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# How Tall is It? PowerPoint PPT Presentation

How Tall is It?. Megan Johnson Alex Gaskins Thomas Rush Hassan Ali. 30 Degrees. Tan x= opposite/adjacent Tan30=x/336 (336)Tan30=x x≈193.99 inches h= x+ eye height ≈193.99+60 h≈253.99 inches. Short leg. 112√3. Long leg. ∙ Hassan’s Triangle: ∙ 60 inches (eye height)

How Tall is It?

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## How Tall is It?

Megan Johnson

Thomas Rush

Hassan Ali

### 30 Degrees

Tan30=x/336

(336)Tan30=x

x≈193.99 inches

h= x+ eye height

≈193.99+60

h≈253.99 inches

Short

leg

112√3

Long leg

∙ Hassan’s Triangle:

∙ 60 inches (eye height)

∙ 28 feet=336 inches (base)

336”

Eye height

Long leg=336

Short leg=x

Short leg=long leg/√3

x=336/√3

=336√3/3

=112√3

h= x + eye height

=112√3+60

≈193.99+60

h≈253.99

60”

Base

336”

### 45 Degrees

Tan45=x/168

(168)Tan45=x

X= 168 inches

h= x+ eye height

= 168+63

h= 231 inches

168”

leg₂

Megan’s triangle:

63 inches (eye height)

14 feet=168 inches (base)

leg₁

In a 45-45-90 triangle, the two legs are

congruent.

leg₁=leg₂

168=168

H= leg + eye height

= 168 + 63

= 231 inches

168”

168” eye

height

base

168”

### 60 degrees

Tan60=x/84

(84)Tan60=x

X≈ 145.49 inches

h= x+ eye height

≈145.49+65

≈210.49 inches

Long

leg

145.49”

Thomas’s triangle:

65 inches (eye height)

7 feet= 84 inches (base)

Short leg

84”

Eye

height

Short leg=84

Long leg = x

x= 84∙√3

x= 84√3

h= x + eye height

=84√3+65

≈145.49+65

≈210.49 inches

65”

Base 84”

### 10 degrees

Tan10=x/936

(936)Tan10=x

x≈165.04 inches

h= x+ eye height

≈165.04+59

h≈224.04 inches

165.04”

936”

59”

Alex’s triangle:

59 inches (eye height)

78 feet = 936 inches

Base 936”

### Conclusion

• We used the Trigonometry to find the missing side.

• We then used the Special Right Triangle Formulas to find the third and final side to the triangle.

• Average Height Calculated

229.87 inches