fch 532 lecture 16
Download
Skip this Video
Download Presentation
FCH 532 Lecture 16

Loading in 2 Seconds...

play fullscreen
1 / 45

FCH 532 Lecture 16 - PowerPoint PPT Presentation


  • 52 Views
  • Uploaded on

FCH 532 Lecture 16. Extra credit assignment for Friday March 2-Seminar Speaker Matt DeLisa, 3PM-4:30PM 148 Baker New Homework/Study Guide posted Chapter 31. Major classes of RNA. Ribosomal RNA (rRNA) Transfer RNA (tRNA) Messenger RNA (mRNA)

loader
I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.
capcha
Download Presentation

PowerPoint Slideshow about ' FCH 532 Lecture 16' - emery-waller


An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript
fch 532 lecture 16
FCH 532 Lecture 16

Extra credit assignment for Friday March 2-Seminar Speaker Matt DeLisa, 3PM-4:30PM 148 Baker

New Homework/Study Guide posted

Chapter 31

slide2

Major classes of RNA

  • Ribosomal RNA (rRNA)
  • Transfer RNA (tRNA)
  • Messenger RNA (mRNA)
  • The role that proteins are specified by mRNA and synthesized on ribosomes was defined by experiments in enzyme induction.
  • Enzyme induction is a consequence of mRNA synthesis by proteins that specfically bind to the mRNA’s DNA template.
slide3

Enzymes

  • Constitutive enzymes - enzymes that are involved in basic cellular housekeeping functions and are synthesized at a constant rate.
  • Adaptive/inducible enzymes-enzymes that are synthesized at rates that vary with the cell’s circumstances.
  • Example: lactose metabolizing enzymes conversion of lactose to galactose and D-glucose.
  • Two main proteins: -galactosidase-catalyzes the hydrolysis of lactose to galactose and glucose
  • Galactosidde permease (lactose permease)-transports lactose into the cell.
slide4

H

H

H

H

H

H

H

H

H

H

H

H

H

+

H

H

H

H

H

H

H

Enzymes

  • In the absence of lactose only a few molecules of -galactosidase or lactose permease.
  • Minutes after lactose introduced increased by ~1000-fold.
  • Lactose unavailable - returns to the basal level.
  • Metabolic product triggers the synthesis of proteins-inducer.
slide6

Inducers of the lac operon

  • Physiological inducer-lactose isomer 1,6-allolactose.
  • Results from transglycosylation of lactoase by -galactosidase
  • Most studies of lactose system use isopropylthiogalactoside (IPTG).
  • Potent inducer that is not degraded.

H

H

H

H

H

H

H

H

H

H

H

H

H

H

H

H

slide8

lac repressor inhibits synthesis of lac operon proteins

  • PaJaMo experiment-Hfr bacteria of genotype I+Z+ were mated to F- strain with a genotype I-Z- in the absence of inducer while -galactosidase activity was monitored.
  • At first, no -galactosidase activity because the Hfr donors lacked inducer and F- recipients were unable to to produce active enzyme.
  • After 1 h conjugation when the I+Z+ enter the F- cells -galactosidase began and ceased after another hour.
  • The donated Z+ gene entering the cytoplasm of the I- cell causes constitutive expression of the -galactosidase gene.
  • After the I+ gene is expressed (after 1 h) it represses -galactosidase synthesis.
  • I must be a diffusible product.
figure 31 6 the pajamo experiment
Figure 31-6 The PaJaMo experiment.

Page 1219

F- strain resistant to T6 phage and streptomycin.

slide11

Other constitutive mutations

  • Second type of constitutive mutation in the lactose system is OC - operator constitutive.
  • Independent of I gene-maps to space between I and Z genes.
  • In a partially diploid F’ strain OC Z-/F O+Z+, -galactosidase activity is inducible by IPTG.
  • In the strain OC Z+/F O+Z-, -galactosidase is constitutively produced.
slide12

Other constitutive mutations

  • An O sequence can only control expression of the Z gene on the same chromosome.
  • The structural genes on DNA are transcribed onto complementary strands of mRNA.
  • The mRNAs transiently associate with ribosomes, which they direct in polypeptide synthesis.

