in the ( )( )

by the positive coefficient of x2.

Divide out common terms.

(aka: Simplify fractions.)


If there is a whole # left, that ( ) is finished.

If there is a fraction left, the denominator becomes the coefficient of x and the numerator is now the constant in the ( ).

Example: (x + 2) (x + ¾)

(x+2) ( 4x + 3) = answer

This is now in factored form.


TO SOLVE FOR X:

Set each ( ) equal to 0 and solve for x.

Example: (x + 3) ( x + 5) = 0

x + 3 = 0x + 5 = 0

x = 0 – 3 x = 0 – 5

x = – 3 x = – 5

If x equals – 3 or – 5, then at least one factor will be equal to 0 which will cause the left side to be 0. So 0 = 0 is true and the answer is x = {-3, -5}.


Now let’s try some . . .


Actual Work ShownMental Work

x2+ 5x + 6


Actual Work ShownMental Work

1x2+ 5x + 6


Actual Work ShownMental Work

1x2+ 5x + 6

Step 1: No GCF


Actual Work ShownMental Work

1x2+ 5x + 6

Step 1: No GCF

Step 2:

1 * 6 = 6

1 * 6

2 * 3


Actual Work ShownMental Work

1x2+ 5x + 6

Step 1: No GCF

Step 2:Step 3:

1 * 6 = 6+ 6+3

1 * 6 – 1+2

2 * 3+ 5+5


Actual Work ShownMental Work

1x2+ 5x + 6

Step 1: No GCF

Step 2:Step 3:

1 * 6 = 6+ 6+3

1 * 6 – 1+2

2 * 3+ 5+5

Even though there are two ways to get +5, only one set of factors will work.


Actual Work ShownMental Work

1x2+ 5x + 6

Step 1: No GCF

Step 2:Step 3:

1 * 6 = 6+ 6+3

1 * 6 – 1+2

2 * 3+ 5+5

Even though there are two ways to get +5, only one set of factors will work.

Step 4:

(+6)(–1) = – #

(+3)(+2) = + #, and the last term is a + #, so only the +3 and the +2 will work.


Actual Work ShownMental Work

1x2+ 5x + 6

Step 1: No GCF

Step 5: (x + 2) (x + 3)

Step 2:Step 3:

1 * 6 = 6+ 6+3

1 * 6 – 1+2

2 * 3+ 5+5

Even though there are two ways to get +5, only one set of factors will work.

Step 4:

(+6)(–1) = – #

(+3)(+2) = + #, and the last term is a + #, so only the +3 and the +2 will work.


Actual Work ShownMental Work

1x2+ 5x + 6

Step 1: No GCF

Step 5: (x + 2) (x + 3)

Step 6: (x + 2) (x + 3)

1 1

Step 2:Step 3:

1 * 6 = 6+ 6+3

1 * 6 – 1+2

2 * 3+ 5+5

Even though there are two ways to get +5, only one set of factors will work.

Step 4:

(+6)(–1) = – #

(+3)(+2) = + #, and the last term is a + #, so only the +3 and the +2 will work.


Actual Work ShownMental Work

1x2+ 5x + 6

Step 1: No GCF

Step 5: (x + 2) (x + 3)

Step 6: (x + 2) (x + 3)

1 1

Step 7-9: (x + 2) (x + 3)

Step 2:Step 3:

1 * 6 = 6+ 6+3

1 * 6 – 1+2

2 * 3+ 5+5

Even though there are two ways to get +5, only one set of factors will work.

Step 4:

(+6)(–1) = – #

(+3)(+2) = + #, and the last term is a + #, so only the +3 and the +2 will work.


To Solve for x:

(x + 2) (x + 3) = 0

x + 2 = 0 x + 3 = 0

x = 0 – 2 x = 0 – 3

x = – 2 x = – 3

x = {– 2, – 3}


Actual Work ShownMental Work

x2 – 5x – 6


Actual Work ShownMental Work

1x2 – 5x – 6


Actual Work ShownMental Work

1x2 – 5x – 6

Step 1: No GCF


Actual Work ShownMental Work

1x2 – 5x – 6

Step 1: No GCF

Step 2:

1 * 6 = 6

1 * 6

2 * 3


Actual Work ShownMental Work

1x2 – 5x – 6

Step 1: No GCF

Step 2:Step 3:

1 * 6 = 6– 6 – 3

1 * 6 + 1– 2

2 * 3– 5 – 5

Even though there are two ways to get – 5, only one set of factors will work.


Actual Work ShownMental Work

1x2 – 5x – 6

Step 1: No GCF

Step 2:Step 3:

1 * 6 = 6– 6 – 3

1 * 6 + 1– 2

2 * 3– 5 – 5

Even though there are two ways to get – 5, only one set of factors will work.

Step 4:

(– 6)(+ 1) = – #

(– 3)(– 2) = + #, and the last term is a – #, so only the – 6 and the + 1 will work.


