Problem 1 6 5
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Problem # 1-6/5. mean core length = 52 cm length of air gap = 0.14 cm cross-sectional area = 18 cm 2 air gap flux density = 1.2 T Determine the voltage E. Use magnetization curve shown in Fig. 1.5. Problem #1-6/5. To determine the voltage E coil

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Problem # 1-6/5

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Problem 1 6 5

Problem # 1-6/5

mean core length = 52 cm length of air gap = 0.14 cm

cross-sectional area = 18 cm2 air gap flux density = 1.2 T

Determine the voltage E.

Use magnetization curve shown in Fig. 1.5


Problem 1 6 51

Problem #1-6/5

  • To determine the voltage Ecoil

    • Find the current in the coil, Icoil

      • Ecoil=IcoilRcoil

  • To determine the current Icoil

    • Calculate the total mmf

    • Calculate the coil current


Problem 1 6 5 continued

Problem #1-6/5 continued

  • To determine F, calculate H


Problem 1 6 5 continued1

Problem #1-6/5 continued

  • To determine Hcore use Fig. 1.15

    • Hcore={1.15 oersteds}{79.577 A-t/m/oersted}

    • Hcore=91.5 A-t/m

  • Then calculate Fcore

    • Fcore=Hcorelcore

    • Fcore={91.5 A-t/m}{0.52 m}

    • Fcore=47.58 A-t


Problem 1 6 5 continued2

Problem #1-6/5 continued


Problem 1 6 5 continued3

Problem #1-6/5 continued

  • To determine Hgap

    • Hgap={1.2 Wb/m2}/{4πx10-7 Wb/A-t-m}

    • Hgap=955.4x103 A-t/m


Problem 1 6 5 continued4

Problem #1-6/5 continued

  • Calculating Fgap

    • Fgap=Hgaplgap

    • Fgap={955x103 A-t/m}{0.0014 m}

    • Fgap=1337 A-t

  • The total mmf

    • Ftotal=Fcore+Fgap

    • Ftotal={47.58+1337} A-t = 1384.58 A-t


Problem 1 6 5 continued5

Problem #1-6/5 continued

  • Calculate the coil current Icoil

  • Finally, the voltage


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