The lac repressor binds to the O sequence to prevent the transcription of mRNA. In an OCmutant, the repressor cannot bind to the sequence.

slide13

Other constitutive mutations

  • The simultaneous or coordinate expression of the lac enzymes under the control of a single operator indicates that the lac operon is transcribed as a single polycistronic mRNA
  • Cistron-gene
  • Control sequence that act only on the same DNA molecules as the genes they control are called cis-acting elements.
  • Agents of diffusible products can be on different DNA molecules. Trans-acting factors.
slide14

RNA polymerase

  • RNAP is the enzyme responsible for the DNA-directed synthesis of RNA.
  • Enzyme couples together the ribonucleoside triphosphates ATP, CTP, GTP, and UTP on DNA templates in a reaction driven by the release and hydrolysis of pyrophosphate.

(RNA)n residues+ NTP (RNA)n + 1 residues + PPi

  • RNAP holoenzyme (459 kD) ’.
  • Once RNA synthesis is initiated the subunit dissociates from the core enzyme ’which carries out the polymerization.
slide16

Figure 31-9 An electron micrograph of E. coli RNA polymerase (RNAP) holoenzyme attached to various promoter sites on bacteriophage T7 DNA.

Page 1222

slide17

RNA polymerase

  • (+) strand (sense strand) or coding strand-has the same sequence as the transcribed RNA.
  • (-) strand (antisense strand) acts as the template.
  • By convention, the sequence template DNA is repesented by its template (nontemplate strand) so that it will have the same directionality as the transcribed RNA.
  • RNAP holoenzyme binds to its initiation sites called promoters that are recognized by the corresponding  factor.
  • Promoters consist of ~40-bp sequence located 5’ to the transcription start site.
  • Holoenzyme forms tight complexes with promoters (K ~10-14 M)
slide18

Promoter sequences

  • In E. coli, most conserved sequence is a hexamer at about the -10 region (Pribnow box) of TATAAT.
  • Upstream sequence at -35 is also highly conserved, TTGACA.
  • Sequence unimportant between -35 and -10 but length is (16-19 bp).
  • Initiating nucleotide (+1) is always A or G.
  • Additional A+T rich sequence between -40 and -60 upstream promoter (UP) element binds to the C-terminal domain of RNAP’s  subunits.
  • Promoter mutations that increase or decrease the rate at which the associated gene is transcribed are called up mutations and down mutations.
slide20

Figure 31-11aX-Ray structure of Taq RNAP core enzyme. a subunits are yellow and green, b subunit is cyan, b¢ subunit is pink, w subunit is gray.

Page 1224

figure 31 11b x ray structure of taq rnap b the holoenzyme viewed as in part a
Figure 31-11b X-Ray structure of Taq RNAP. (b) The holoenzyme viewed as in Part a.

Page 1224

slide22
Figure 31-12a The sequence of a fork-junction promoter DNA fragment. Numbers are relative to the transcription start site, +1.

Page 1225

slide23
Figure 31-12b X-Ray structure of Taq holoenzyme in complex with a fork-junction promoter DNA fragment.

Page 1225

slide24
Figure 31-13aModel of the closed (RPc) complex of Taq RNAP with promoter-containing DNA extending between positions –60 and +25.

Page 1225

slide25

Figure 31-13bModel of the open (Rpo) complex of Taq RNAP with promoter-containing DNA showing the transcription bubble and the active site.

Page 1225

slide26

RNA polymerase

  • RNAP holoenzyme (459 kD) ’.
  • Crystal structure for Taq RNAP solved by Seth Darst.
  • Active site has a Mg2+ ion.
  • DNA template lies across one face of the enzyme outside the active site.
  • Open and closed complexes.
  • Closed complex has UP element contacts.
  • Open complex, template strand of transcription bubble is in a tunnel formed by the ’subunits lined with basic amino acids.
  • This tunnel leads to the active site.
slide27

Rifamycins inhibit prokaryotic RNAP

  • Two related antibiotics: rifamycin B and rifampicin
  • 2 X 10-8 M rifampicin inhibits 50% RNAP
  • Binds to the  subunit and prevents chain elongation.
slide28

Figure 31-14 The two possible modes of RNA chain growth. Growth may occur (a) by the addition of nucleotides to the 3¢ end and (b) by the addition of nucleotides to the 5¢ end.

Page 1226

slide29

Chain elongation proceeds in the 5’  3’ direction with RNAP

  • Experimentally proven with radiactively labelled [32-P]GTP.
  • For 5’  3’ elongation, the 5’ -P is permanently labeled so that the chain’s level of radioactivity does not change upon replacement of labeled GTP with unlabeled GTP.
  • For 3’  5’ elongation, the 5’ -P would be added with each nucleotide, so that on replacement of labeled GTP by unlabeled GTP, the RNA chains lose their radioactivity.
  • The 5’  3’ elongation is observed experimentally, therefore, chain elongation proceeds 5’  3’.
slide31

Figure 31-16 An electron micrograph of three contiguous ribosomal genes from oocytes of the salamander Pleurodeles waltl undergoing transcription.

