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Finding the z value. Help for Chapter 5, SHW Problem 7. .0301. .0301. LSL. Mean. USL. X. z = ?. 0. Assume that 6.02% of a company product is defective. Find the z value corresponding to the upper spec. limit. (Use .0602 and split it between

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finding the z value

Finding the z value

Help for Chapter 5, SHW Problem 7

slide2

.0301

.0301

LSL

Mean

USL

X

z = ?

0

Assume that 6.02% of a company product is

defective. Find the z value corresponding to the

upper spec. limit. (Use .0602 and split it between

the two tail areas beyond spec limits.)

slide3

Use Appendix B, p. 652 to find z. Since the tail area

above USL is .0301 and Appendix B gives the area

between 0 and z, we Look up the area between 0

and z, which is .5000 -.0301. =.4699

.4699

.0301

.0301

LSL

USL

z = 1.88

0

From Appendix B, the z value is z = 1.88. See next

slide.

meaning of z
Meaning of z
  • The z value tells us that the upper spec. limit is 1.88 standard deviations above the mean.
  • Because the normal distribution is symmetrical, the z value corresponding to the lower spec. limit is -1.88.
  • This indicates that the lower spec. limit is 1.88 standard deviations below the mean.
slide6

The expression for z is:

If we know any 3 of the terms in z, we can solve for the 4th. For example, if know z, Mean, and the estimated standard deviation, we can solve for USL.

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