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Displacement with constant accelerationPowerPoint Presentation

Displacement with constant acceleration

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Displacement with constant acceleration

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Displacement with constant acceleration

How far, how fast?

- We have seen a way to calculate vavg already:
vavg= Δx / t

- Let’s look at the Old School way to find an average….

- If you wanted to find the average of these numbers:
5,3,7 and 5

You would just add them up and divide by 4

Mmmk.

- You can do the same thing with velocities
- Suppose a car accelerates from 0m/s for 30 sec at 1m/s2.

That’s gonna take forever to do!

- OR… There’s a much easier way:
- If acceleration is constant (it always will be for us.) average the first and last velocities and you get the same answer.

Oh, good!

- We now have two ways to find vavg :
- Now let’s put them together…

Uhhhh…

- 1st:

…

- 1st:
- Now, substitute in
- 2nd:

…

- 1st:
- Now, substitute in
- 2nd:
- New Equation:

Ok, got it!

- A racing car reaches a speed of 42 m/s. It then begins a uniform negative acceleration, using its parachute and braking system, and comes to rest 5.5s later. Find the distance that the car travels during braking.

- A racing car reaches a speed of 42 m/s. It then begins a uniform negative acceleration, using its parachute and braking system, and comes to rest 5.5s later. Find the distance that the car travels during braking.
- Givens: vi=42 m/st= 5.5 s vf=0 m/sΔx= ?

- A racing car reaches a speed of 42 m/s. It then begins a uniform negative acceleration, using its parachute and braking system, and comes to rest 5.5s later. Find the distance that the car travels during braking.
- Givens: vi=42 m/st= 5.5 s vf=0 m/sΔx= ?
- Formula:

- Givens: vi=42 m/st= 5.5 s vf=0 m/sΔx= ?
- Formula:

- For classwork, complete Practice C, Pg. 53