Actual Work ShownMental Work

1x2 – 5x – 6

Step 1: No GCF

Step 5: (x – 6) (x + 1)

Step 2:Step 3:

1 * 6 = 6– 6 – 3

1 * 6 + 1– 2

2 * 3– 5 – 5

Even though there are two ways to get – 5, only one set of factors will work.

Step 4:

(– 6)(+ 1) = – #

(– 3)(– 2) = + #, and the last term is a – #, so only the – 6 and the + 1 will work.


Actual Work ShownMental Work

1x2 – 5x – 6

Step 1: No GCF

Step 5: (x – 6) (x + 1)

Step 6: (x – 6) (x + 1)

1 1

Step 2:Step 3:

1 * 6 = 6– 6 – 3

1 * 6 + 1– 2

2 * 3– 5 – 5

Even though there are two ways to get – 5, only one set of factors will work.

Step 4:

(– 6)(+ 1) = – #

(– 3)(– 2) = + #, and the last term is a – #, so only the – 6 and the + 1 will work.


Actual Work ShownMental Work

1x2 – 5x – 6

Step 1: No GCF

Step 5: (x – 6) (x + 1)

Step 6: (x – 6) (x + 1)

1 1

Step 7-9:(x – 6) (x + 1)

Step 2:Step 3:

1 * 6 = 6– 6 – 3

1 * 6 + 1– 2

2 * 3– 5 – 5

Even though there are two ways to get – 5, only one set of factors will work.

Step 4:

(– 6)(+ 1) = – #

(– 3)(– 2) = + #, and the last term is a – #, so only the – 6 and the + 1 will work.


To Solve for x:

(x – 6) (x + 1) = 0

x – 6 = 0 x + 1 = 0

x = 0 + 6 x = 0 – 1

x = + 6 x = – 1

x = {+ 6, – 1}


Actual Work ShownMental Work

2x2 + 7x – 4


Actual Work ShownMental Work

2x2 + 7x – 4

Step 1: No GCF


Actual Work ShownMental Work

2x2 + 7x – 4

Step 1: No GCF

Step 2:

2 * 4 = 8

1 * 8

2 * 4


Actual Work ShownMental Work

2x2 + 7x – 4

Step 1: No GCF

Step 2:Step 3:

2 * 4 = 8 + 8

1 * 8 – 1

2 * 4 + 7


Actual Work ShownMental Work

2x2 + 7x – 4

Step 1: No GCF

Step 2:Step 3:

2 * 4 = 8 + 8

1 * 8 – 1

2 * 4 + 7

Step 4:

Only the +8 added to the – 1 will equal +7.

And since (+ 8)(– 1) = – # , this verifies these are the two factors needed.


Actual Work ShownMental Work

2x2 + 7x – 4

Step 1: No GCF

Step 5: (x + 8) (x – 1)

Step 2:Step 3:

2 * 4 = 8 + 8

1 * 8 – 1

2 * 4 + 7

Step 4:

Only the +8 added to the – 1 will equal +7.

And since (+ 8)(– 1) = – # , this verifies these are the two factors needed.


Actual Work ShownMental Work

2x2 + 7x – 4

Step 1: No GCF

Step 5: (x + 8) (x – 1)

Step 6: (x + 8) (x – 1)

2 2

Step 2:Step 3:

2 * 4 = 8 + 8

1 * 8 – 1

2 * 4 + 7

Step 4:

Only the +8 added to the – 1 will equal +7.

And since (+ 8)(– 1) = – # , this verifies these are the two factors needed.


Actual Work ShownMental Work

2x2 + 7x – 4

Step 1: No GCF

Step 5: (x + 8) (x – 1)

Step 6: (x + 8) (x – 1)

2 2

Step 7-9: (x + 4) (2x – 1)

Step 2:Step 3:

2 * 4 = 8 + 8

1 * 8 – 1

2 * 4 + 7

Step 4:

Only the +8 added to the – 1 will equal +7.

And since (+ 8)(– 1) = – # , this verifies these are the two factors needed.


To Solve for x:

(x + 4) (2x – 1)

x + 4 = 0 2x – 1= 0

x = 0 – 4 2x = 0 + 1

x = – 4 2x = 1

x = ½

x = { – 4, ½ }


Now here are some

practice problems. . .


x2 + 4x + 3


x2 + 4x + 3

Step 1: No GCF

Step 2: “Front times the Back”

Step 3A: What factors of 3 add to = +4? AND

Step 3B: Do signs multiply to equal a + #?


x2 + 4x + 3

x2+3x +1x + 3


  • x2 + 4x + 3

  • x2+3x +1x + 3

  • Now separate the x2 into x • x

  • Put each x into ( ) ( )

  • Put the two red #s into ( ) ( )


1x2 + 4x + 3

x2+3x +1x + 3

( x +3) ( x +1)

Now, divide by the coefficient of x2.


