1 / 4

Chapter 9, section 3, part 2

Chapter 9, section 3, part 2. Percent Yield. Why percent yield?. Usually, not all the product possible is actually formed. theoretical yield maximum amount of product possible is calculated using limiting reactant and stoichiometry actual yield

dyee
Download Presentation

Chapter 9, section 3, part 2

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Chapter 9, section 3, part 2 Percent Yield

  2. Why percent yield? • Usually, not all the product possible is actually formed. • theoretical yield • maximum amount of product possible • is calculated using limiting reactant and stoichiometry • actual yield • the measured amount formed in lab reaction • always less than or equal to theoretical yield

  3. Example 1 • If 72.0 g of C2H2 reacts with an excess of Br2 and 729 g of the product is recovered, what is the percent yield? C2H2 + Br2 CHBr2CHBr2 First calculate theoretical yield: 72.0 g C2H2 1 mol C2H2 1mol CHBr2CHBr2 345.64 g CHBr2CHBr2 26.04 g C2H2 1 mol C2H2 1 mol CHBr2CHBr2 = 956 g CHBr2CHBr2 Then calculate percent yield: 729 g 100% = 76.3% 956 g

  4. Example 2 • If the percent yield of the reaction below is 73.8% and the reaction began with 24.3 g of CaO, how many grams of Ca(OH)2 were created? CaO + H2O  Ca(OH)2 First, calculate theoretical yield: 24.3 g CaO 1 mol CaO 1 mol Ca(OH)2 74.09 g Ca(OH)2 = 32.1 g Ca(OH)2 56.07 g CaO 1 mol CaO 1 mol Ca(OH)2 Then use given percent yield to calculate actual yield: 32.1 g Ca(OH)2 x 0.738 = 23.7 g Ca(OH)2

More Related