# Problem # 1-6/5 - PowerPoint PPT Presentation

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Problem # 1-6/5. mean core length = 52 cm length of air gap = 0.14 cm cross-sectional area = 18 cm 2 air gap flux density = 1.2 T Determine the voltage E. Use magnetization curve shown in Fig. 1.5. Problem #1-6/5. To determine the voltage E coil

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Problem # 1-6/5

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### Problem # 1-6/5

mean core length = 52 cm length of air gap = 0.14 cm

cross-sectional area = 18 cm2 air gap flux density = 1.2 T

Determine the voltage E.

Use magnetization curve shown in Fig. 1.5

### Problem #1-6/5

• To determine the voltage Ecoil

• Find the current in the coil, Icoil

• Ecoil=IcoilRcoil

• To determine the current Icoil

• Calculate the total mmf

• Calculate the coil current

### Problem #1-6/5 continued

• To determine F, calculate H

### Problem #1-6/5 continued

• To determine Hcore use Fig. 1.15

• Hcore={1.15 oersteds}{79.577 A-t/m/oersted}

• Hcore=91.5 A-t/m

• Then calculate Fcore

• Fcore=Hcorelcore

• Fcore={91.5 A-t/m}{0.52 m}

• Fcore=47.58 A-t

### Problem #1-6/5 continued

• To determine Hgap

• Hgap={1.2 Wb/m2}/{4πx10-7 Wb/A-t-m}

• Hgap=955.4x103 A-t/m

### Problem #1-6/5 continued

• Calculating Fgap

• Fgap=Hgaplgap

• Fgap={955x103 A-t/m}{0.0014 m}

• Fgap=1337 A-t

• The total mmf

• Ftotal=Fcore+Fgap

• Ftotal={47.58+1337} A-t = 1384.58 A-t

### Problem #1-6/5 continued

• Calculate the coil current Icoil

• Finally, the voltage