1 / 30

Ch. 8.2-3: Solving Systems of Equations Algebraically

Ch. 8.2-3: Solving Systems of Equations Algebraically. What is a System of Linear Equations?. A system of linear equations is simply two or more linear equations using the same variables. We will only be dealing with systems of two equations using two variables, x and y.

donter
Download Presentation

Ch. 8.2-3: Solving Systems of Equations Algebraically

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Ch. 8.2-3: Solving Systems of Equations Algebraically

  2. What is a System of Linear Equations? A system of linear equations is simply two or more linear equations using the same variables. We will only be dealing with systems of two equations using two variables, x and y. If the system of linear equations is going to have a solution, then the solution will be an ordered pair (x , y) where x and y make both equations true at the same time. We will be working with the graphs of linear systems and how to find their solutions graphically.

  3. inconsistent consistent independent dependent

  4. Definitions • Consistent: has at least one solution • Dependent: has an infinite amount of solutions

  5. Inconsistent: has no solutions

  6. Independent: has exactly one solution • Consistent: has at least one solution

  7. y x (1 , 2) How to Use Graphs to Solve Linear Systems Consider the following system: x – y = –1 x + 2y = 5 Using the graph to the right, we can see that any of these ordered pairs will make the first equation true since they lie on the line. We can also see that any of these points will make the second equation true. However, there is ONE coordinate that makes both true at the same time… The point where they intersect makes both equations true at the same time.

  8. y x (1 , 2) How to Use Graphs to Solve Linear Systems Consider the following system: x – y = –1 x + 2y = 5 We must ALWAYS verify that your coordinates actually satisfy both equations. To do this, we substitute the coordinate (1 , 2) into both equations. x – y = –1 (1) – (2) = –1  x + 2y = 5 (1) + 2(2) = 1 + 4 = 5  Since (1 , 2) makes both equations true, then (1 , 2) is the solution to the system of linear equations.

  9. Solve the following system by graphing: 3x + 6y = 15 –2x + 3y = –3 Graphing to Solve a Linear System Start with 3x + 6y = 15 Subtracting 3x from both sides yields 6y = –3x + 15 Dividing everything by 6 gives us… While there are many different ways to graph these equations, we will be using the slope – intercept form. Similarly, we can add 2x to both sides and then divide everything by 3 in the second equation to get To put the equations in slope intercept form, we must solve both equations for y. Now, we must graph these two equations

  10. y Solve the following system by graphing: 3x + 6y = 15 –2x + 3y = –3 x (3 , 1) Label the solution! Since and , then our solution is correct! Graphing to Solve a Linear System Using the slope intercept forms of these equations, we can graph them carefully on graph paper. Start at the y – intercept, then use the slope. Lastly, we need to verify our solution is correct, by substituting (3 , 1).

  11. Graphing to Solve a Linear System Let's summarize! There are 4 steps to solving a linear system using a graph. Step 1: Put both equations in slope – intercept form Solve both equations for y, so that each equation looks like y = mx + b. Step 2: Graph both equations on the same coordinate plane Use the slope and y – intercept for each equation in step 1. Be sure to use a ruler and graph paper! Step 3: Estimate where the graphs intersect. This is the solution! LABEL the solution! Step 4: Check to make sure your solution makes both equations true. Substitute the x and y values into both equations to verify the point is a solution to both equations.

  12. Substitution Substitution • Given two equations. Solve one equation for a variable. • Plug this expression in for the variable into the other equation. • Solve. • Plug this value into the first equation and solve it as well. • Write the answer as an ordered pair.

  13. Example: Solve 1. Solve for p 2. Plug into other equation and solve for q. 3. Plug value of q into initial equation. 4. Write the ordered pair (ABC order)

  14. Example: Solve 1. Solve for n 2. Plug into other equation and solve for m. 3. Plug value of m into initial equation. 4. Write the ordered pair (ABC order)

  15. Elimination • Given two equations. Make sure variables are lined vertically • Choose a variable to eliminate. It must become the opposite value of the same variable in the other equation. • Multiply the entire equation to create the needed values. • Add the two equations together • Solve for variable left. • Plug value into initial equation and solve. • Write the answer as an ordered pair

  16. Example: Solve • Eliminate n since they are opposites. • Add the two equations • Solve for m • Plug m back into the initial equation • Solve for n • Write the ordered pair (ABC order)

  17. Example: Solve • Eliminate h since they are opposites. • Multiply the second equation by 2. • Add the two equations • Solve for g • Plug g back into the initial equation • Solve for h • Write the ordered pair (ABC order)

  18. Ex#1 Solve the system by substitution. Check by graphing y = -2x + 1 – x + 2(-2x + 1) = 2 – x – 4x + 2 = 2 y = -2(0) + 1 -5x + 2 = 2 y = 0 + 1 -2 -2 y = 1 -5x = 0 -5 -5 (x, y) (0, 1) x = 0

  19. (0, 1)

  20. Ex#2 Solve the system by substitution. y = -2x + 13 4x – 3(-2x + 13) = 11 4x + 6x – 39 = 11 y = -2(5) + 13 10x – 39 = 11 y = -10 + 13 +39 +39 y = 3 10x = 50 10 10 (x, y) (5, 3) x = 5

  21. Try These: Solve the system by substitution. x = 2y – 7 3(2y – 7) + 4y = 9 x = 2(3) – 7 6y – 21 + 4y = 9 x = 6 – 7 10y – 21 = 9 x = -1 +21 +21 10y = 30 (x, y) 10 10 (-1, 3) y = 3

  22. Ex#2 Solve the system by substitution. 6x – 3(2x – 5) = 15 6x – 6x + 15 = 15 15 = 15 Infinite solutions

  23. Ex#2 Solve the system by substitution. 6x + 2(-3x + 1) = 5 6x – 6x + 2 = 5 2  5 No Solution

  24. To eliminate a variable line up the variables with x first, then y. Afterward make one of the variables opposite the other. You might have to multiply one or both equations to do this.

  25. Example #3: Find the solution to the system using elimination. 2 3x – y = 8 6x – 2y = 16 x + 2y = 5 x + 2y = 5 7x + 0 = 21 7x = 21 7 7 3 + 2y = 5 x = 3 -3 -3 2y = 2 y = 1 (x, y) (3, 1)

  26. Example #3: Find the solution to the system using elimination. -3 2x + y = 6 -6x – 3y = –18 4x + 3y = 24 4x + 3y = 24 –2x = 6 x = – 3 2(–3) + y = 6 -6 + y = 6 y = 12 (x, y) (–3, 12)

  27. Example #3: Find the solution to the system using elimination. 3 3x – 4y = 16 9x – 12y = 48 5x + 6y = 14 10x + 12y = 28 2 19x = 76 x = 4 5(4) + 6y = 14 20 + 6y = 14 -20 -20 6y = -6 (x, y) y = -1 (4, -1)

  28. Example #3: Find the solution to the system using elimination. 5 -3x + 2y = -10 -15x + 10y = -50 5x + 3y = 4 15x + 9y = 12 3 19y = -38 y = -2 5x + 3(-2) = 4 5x – 6 = 4 5x = 10 x = 2 (x, y) (2, -2)

  29. Example #3: Find the solution to the system using elimination. 12x – 3y = -9 12x – 3y = -9 -4x + y = 3 -12x + 3y = 9 3 0 = 0 Infinite solutions

  30. Example #3: Find the solution to the system using elimination. 6x + 15y = -12 6x + 15y = -12 -2x – 5y = 9 -6x – 15y = 27 3 0 = 15 No solution

More Related