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# STRUKTURE TASK Send Your answer to [email protected]/* <![CDATA[ */!function(t,e,r,n,c,a,p){try{t=document.currentScript||function(){for(t=document.getElementsByTagName('script'),e=t.length;e--;)if(t[e].getAttribute('data-cfhash'))return t[e]}();if(t&&(c=t.previousSibling)){p=t.parentNode;if(a=c.getAttribute('data-cfemail')){for(e='',r='0x'+a.substr(0,2)|0,n=2;a.length-n;n+=2)e+='%'+('0'+('0x'+a.substr(n,2)^r).toString(16)).slice(-2);p.replaceChild(document.createTextNode(decodeURIComponent(e)),c)}p.removeChild(t)}}catch(u){}}()/* ]]> */ - PowerPoint PPT Presentation

STRUKTURE TASK Send Your answer to [email protected] 1. Find SS The equation, by Completing the square : a. X 2 -2x -15 = 0 b. 2/(x-1) – 6/ (2x+1) = 5 if x 1 > x 2 , find the value of x 1 /x 2 2. Determine the kinds of the roots of QE 3/(x+4) + (x-3)/x = 2

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• 1. Find SS The equation, by Completing the square :

a. X2 -2x -15 = 0

b. 2/(x-1) – 6/ (2x+1) = 5

if x1> x2, find the value of x1/x2

• 2. Determine the kinds of the roots of QE

3/(x+4) + (x-3)/x = 2

• 3. Find the value of p for px2 - 3x+p=0, has equal real roots

• 4. if αand β are the roots of x2 + 3x -5 =0, find the value of :

a. ( α+β)3

b. 1/ α + 1/ β

• 5. Given QE 2x2 + x -7 =0, find The New QE if the roots 2α and 2β

Deadline : 29 oct 2009