Torque Notes

1. Torque Notes

2. Translational ….. Circular…..now rotational • Difference between Circular & Rotational motion • CAUSES…. Fnet FC, and now NET • Vector – direction & units

3. ( ) distance to pivot point t Force = F and d must be  REQUIREMENT:

4. 6 N 10 N 10 N  = 10(1.5)  = 15 N-m CCW

5. 6 N 10 N 10 N  = 10(1.5)  = 10(3)  = 15 N-m  = 30 N-m CCW CW

6. 6 N 10 N 10 N  = 10(1.5)  = 10(3)  = 6(4.5)  = 15 N-m  = 30 N-m  = 27 N-m CCW CW CW NET = 42 N-m CW

7. 20 N 20 N 12 N 12 N  = 20(7)  = 12(2.5)  = 20(2)  = 12(5)  = 140 Nm CW  = 30 Nm CW  = 40 Nm CCW  = 60 Nm CCW 32 N  = 32(5)  = 160 Nm CCW NET = 90 N-m CCW

8. only perpendicular component causes torque 20 N 20 N 40º 40º 20º 28 N  = sin40(20)(2)  = sin20(28)(1)  = sin40(20)(3)  = 25.7 Nm CW  = 9.57 Nm CW  = 38.6 Nm CCW NET = 3.33 N-m CCW

9. 8B Examples

10. 53

11. T 53° 315 545 ROTATIONAL CW = CCW 545 (1.5) + 315 (2.5) = sin53 T (5) T = 402 N

12. T 53° 315 545 539 242 591 N 66° above the hor 321 242 TRANSLATIONAL NEED: 539 UP 242 RIGHT

14. Where to put pivot point? NOT pivoting....so it could "not pivot" about ANY point! pick a point that will eliminate torque from a force you don't know

15. FN Wbridge Wbear ROTATIONAL CW = CCW FN(12) = 250(9.8)(6) + 900(9.8)(4) FN = 4165 N