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2 C 6 H 6 + 15 O 2 → 12 CO 2 + 6 H 2 O

2 C 6 H 6 + 15 O 2 → 12 CO 2 + 6 H 2 O. How many moles of water are made by burning 0.35 moles of C 6 H 6 ?. 6 mol H 2 O = 3 = X 2 mol C 6 H 6 1 0.35 X = 1.1 mol H 2 O. 2 C 6 H 6 + 15 O 2 → 12 CO 2 + 6 H 2 O.

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2 C 6 H 6 + 15 O 2 → 12 CO 2 + 6 H 2 O

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  1. 2 C6H6 + 15 O2 → 12 CO2 + 6 H2O • How many moles of water are made by • burning 0.35 moles of C6H6? • 6 mol H2O = 3 = X • 2 mol C6H61 0.35 • X = 1.1 mol H2O

  2. 2 C6H6 + 15 O2 → 12 CO2 + 6 H2O • What is the mole ratio between the products? Label with the formulas. 12 CO2 =2 CO26 H2O =1 H2O 6 H2O 1 H2O or 12 CO2 2 CO2

  3. 2 C6H6 + 15 O2 → 12 CO2 + 6 H2O • How many grams of carbon dioxide are • made by burning 18.0 g of C6H6? • 2 C6H6= 1 C6H6= 78.0 g C6H6= 18.0 g • 12 CO26 CO2 264 g CO2 X • X = 60.9 g CO2

  4. 2 C6H6 + 15 O2 → 12 CO2 + 6 H2O • If the actual lab result from burning 18.0g C6H6 is 45.6 grams CO2, how much is the % yield? • % yield = Actual (lab) result x 100 % Theoretical (calculated) • % yield = 45.6 g x 100 = 74.9 % • 60.9 g

  5. 2 C6H6 + 15 O2 → 12 CO2 + 6 H2O • How many grams of water are made by burning 78.0 g of C6H6 with 220.0 g of oxygen? 2 mol C6H6= 156 g C6H6= 78.0 g 6 mol H2O 108 g H2O X X = 54.0 gH2O 15 mol O2 = 480 g O2= 220.0 g O2 6 mole H2O 108 g H2O X X = 49.5 g H2O

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