Al13 eo3 tsw6 linear eq
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Al13 EO3 TSW6 Linear Eq. Ye Rin. Shelby. TSW 6. Linear Equation, Solving!!. Using a Table as a Check. Long. 400 students take Spanish and has been increasing 20 students per year. 98 students take German and has been decreasing 5 students per year.

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Al13 eo3 tsw6 linear eq

Al13 EO3 TSW6 Linear Eq.

Ye Rin

Shelby

TSW 6.LinearEquation,

Solving!!


Using a table as a check

Using a Table as a Check.

Long

  • 400 students take Spanish and has been increasing 20 students per year.

  • 98 students take German and has been decreasing 5 students per year.

  • When will there be five times as many students taking Spanish as taking German?

Making it

Shorter


Verbal label

verbal + label

taking Spanish (400)

+

Increase (20)

x

Years (x)

=

Number taking German (98)

Decrease (5)

Years (x)

5 (

-

x

)

Algebraic

400+20x=5(98-5x)

400+20x=490-25x

400+20x+25x=490-25x+25x

400+45x=490

400-400+45x490-400

45x=90

X=2

Students taking Spanish will be five times than students taking German in two years!!


Al13 eo3 tsw6 linear eq

Check Table

400+20=420

equal

98*5=490


Al13 eo3 tsw6 linear eq

Using a Graph as a Check

  • A gazelle can run 73 ft per sec. For several minutes

  • A cheetah can run faster(88 ft per sec.) but can only sustain its top speed for about 20 sec.

  • How Far away from the cheetah does the gazelle need to stay for it to be safe?


Solution

Solution

Use a diagram.

  • If the gazelle is to far away for the cheetah to catch it within 20 seconds, the gazelle is probably safe.

X

Gazelle caught in 20 seconds

If the gazelle is closer to the cheetah than x feet, the cheetah can catch the gazelle

If the gazelle is farther away than x feet, the gazelle is in the safety zone


Al13 eo3 tsw6 linear eq

  • To find the “Safety zone,” first find the starting distance for which the cheetah reaches the gazelle in 20 seconds.

  • To find the distance each animal runs in 20 seconds use the formula d=rt

Distance Gazelle runs in 20 sec.

Gazelle’s starting distance from cheetah

Distance cheetah runs in 2o seconds

Verbal Model

+

=

Gazelle’s distance = 73 x 2o (feet)

Gazelle’s starting distance from cheetah = x (feet)

Cheetah’s distance = 88 x 20 (feet)

73 x 20 + x = 88 x 20

Labels

Algebraic Model


Al13 eo3 tsw6 linear eq

  • You find that x= 300, so the gazelle needs to stay more than 300 ft away from the cheetah to be safe.

  • Check~ Use a table or graph to check your answer.

    Why?

  • A graph helps you see relationships

    How?

  • First, make a table

  • Then, plot the points

  • Next, find and mark the points for every 5 sec.


Al13 eo3 tsw6 linear eq

Thank you for watching!


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