Page 1228

slide32

RNA polymerase cannot proofread

  • Cannot rebind polynucleotide it has released.
  • Enzyme is processive.
  • No exonuclease activity.
  • Error rate is one wrong base for every ~104 transcribed.
  • DNA Pol I is one nt incorrect for every 107
  • RNAP error rate is tolerable because most genes are repeatedly transcribed.
  • The genetic code has synonyms (redundancy).
  • Amino acid substitutions can be functionally innocuous.
  • Large portions of many eukaryotic transcripts are excised when forming mature mRNAs.
slide33

Chain termination

  • Transcriptional terminators share two common features:
  • A series of 4 - 10 consecutive A-Ts with the A’s on the template strand. The transcribed RNA is terminated in or just past this sequence.
  • A G-C rich region with a palindromic (2-fold) symmetric sequence that is immediately upstream of the series of A-Ts.

This sequence forms a self-complementary “hairpin” that is very stable.

slide35

Rho factor aids in termination

  • Rho factor is ahelicase that unwinds RNA-DNA and RNA-RNA double helices dependent on the hydrolysis of NTPs.
  • Require a specific recognition sequence (80 -100 nt that lack a stable secondary structure and have multiple C rich regions, G poor regions) on the newly transcribed RNA upstream of the termination site.
  • Attaches to nascent RNA at recognition site and migrates in the 5’ 3’ direction until it encounters RNAP paused at termination site and unwinds the RNA-DNA duplex that forms the transcription bubble.
  • This releases the RNA transcript.
slide36

Figure 31-19a X-Ray structure of Rho factor in complex with RNA. (a) The Rho protomer with its N-terminal domain cyan, its C-terminal domain red, and their connecting linker yellow.

Figure 31-19b X-Ray structure of Rho factor in complex with RNA. (b) The Rho hexamer. Its six subunits, each of which are drawn in a different color, form an open lock washer-shaped hexagonal ring.

Page 1231

slide37

Figure 31-19c X-Ray structure of Rho factor in complex with RNA. (c) The solvent-accessible surface of the Rho hexamer as viewed from the top of Part b.

Page 1231

slide38

Control of transcription in prokaryotes

  • Prokaryotes need to respond to sudden environmental changes such as the influx of nutrients, by inducing the synthesis of proteins.
  • Transcription and translation are tightly coupled.
  • Ribosomes commence translation near the 5’ end of the nascent mRNA soon after it is made by RNAP.
  • Most prokaryotic transcripts are degraded within 1 - 3 min after their synthesis.
  • In contrast, eukaryotic induction takes hours or days to respond because the transcription takes place in the nucleus and has to be exported to the cytoplasm for translation.
slide39

Figure 31-24 An electron micrograph and its interpretive drawing showing the simultaneous transcription and translation of an E. coli gene.

Page 1237

slide40

Promoters

  • The more the promoter resembles the consensus sequence, the stronger the promoter.
slide41

lac repressor binding

  • lac repressor is a tetramer of 360 residue subunits which are each capable of binding one IPTG with a K = 10-6 M.
  • In the absence of inducer, binds to duplex DNA nonspecifically (K = 10-4)
  • Binds to the lac operator tightly (K = 10-13 M).
  • Binds faster than diffusion rate constant in solution, so lac repressor slides along DNA quickly until it finds the lac operator sequence.
  • lac operator sequence is nearly palindromic.
  • lac repressor prevents RNAP from forming a productive initiation complex.
figure 31 26 the nucleotide sequence of the e coli lac promoter operator region
Figure 31-26 The nucleotide sequence of the E. coli lac promoter–operator region.

N-terminus LacZ

C-terminus LacI

Page 1239

slide44

Catabolite repression

  • Glucose is the carbon source of choice for E. coli, so if it is present in large amounts, the bacterium will suppress the expression of genes encoding proteins involved in other catabolites’ metabolism.
  • This happens even when metabolites such as lactose, arabinose, or galactose are present in high concentrations.
  • Catabolite repression-prevents the wasteful duplication of energy-producing enzymes.
slide45
Figure 31-27 The kinetics of lac operon mRNA synthesis following its induction with IPTG, and of its degradation after glucose addition.

Page 1240

ad