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Спецкурс. Осенний семестр 2008 г. PowerPoint PPT Presentation


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Методы оценок стандартных энтальпий и энергий Гиббса образования неорганических и органических соединений. Спецкурс. Осенний семестр 2008 г. Энтальпии реакции. Метод разностей. Однотипными называют две реакции, в которых каждому компоненту одной реакции соответствует

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Спецкурс. Осенний семестр 2008 г.

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2008

. 2008 .


2008

,

,

,

rHo(Y,T) - rHo(X,T) =

rHo(Y,0) - rHo(X,0) = H = const

rHo(AX,T) - rHo(BX,T) = HX

rHo(AY,T) - rHo(BY,T) = HY

HX- HY= const


2008

rHo(Y,T) / rHo(X,T) = H

rHo(AY,T) / rHo(AX,T) = HA

rHo(BY,T) / rHo(BX,T) = HB

HA / HB = const

:

CaTiO3 + 2 HF = CaF2 + TiO2 + H2O (),

(. .)

MgTiO3 + 2 HF = MgF2 + TiO2 + H2O ()

CaSiO3 + 2 HF = CaF2 + SiO2 + H2O ()

MgSiO3 + 2 HF = MgF2 + SiO2 + H2O ()

rHo(AX,T) - rHo(BX,T) = HX

rHo(AY,T) - rHo(BY,T) = HY

HX- HY= const


2008

fHo = A + Bn, fGo = C + Dn ( )

fHo

fHo

fHo = A*lgP + B


2008

fHo298 = -59.29 kcal/mol = -248.07 kJ/mol (9.1 %)


2008


2008

-

..

. . 1975


2008

.


2008

* =

.

.


2008

() (.. .)

Chen, X.-Q. Miedema's model revisited //

Calphad: Computer Coupling of Phase Diagrams and Thermochemistry

Volume 30, Issue 3, September 2006, Pages 266-269


2008

fGo(X,T) - fHo(X,T) = fGo(Y,T) - fHo(Y,T)

MO + CO2 = MCO3

MO + H2O = M(OH)2

MSO4 = MO + SO2 + O2


2008


2008

( .. . 1996. 70. 7. .1201)

fSTiO2 =-21.5R

V6O11

TiO(TiO2)n

n = 3,4, 9

fHTiO2 =-113357R

V5O9

Ti9O17

Ti7O13

V4O7

Ti8O15

V3O5

Ti6O11

Ti5O9

MoO2(MoO3)n

n = 3,4, 9

  • (1-)A1-xBx + A1-xBx= A1-xBx

  • = (x - x)/(x-x)

    = -(x-x)(x - x)/(xxx), rG(x) = (x)G


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