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Lesson Objective Calculate the concentration of solutions in units of molarityPowerPoint Presentation

Lesson Objective Calculate the concentration of solutions in units of molarity

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- Calculate the concentration of solutions in units of molarity
- Calculate the dilution of solutions in units of molarity

- Solutions are made in various concentrations
- Concentration depends on the amount of solute dissolved in a given amount of solvent
- Molarity (M) – number of moles of solute dissolved in one liter of the solution
- Units of mol/L or M
Ex) 2 mol/L = 2 M

- The higher the molarity, the more concentrated the solution

- Units of mol/L or M

- Molarity (M) – number of moles of solute dissolved in one liter of the solution

- Molarity

By Leridant[CC-BY-SA-2.5]

Decreasing Concentration

- Convert given units, if necessary, before plugging into the molarity equation
- Mass to moles
- Volume to liters

Ex) 2 M solution of NaOHdescribes a solution in which every liter of solution contains 2 moles of NaOH

- Calculating Molarity

- Write unknown and givens
V = 500. mL

m= 102 g

Molar mass = 58.44 g/mol

M = ?

- Identify the formula and rearrange, if needed

Ex) What is the concentration of a 500. mL salt solution containing 102 g of NaCl? (Molar mass of NaCl = 58.44 g/mol)

- Convert units and find intermediates, if needed
- Plug in and solve
- Make sure the answer is reasonable

What is the molarity of an aqueous solution containing 40.0 g of glucose (C6H12O6) in 1.5L of solution?

- Molarity Calculation

How many grams of NaOH are present in a 2.5 M solution?

- Molarity Calculation

- Dilution – process of decreasing the concentration of a solution by adding additional solvent
- Number of solute particles does not change, but the amount of solvent is increased
- Adding solvent increases the overall volume of the solution and decreases the concentration
- Inversely proportional relationship between concentration and volume of solvent in a solution

- Dilution

- Use the following equation when performing dilution calculations
- V1= volume of the original (stock) solution
- M1 = molarity of the original (stock) solution
- V2 = volume of the diluted solution
- M2 = molarity of the diluted solution

- Dilution Formula

- Dilution Calculation calculations

- Write unknown and givens
M1 = 2.0 M

V1 = 1.5 L

V2 = 4.0 L

M2 = ?

- Identify the formula and rearrange, if needed

Ex) A 2.0 M solution of acid is diluted by increasing its volume from 1.5 L to 4.0 L. Calculate the molarity of the new solution.

- Convert units and find intermediates, if needed
- Plug in and solve
5. Make sure the answer is reasonable

What volume of a 3.00 calculationsM KI stock solution would you use to make 0.300 L of a 1.25M KI solution?

- Dilution Calculation

- How many moles of solute are contained in 25 mL of 1.5 calculationsMCa(OH)2?

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