Loading in 5 sec....

Electrostatics – Coulomb’s LawPowerPoint Presentation

Electrostatics – Coulomb’s Law

- 119 Views
- Uploaded on

Download Presentation
## PowerPoint Slideshow about ' Electrostatics – Coulomb’s Law' - fallon

**An Image/Link below is provided (as is) to download presentation**

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Presentation Transcript

Tues / Wed Read Chapter 20 pp. 461-470

Homework: p. 477 1-3, 9-12

Wed/Thurs Do problems p. 478 20, 21, 22, 24, 25, 27

Thurs/Fri p. 478 28, 29, 30, 31, 32

Thurs / Fri Lab

Fri / Mon Homework: Read ch 21 pages 481-487

Do p. 502 23, 24, 26, 27, 28, 30, 31

Mon / Tues Homework: Read 488-501

Do 32, 33, 34, 42, 43, 47

_

+

+

_

_

+

+

_

_

_

+

+

+

_

_

_

+

+

+

_

_

+

_

_

+

_

+

+

_

_

+

+

_

+

_

+

F 1/r2

r

Coulomb’s Law- Charles Coulomb discovered that the repulsive force due to similar charges or the attractive force of dissimilar charges was inversely proportional to the square of the distance between the two charged bodies.

_

+

+

_

_

+

+

_

_

_

+

+

+

_

_

_

+

+

+

_

_

+

_

_

+

_

+

+

_

_

+

+

_

+

_

+

Coulomb’s Law- Coulomb further discovered that the force was proportional to the product of the charge on each of the objects.

q1

q2

F q1q2

Sphere 1

Sphere 2

F = kq1q2

r2

Coulomb’s Law- Where:
- k = 8.99 x 109 N•m2/C2
- q1, q2 = the charge of each sphere in Coulombs.
- r = the distance between the two charged bodies.
- Applet 1 - Coulomb's Law
- Applet II - Coulomb's Law

Example 1:

Two point charges,

q1 = 1C

q2 = 2C

are separated by 1 m. What is the force between them?

F = kq1q2 / r2

= (8.99E9N*m2/C2)(1C)(2C)/(1m) 2

= 1.8E10N

Where:

k = 8.99 x 109 N•m2/C2

q1, q2 = the charge of each sphere in Coulombs.

r = the distance between the two charged bodies.

Example 2:

Two point charges,

q1 = 1C

q2 = -2C

are separated by 1 m. What is the force between them?

F = kq1q2 / r2

= (8.99E9N*m2/C2)(1C)(2C)/(1m) 2

= -1.8E10N

Where:

k = 8.99 x 109 N•m2/C2

q1, q2 = the charge of each sphere in Coulombs.

r = the distance between the two charged bodies.

Example 3:

Two point charges,

q1 = 1E-19C

q2 = -2E-19C

are separated by 1E-10 m. What is the force between them?

F = kq1q2 / r2

= (8.99E9N*m2/C2)(1E-19C)(-2E-19C)/(1E-10m) 2

= -1.798E-8N

Where:

k = 8.99 x 109 N•m2/C2

q1, q2 = the charge of each sphere in Coulombs.

r = the distance between the two charged bodies.

Example 4:

At what distance does the electrostatic force between two protons equal 899N?

F = kq1q2 / r2 kq1q2 / F = r2

(8.99E9)(1.6E-19)2 / 899 = (2.56E-31) r= 5.05E-16

Where:

k = 8.99 x 109 N•m2/C2

q1, q2 = the charge of each sphere in Coulombs.

r = the distance between the two charged bodies.

Graphs (oh, no, not again.)

- Graph of F vs. r?
- Graph of F vs. q1q2?

Key Ideas

- Like charges repel.
- The electrostatic force is proportional to the charge on the two objects and inversely proportional to the square of the distance between them.

Download Presentation

Connecting to Server..