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The dreaded “popcorn” problem … This is a 2 step problemPowerPoint Presentation

The dreaded “popcorn” problem … This is a 2 step problem

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The dreaded “popcorn” problem … This is a 2 step problem

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The dreaded “popcorn” problem … This is a 2 step problem

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- Step 1
- “Popcorn kernels pop unimolecularly…”

- The dreaded “popcorn” problem…
- This is a 2 step problem

= first-order reaction

ln(A) -ln(A0) = -kt

determine k first

- 29 kernels pop in 10 seconds when 400 total kernels are present. After 100 have popped, how many will pop over the next 10 seconds?

- 29 kernels pop in 10 seconds when 400 total kernels are present.After 100 have popped, how many will pop over the next 10 seconds?

- A0 = 400(initial number of kernels)
- t = 10 sec
- A = 371 (number of kernels at time t)
- k = 0.00753 sec-1

- Step 2
- Start over with a new initial condition

- 1st ORDER: ln(A) -ln(A0) = -kt
- and k = 0.00753 sec-1

- After 100 have popped, how many will pop over the next 10 seconds?

- A0 = 300(initial number of kernels)
- t = 10 sec
- k = 0.00753 sec-1

- Answer: 300-278.25 = 22.75