1 / 21

MAT 360 Lecture 6

MAT 360 Lecture 6. Hilbert Axioms Congruence. To come. MLC Sketchpad projects Midterm – 4 problems Models and interpretation. Proof from Hilbert’s axioms Produce a definition of some known object

diamond
Download Presentation

MAT 360 Lecture 6

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. MAT 360 Lecture 6 • Hilbert Axioms • Congruence

  2. To come • MLC • Sketchpad projects • Midterm – 4 problems • Models and interpretation. • Proof from Hilbert’s axioms • Produce a definition of some known object • Definitions of terms we learn (like independence, categorical) will not be asked directly but “applied”

  3. Congruence Axiom 1 • If A and B are distinct points then for any point A’ and for each ray r emanating from A’ there exist a unique point B’ on r such that B’≠ A’ and AB ~ A’B’.

  4. Recall we have an undefined term • CONGRUENT • This term will be used in two ways: • Segment CD is congruent to segment EF • Angle <A is congruent to angle <B • Question: Could we use different words for the use 1. and the use 2?

  5. Congruence Axiom 2 • If AB ~ CD and AB ~ EF then CD ~ EF • AB ~ AB

  6. Prove that • segment AB is congruent to segment BA • If AB ~ CD then CD ~ AB

  7. Congruence Axiom 3 • If • A*B*C, • A’*B’*C’, • AB ~ A’B’ • BC ~ B’C’ • Then AC ~ A’C’

  8. Congruence Axiom 4 • Given an angle <BAC, a ray A’B’ and a side of the line A’B’ there is a unique ray A’C’ emanating from the point A’ such that • <BAC < B’A’C’

  9. Congruence Axiom 5 • If <A ~ <B and <A ~ <C then <B ~ <C. • <A~<A

  10. Proposition • If <A ~ <B then <B ~ <A

  11. Definition • Two triangles are congruent if there is a one to one correspondence between the vertices so that the corresponding sides are congruent and the corresponding angles are congruent. • NOTE: This is third use of the word “congruent.”.

  12. Congruence Axiom 6 (SAS) • If two sides and the included angle of a triangle are congruent respectively to two sides and the included angle of another triangle then the two triangles are congruent.

  13. Proposition • Given a triangle ΔABC and a segment DE such that DE~AB there is a unique point F on a given side of the line DE such that the ΔABC~ΔDEF

  14. Proposition • If in ΔABC we have that AB~AC then <B~<C.

  15. Definition • The symbols AB<CD mean that there exists a point E between C and D such that AB~CE. • The symbols CD>AB have the same meaning.

  16. Proposition • Exactly one of the following conditions holds • AC<CD, AB~C or AB>CD • If AB<CD and CD~EF then AB<EF. • If AB>CD and CD~EF then AB>EF. • If AB<CD and CD<EF then AB<EF.

  17. More Propositions • Supplements of congruent angles are congruent. • Vertical angles are congruent to each other • An angle congruent to a right angle is a right angle. • For every line l and every point P there exists a line through P perpendicular to l.

  18. Definition • Suppose that there exists a ray EG between ED and EF such that • <ABC ~ <GEF. • Then we write <ABC < <DEF.

  19. Proposition • Exactly one of the following holds • <P < <Q , <Q < <P or P ~ Q. • If <P<<Q and <Q~<R then<P <<R • If <P ><Q and <Q~<R then<P > <R (typo) • If <P <<Q and <Q<R then <P<<R

  20. Proposition (SSS) • Given triangles ΔABC and ΔDEF. If AB~DE, BC~EF and AC~DF then • ΔABC~ ΔDEF • Note: from now on, in the slides, we denote congruence by ~

  21. Proposition • All right angles are congruent with each other.

More Related