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Problem # 1-6/5. mean core length = 52 cm length of air gap = 0.14 cm cross-sectional area = 18 cm 2 air gap flux density = 1.2 T Determine the voltage E. Use magnetization curve shown in Fig. 1.5. Problem #1-6/5. To determine the voltage E coil

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problem 1 6 5
Problem # 1-6/5

mean core length = 52 cm length of air gap = 0.14 cm

cross-sectional area = 18 cm2 air gap flux density = 1.2 T

Determine the voltage E.

Use magnetization curve shown in Fig. 1.5

problem 1 6 51
Problem #1-6/5
  • To determine the voltage Ecoil
    • Find the current in the coil, Icoil
      • Ecoil=IcoilRcoil
  • To determine the current Icoil
    • Calculate the total mmf
    • Calculate the coil current
problem 1 6 5 continued
Problem #1-6/5 continued
  • To determine F, calculate H
problem 1 6 5 continued1
Problem #1-6/5 continued
  • To determine Hcore use Fig. 1.15
    • Hcore={1.15 oersteds}{79.577 A-t/m/oersted}
    • Hcore=91.5 A-t/m
  • Then calculate Fcore
    • Fcore=Hcorelcore
    • Fcore={91.5 A-t/m}{0.52 m}
    • Fcore=47.58 A-t
problem 1 6 5 continued3
Problem #1-6/5 continued
  • To determine Hgap
    • Hgap={1.2 Wb/m2}/{4πx10-7 Wb/A-t-m}
    • Hgap=955.4x103 A-t/m
problem 1 6 5 continued4
Problem #1-6/5 continued
  • Calculating Fgap
    • Fgap=Hgaplgap
    • Fgap={955x103 A-t/m}{0.0014 m}
    • Fgap=1337 A-t
  • The total mmf
    • Ftotal=Fcore+Fgap
    • Ftotal={47.58+1337} A-t = 1384.58 A-t
problem 1 6 5 continued5
Problem #1-6/5 continued
  • Calculate the coil current Icoil
  • Finally, the voltage
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