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The Heart of Chemistry

Representative Particles: Molecules, Ions, Atoms, Formula Units. Volume: Liters. Mole. The Heart of Chemistry. ÷ 22.4 L. ÷ 6.02 x 10 23. X 22.4 L. x 6.02 x 10 23. ÷ molar mass (g). DIMO: Divide In Multiply Out. X molar mass (g). Mass: grams. N. V. Mole. The Heart of Chemistry.

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The Heart of Chemistry

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  1. Representative Particles: Molecules, Ions, Atoms, Formula Units Volume: Liters Mole The Heart of Chemistry ÷22.4 L ÷ 6.02 x 1023 X 22.4 L x 6.02 x 1023 ÷ molar mass (g) DIMO: Divide In Multiply Out X molar mass (g) Mass: grams

  2. N V Mole The Heart of Chemistry ÷ V0 x V0 ÷N0 xN0 ÷MM DIMO: Divide In Multiply Out n X MM m

  3. 2…Mole, Particles • Steps: • Use Dimension Analysis to convert Particles to or from Moles using Avogadro’s Number

  4. Ex:2.1: How many formula units of NaCl are in 2.70-mol of NaCl?

  5. Ex:2.1: How many formula units of NaCl are in 2.70-mol of NaCl? n = 2.70-mol NaCl N = ? N0 = 6.02 x 1023 f.u./mol

  6. Ex:2.1: How many formula units of NaCl are in 2.70-mol of NaCl? n = 2.70-mol NaCl N = ? N0 = 6.02 x 1023 f.u./mol N = n x N0 = (2.70-mol)(6.02E23f.u./mol) N = 1.63E24 formula units NaCl

  7. Ex:2.2: How many moles of Helium atoms are present in a sample containing of in 1.27 x1024 atoms? n = ? N = 1.27E24 atoms He N0 = 6.02 x 1023 atoms/mol

  8. Ex:2.2: How many moles of Helium atoms are present in a sample containing of in 1.27 x1024 atoms? n = ? N = 1.27E24 atoms He N0 = 6.02 x 1023 atoms/mol n = N ÷ N0 = (1.27E24 @)/(6.02E23@/mol) n = 2.11 moles He

  9. 3…Mole, Liters • Steps: • Use Dimension Analysis to convert Liters to or from Moles using Molar Volume

  10. Ex:3.1: What is the volume in liters of a 1.78 x 10-3 moles of Helium at STP? n = 1.78E-3 moles He V = ? V0 = 22.4-Liters/mol V = n x V0 = (1.78E-3 mol)(22.4L/mol) V = 0.0399 L = 39.9 mL

  11. Ex:3.2: How many moles of Oxygen are in a volume of 0.560 liters? n = ? V = 0.560 Liters V0 = 22.4-Liters/mol n = V ÷ V0 = (0.560 L)/(22.4L/mol) n = 0.025 moles Oxygen)

  12. Page 186 in the textbook

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