2/1
This presentation is the property of its rightful owner.
Sponsored Links
1 / 16

Основни въпроси: 1. Променлив електричен ток. Основни понятия 2. Получаване на променлив ток PowerPoint PPT Presentation


  • 388 Views
  • Uploaded on
  • Presentation posted in: General

Лекция 2/1 Променлив електричен ток. Основни понятия. Получаване и начини на изразяване на синусоидални величини. Основни въпроси: 1. Променлив електричен ток. Основни понятия 2. Получаване на променлив ток 3. Основни параметри и стойности на променливия ток

Download Presentation

Основни въпроси: 1. Променлив електричен ток. Основни понятия 2. Получаване на променлив ток

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Presentation Transcript


1 2

2/1 . . .


1 2

:

1. .

2.

3.

4. . .


1 2

1. .

-O - , ..., , , ;

- , , , ;

- , ..;

- ;

- ;

i

t

. 1.1

T


1 2

i

i

t

t

.1.2.

- , (, .) - ;

- - - - .

T

a)

b)


1 2

2.

, ;

.2.1

ab = l , ...,

e1 = Blvsint (2.1);

cde2 = Blvsin(t + ) = - Blvsint (2.2);

S

S

a

b

= t

e1

m

n

d

e2

d

c

N

N


1 2

- ;

v = a/2 - - ;

t (t +) - , ;

... , ,

e = 2Blvsint = Emsint (2.3) ;

m= 2Blv ..., , /2 ;

m= 2Blv = 2Bl /2 = BS = m (2.4) ;

W ,

m= Wm (2.5) ;

3. .


1 2

3.1.

- - , ;

- -- , - , s;

- - f = 1/T, Hz();

1Hz = 1 1 ;

- - , - = 2/ , rad/s ( ) 1/s ;

- - (t +1) - .. . t=0 , .. 1, , . ( 1- 2 );


1 2

, , ; , .

3.2.

- - - i, u, e;

- -- , . - Im , Um , Em ;

- -I , U ,;

,

, /2, -

,

;

i

Im

I

t

/2

. 3.1


1 2

(3.1)

,

(3.2)

I0 =I ; (3.1) (3.2) ,

I = ( 3.3)

- - : , , , , R, , ;

= = I2 RT (3.4)


1 2

A~=(3.4) ;

A~ = ,

(3.5);

= Im / I = 1,4142 (3.6);

- ,

= I / I = 1,11 (3.7);

4. -.

4.1.


1 2

, , ..., . , ( ) ,

u = Umsin(t - ) (4.1) ;

, - . ;

4.2. - i = Imsin t ; = t

i

2

i

2

1

1`

3

3

Im

Im

1

)

8

8

4

0

t

0

4

7

5

5

7

6

6

.4.1


1 2

, , ;

4.3.

i = Im sin (t + ) Im , t=0 t

. - , , , - sin- .

i

Im i- . - - . , - , , -

Im

i1

)

t

O

.4.2


1 2

- - , ;

- .

4.4. -

- . , - . - . ,

i = a + jb = Im (cost + jsin t ) = Im e j t ;

- .;

-- .

4.5.

, P = IU


1 2

.. - p = iu ;

- , ,

p = Im Um sin2t = (Im Um / 2)(1 - cos 2t) (4.2)

, ,

P== UI (4.3) ;

,

u = Umsin(t +) ; i=Imsint ;

p=iu=UmImsintsin(t +)= 0,5UmIm[(1-cos2t)cos +

+sin2tsin] =UI[(1-cos2t)cos +sin2tsin] (4.4)


1 2

(4.4) 0 -, ,

P = IUcos (4.5)

, ,

I = Ia + Ir ;

Ia = Icos, ; Ir= Isin;

(4.4) ,

p=UIa(1-cos2t)+UIr sin2t; (4.6)

0 ,

P = UIa + UIr = IUcos +IUsin = Pa +Pr ; (4.7)

pa = UIa(1-cos2t), W; (4.8)

pr = UIr sin2t , VAr; (4(9)

I

Ir

)

U

Ia


1 2

;

- ( ) - S = UI = P2a+P2r (4.10) ;

- cos = Pa / S (4.11)


  • Login