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Тема : Масова частка елементів у речовині PowerPoint PPT Presentation


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Тема : Масова частка елементів у речовині. Мета:.

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Тема : Масова частка елементів у речовині

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4905753

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  • : PbO, BaSO4, KCl, AgNO3.

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Mr(PbO)=207+16=223

Mr(BaSO4)= 137+32+164=233

Mr(KCl)=39+35,5=74,5

Mr(AgNO3)=108+14+163=170

: 1 .

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CaO

Ar (Ca) = 40; Ar (O) = 16

m ( Ca) : m (O) = 40 : 16 = 10 : 4 = 5: 2

, .

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Ag2O

Ar ( Ag) = 108; Ar ( O) = 16;

m ( Ag) : m (O) = 216 : 16 = 108 : 8 = 27 : 2

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Kno 3

KNO3.

Ar ( K) = 39: Ar ( N) = 14:

Ar ( O) = 16

m (K) : m ( N) : m(O) = 39 : 14 : 48

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SO3, CaCO3.

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m( S): m(O) =32: 163=32 :48 =16:24=2:3

m (Ca):m(C):m (O)=40:12:48=10:3:12

: 1 . .

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100%,

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Mr (CaO) = 56 - 100%

Ar (Ca) = 40 x%

= 40 100% / 56 = 71, 4 %.

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  • W

  • ( )

  • n ;

  • Ar - ;

  • Mr .

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Na2O

Ar ( Na) = 23, Mr (Na2O) = 62

( ) = 100% - ( Na ) = 100% - 74% = 26%

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1 . 2.

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2Mr (CO2) = 12 + 32 = 44

( C ) - ?

( O ) - ?

: w ( C) = 27,3% ; w( O) = 72,7%

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2. .

ZnS, Ca3P2, Al4C3, CH4, Fe2O3

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Mr (ZnS) = 97 w ( Zn) = 67% , w ( S) = 33%

Mr (Ca3P2) = 182 w( Ca) = 66 %, w( P) = 34%

Mr (Al4C3 ) = 144 w( Al) = 75% w( C) = 25%

Mr (CH4) = 16 w( C) = 75% w( H) = 25%

Mr (Fe2O3) = 160 w( Fe) = 70% , w (O) = 30%

: 3 . .

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4,5,9,13(). ?

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