1x2 + 4x + 3

x2+3x +1x + 3

( x +3) ( x +1)

1 1


1x2 + 4x + 3

x2+3x +1x + 3

( x +3) ( x +1)

1 1

Since dividing by 1 does not change the numbers, we have discovered that if the coefficient of x2 is 1, then we can eliminate the dividing by the x2 coefficient step.


Therefore,

the Factored Form of

x2 + 4x + 3

is (x+3) (x+1).


Now, let’s try another problem.


3x2 - 4x – 4


3x2 - 4x – 4

(x + 2) (x – 6)


3x2 - 4x – 4

(x + 2) (x – 6)

(x + 2) (x – 6)

3 3


3x2 - 4x – 4

(x + 2) (x – 6)

(x + 2) (x – 6)

3 3

(3x + 2) (x – 2)


3x2 - 4x – 4

(x + 2) (x – 6)

(x + 2) (x – 6)

3 3

(3x + 2) (x – 2)

You are now ready for

The Problem ! ! ! ! !


Actual Work ShownMental Work

– 6x2 – x + 2


Actual Work ShownMental Work

– 6x2 – x + 2

Step 1A: No GCF


Actual Work ShownMental Work

– 6x2 – x + 2

Step 1A: No GCF

Step 1B: – 1(6x2 + x – 2)


Actual Work ShownMental Work

– 6x2 – x + 2

Step 1A: No GCF

Step 1B: – 1(6x2 + x – 2)

Step 2:

6 * 2 = 12

1 * 12

2 * 6

  3 * 4


Actual Work ShownMental Work

– 6x2 – x + 2

Step 1A: No GCF

Step 1B: – 1(6x2 + x – 2)

Step 2:Step 3:

6 * 2 = 12 + 4

1 * 12 – 3

2 * 6 + 1

  3 * 4


Actual Work ShownMental Work

– 6x2 – x + 2

Step 1A: No GCF

Step 1B: – 1(6x2 + x – 2)

Step 2:Step 3:

6 * 2 = 12 + 4

1 * 12 – 3

2 * 6 + 1

  3 * 4

Step 4:

Only the +4 added to the – 3 will equal +1.

And since (+ 4)(– 3) = – # , this verifies these are the two factors needed.


Actual Work ShownMental Work

– 6x2 – x + 2

Step 1A: No GCF

Step 1B: – 1(6x2 + x – 2)

Step 5: – 1 (x + 4) (x – 3)

Step 2:Step 3:

6 * 2 = 12 + 4

1 * 12 – 3

2 * 6 + 1

  3 * 4

Step 4:

Only the +4 added to the – 3 will equal +1.

And since (+ 4)(– 3) = – # , this verifies these are the two factors needed.


Actual Work ShownMental Work

– 6x2 – x + 2

Step 1A: No GCF

Step 1B: – 1(6x2 + x – 2)

Step 5: – 1 (x + 4) (x – 3)

Step 6: – 1 (x + 4) (x – 3)

2 2

Step 2:Step 3:

6 * 2 = 12 + 4

1 * 12 – 3

2 * 6 + 1

  3 * 4

Step 4:

Only the +4 added to the – 3 will equal +1.

And since (+ 4)(– 3) = – # , this verifies these are the two factors needed.


Actual Work ShownMental Work

– 6x2 – x + 2

Step 1A: No GCF

Step 1B: – 1(6x2 + x – 2)

Step 5: – 1 (x + 4) (x – 3)

Step 6: – 1 (x + 4) (x – 3)

6 6

Step 7-9: – 1(3x + 2) (2x – 1)

Step 2:Step 3:

6 * 2 = 12 + 4

1 * 12 – 3

2 * 6 + 1

  3 * 4

Step 4:

Only the +4 added to the – 3 will equal +1.

And since (+ 4)(– 3) = – # , this verifies these are the two factors needed.


Now try these problems . . .

(you may use GeoGebra).

x2 + 4x + 3

x2 + 7x + 6

x2 + 9x + 8

x2 + 10x + 9

x2 + 2x − 3

x2 + 5x − 6

x2 + 7x − 8

x2 + 8x − 9


The problems on this page and the next can be used as extra practice or as homework.

x2 − 2x − 3

x2 − 5x − 6

x2 − 7x − 8

x2 − 8x − 9

x2 − 4x + 3

x2 − 7x + 6

x2 − 9x + 8

x2 − 10x + 9


x2 + 4x + 3

x2 + 7x + 6

x2 + 9x + 8

x2 + 10x + 9

x2 + 2x − 3

x2 + 5x − 6

x2 + 7x − 8

x2 + 8x − 9

x2 − 2x − 3

x2 − 5x − 6

x2 − 7x − 8

x2 − 8x − 9

x2 − 4x + 3

x2 − 7x + 6

x2 − 9x + 8

x2 − 10x + 9


  • Login