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Solving for  5 &  6

Solving for  5 &  6. For  5 : Select (1,3) & (2,3) terms S5 = C4U 13 + S4U 23 C5 = U 33 Tan( 5 ) = S5/C5 = (C4U 13 + S4U 23 )/U 33  5 = Atan2(U 33 , C4U 13 + S4U 23 ) For  6 : Select (3,1) & (3, 2) S6 = C4U 21 – S4U 11 C6 = C4U 22 – S4U 12

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Solving for  5 &  6

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  1. Solving for 5 & 6 • For 5: Select (1,3) & (2,3) terms • S5 = C4U13 + S4U23 • C5 = U33 • Tan(5) = S5/C5 = (C4U13 + S4U23)/U33 • 5 = Atan2(U33, C4U13 + S4U23) • For 6: Select (3,1) & (3, 2) • S6 = C4U21 – S4U11 • C6 = C4U22 – S4U12 • Tan(6) = S6/C6 = ([C4U21 – S4U11]/[C4U22 – S4U12]) • 6 = Atan2 ([C4U22 – S4U12], [C4U21 – S4U11])

  2. Summarizing: • 4 = Atan2(U13, U23) • 5 = Atan2(U33, C4U13 + S4U23) • 6 = Atan2 ([C4U22 – S4U12], [C4U21 – S4U11])

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