1 / 15

Chapter 10 Circles

U SING P ROPERTIES OF I NSCRIBED P OLYGONS. U SING I NSCRIBED A NGLES. Chapter 10 Circles. Section 10.3 Inscribed Angles. U SING I NSCRIBED A NGLES. inscribed angle. intercepted arc.

Download Presentation

Chapter 10 Circles

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. USING PROPERTIES OF INSCRIBED POLYGONS USING INSCRIBED ANGLES Chapter 10Circles Section 10.3 Inscribed Angles

  2. USING INSCRIBED ANGLES inscribed angle intercepted arc An inscribed angle is an angle whose vertex is on a circle and whose sides contain chords of the circle. The arc that lies in the interior of an inscribed angle and has endpoints on the angle is called the intercepted arc of the angle.

  3. USING INSCRIBED ANGLES THEOREM A 1 2 mADB= mAB C D B mAB= 2mADB THEOREM 10.8 Measure of an Inscribed Angle If an angle is inscribed in a circle, then its measure is half the measure of its intercepted arc.

  4. Finding Measures of Arcs and Inscribed Angles W N R S C C Z C M 115° X Q T P Y mQTS = 2mQRS = 2(90°) = 180° 1 2 1 2 mZWX = 2mZYX = 2(115°) = 230° M NMP = mNP = (100°) = 50° Find the measure of the blue arc or angle. 100° SOLUTION

  5. USING INSCRIBED ANGLES THEOREM A B C D C D THEOREM 10.9 If two inscribed angles of a circle intercept the same arc, then the angles are congruent.

  6. Using the Measure of an Inscribed Angle THEATERDESIGN When you go to the movies, you want to be close to the movie screen, but you don’t want to have to move your eyes too much to see the edges of the picture. If E and G are the ends of the screen and you are at F, mEFG is called your viewing angle. E G movie screen F You decide that the middle of the sixth row has the best viewing angle. If someone is sitting there, where else can you sit to have the same viewing angle?

  7. Using the Measure of an Inscribed Angle SOLUTION Draw the circle that is determined by the endpoints of the screen and the sixth row center seat. Any other location on the circle will have the same viewing angle.

  8. USING PROPERTIES OF INSCRIBED POLYGONS If all of the vertices of a polygon lie on a circle, the polygon is inscribed in the circle and the circle is circumscribed about the polygon. The polygon is an inscribed polygon and the circle is a circumscribed circle.

  9. USING PROPERTIES OF INSCRIBED POLYGONS A B C B is a right angle if and only if AC is a diameter of the circle. THEOREMS ABOUT INSCRIBED POLYGONS THEOREM 10.10 If a right triangle is inscribed in a circle, then the hypotenuse is a diameter of the circle. Conversely, if one side of an inscribed triangle is a diameter of the circle, then the triangle is a right triangle and the angle opposite the diameter is the right angle.

  10. USING PROPERTIES OF INSCRIBED PLOYGONS THEOREMS ABOUT INSCRIBED POLYGONS F E C D G D, E, F, and G lie on some circle, C, if and only if m D + m F = 180° and m E + m G = 180°. . THEOREM 10.11 A quadrilateral can be inscribed in a circle if and only if its opposite angles are supplementary.

  11. Using an Inscribed Quadrilateral A 2y° In the diagram, ABCD is inscribed in P. Find the measure of each angle. P 3y° D B 3x° 5x° C .

  12. Using an Inscribed Quadrilateral A 2y° P 3y° D B 3x° 5x° C SOLUTION ABCD is inscribed in a circle, so opposite angles are supplementary. 3x + 3y = 180 5x + 2y = 180

  13. Using an Inscribed Quadrilateral A 3x + 3y = 180 5x + 2y = 180 2y° P 3y° D B 3x° 5x° C To solve this system of linear equations, you can solve the first equation for y to get y = 60 – x. Substitute this expression into the second equation. 5x + 2y = 180 Write second equation. 5x + 2(60 – x) = 180 Substitute 60 – x for y. 5x + 120 – 2x = 180 Distributive property 3x = 60 Subtract 120 from each side. x = 20 Divide each side by 3. y = 60 – 20 = 40 Substitute and solve for y.

  14. Using an Inscribed Quadrilateral A 2y° P 3y° D B 3x° m C = 100°, andm D = 120°. 5x° som A = 80°, m B = 60°, C x = 20 andy = 40,

  15. HW #38Pg 617 9-29

More Related