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# Lesson 3.4, page 410 Exponential & Logarithmic Equations - PowerPoint PPT Presentation

Lesson 3.4, page 410 Exponential & Logarithmic Equations. Objective: To solve exponential and logarithmic equations. Why it’s important…. This skill can be used to solve many types of real-world problems, including those involving animal population. Solving with Same Base.

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### Lesson 3.4, page 410Exponential & Logarithmic Equations

Objective: To solve exponential and logarithmic equations.

• This skill can be used to solve many types of real-world problems, including those involving animal population.

• If bM = bN , then M = N.

STEPS

• Re-write the equation in for form bM = bN.

• Set M = N.

• Solve for the variable.

• Check Point 1: Solve

• a) 5 3x – 6 = 125 b) 8 x + 2 = 4 x - 3

• How do we solve an exponential equation in which we can’t re-write with the same base?

• Answer: take the natural or common logarithm of each side

• Isolate the exponential expression.

• Take the natural logarithm on both sides.

• Simplify using one of the following properties: ln b x = x ln b or ln e x = x.

• Solve for the variable.

• Check Point 2: Solve 5x = 134.

• Check Point 3: Solve 7e 2x – 5 = 58.

• Exponential equation – form b cx = a; (an equation with a variable in the exponent)

Example: 73x = 20

Property of Logarithmic Equality

For any M > 0, N > 0, a > 0, and a 1,

loga M = loga N

M = N

• In other words, take the log of both sides and solve.

Solve: 2x = 50

This is an exact answer. We cannot simplify further, but we can approximate using a calculator.

x  5.6439

We can check by finding 25.6439  50.

• Find each value below and compare.

• Check Point 4: Solve 32x - 1 = 7x + 1.

• Check Point 5: Solve e2x – 8ex + 7 = 0.

• A) 3x = 4 B) 62x = 21

C) 3x+4 = 101 D) e0.25w = 12

• Equations containing variables in logarithmic expressions, such as

log2 x = 16 and log x + log (x + 4) = 1,

are called logarithmic equations.

• Obtain a single logarithmic expression on one side.

• Write an equivalent exponential equation.

• Solve and check.

• Check Point 6

a) log2 (x – 4) = 3 b) 4 ln(3x) = 8

• Check Point 7

Solve: log x + log (x – 3) = 1.

Solve: log4x = 3

More Examples

Another Example

Check: For x = 3:

For x = 3:

Negative numbers do not have real-number logarithms. The solution is 3.

• Get a single log on each side.

• Use the property:

If log b M = log b N, then M = N.

• Solve for the variable.

• Check Point 8

Solve ln (x - 3) = ln (7x – 23) – ln (x + 1).

• Solve:

• Check Point 9: Use the formula in example 9 to answer the question: “What blood alcohol concentration corresponds to a 7% risk of a car accident? (In many states, drivers under the age of 21 can lose their licenses for dring at this level.)

• Check Point 10: How long, to the nearest tenth of a year, will it take \$1000 to grow to \$3600 at 8% annual interest compounded quarterly?

• Check Point 11: Use the function in Example 11 to find in which year there will be 210 million Internet users in the United States.

a) 75x = 3000 b) 52x = 16

c) log(7 – 2x) = -1

d) log 6 – log 3x = -2