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Wff or not wff ?. Get ready to play!!!. 1. Cube(a). Cube(a). 2.  Cube(x).  Cube(x).  Cube(x). A quantifier must always be followed by a variable, e.g. y Cube(x). 3. Tet (x). Tet (x). 4. Smaller(Cube(a), Tet (b)). Smaller(Cube(a), Tet (b)). Smaller(Cube(a), Tet (b)).

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wff or not wff

Wffor not wff?

Get ready to play!!!

cube x1
Cube(x)
  • A quantifier must always be followed by a variable, e.g.

y Cube(x)

smaller cube a tet b1
Smaller(Cube(a), Tet(b))
  • The only things you can put into a predicate hole are a name, a variable, or a function.
  • You can’t put a predicate into another predicate. In this case you need to write:

(Cube(a)  Tet(b))  Smaller(a, b)

z tet x cube a1
z(Tet(x)  Cube(a))
  • Order of construction:

Tet(x)

Cube(a)

(Tet(x)  Cube(a))

z(Tet(x)  Cube(a))

c large c1
c Large(c)

A quantifier must be followed by a variable, i.e. one of the letters:

t, u, v, w, x, y, z. So you need (e.g.):

v Large(v)

smaller a large a1
Smaller(, a)  Large(a)
  • The only things you can put into a predicate hole are a name, a variable, or a function.
  • You can’t put a quantifier directly into the hole of a predicate. In this case you need:

x (Smaller(x, a)  Large(a))

slide27

Cube(a)  Large(a)  Small(y)

  • You need to add brackets when using  and . Then, depending on the order of construction, you’ll get either:

(Cube(a)  Large(a)) Small(y) or

Cube(a) (Large(a)  Small(y))

  • (I left off the outer pair of brackets, as usual.)
y dentist father y rich y1
y(Dentist(father(y))  Rich(y))
  • Order of construction:

Dentist(father(y))

Rich(y)

(Dentist(father(y))  Rich(y))

y(Dentist(father(y))  Rich(y))

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