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Chapter 2 Sections 5-6

Chapter 2 Sections 5-6. Problem Solving and Formulas. Problem Solving. The length of a rectangle is 6 inches more than its width. The perimeter of the rectangle is 24 in. What is the length?. P = 2l +2w. 24 = 2(w+6) + 2(w). w. 24 = 2w + 12 + 2w. l = w + 6. 24 = 4w + 12. w + 6. l = 3 +6.

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Chapter 2 Sections 5-6

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  1. Chapter 2 Sections 5-6 Problem Solving and Formulas

  2. Problem Solving • The length of a rectangle is 6 inches more than its width. The perimeter of the rectangle is 24 in. What is the length? P = 2l +2w 24 = 2(w+6) + 2(w) w 24 = 2w + 12 + 2w l = w + 6 24 = 4w + 12 w + 6 l = 3 +6 12 = 4w l = 9 in 3 = w

  3. The width of a rectangle is 2 cm less than its length. The perimeter of the rectangle is 16 cm. What is the length? P = 2l + 2w l – 2 16 = 2l + 2 (l - 2) 16 = 2l + 2l – 4 16 = 4l – 4 l 20 = 4l l = 5 cm

  4. Consecutive Integers-differ by 1. • The sum of three consecutive integers is 147. Find the integers. N + N + 1 + N + 2 = 147 N: first number N+1: second number N +2 : third number 3N + 3 = 147 3N = 144 N = 48 48, 49, 50

  5. The sum of three consecutive integers is 48. • The sum of four consecutive even integers is 60. • The sum of two consecutive odd integers is 44.

  6. Literal Equation- two or more variables • Solve the formula A = ½ bh for height h. • Solve the formula for the perimeter of a rectangle for the width. P = 2(l + w) • Solve the formula V = lwh for w.

  7. Transforming Equations • Solve y = 5x + 7 for x. • Solve z – br = p for b. • Solve y + 2x = 5 for y. • Solve 5x + 4y = 4 for y. • Solve 2x + 7y = 4 for y.

  8. HW # 6 • Page 107 (1, 2, 4, 6 -8) • Page 113 (1-6, 9 -14)

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