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Applications of Genetic AlgorithmsPowerPoint Presentation

Applications of Genetic Algorithms

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Applications of Genetic Algorithms

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Applications of Genetic Algorithms

Amy Hoover

- Software Bug Repair
- http://www.genetic-programming.org/hc2009/1-Forrest/Forrest-Presentation.pdf

- Weapon Design in Video Games
- gar.eecs.ucf.edu

- Radar coverage

- Problem: You want to mine the most gold in the least amount of time.
- What’s the best route?

B

C

A

E

D

- Problem: You want to mine the most gold in the least amount of time.
- What’s the best route?

4min

4min

B

C

A

5min

2min

2min

7min

3min

E

6min

D

4min

4min

B

C

A

5min

2min

2min

7min

3min

E

6min

D

Path 1: ABCDE

How long would this take?

Path 2: ABDEC

How long would this take?

4min

4min

B

C

A

2min

5min

2min

7min

3min

E

6min

D

Path 1: ABCDE

A-B = 4min, B-C = 4min, C-D = 3 min, D-E = 6 min

4 + 4 + 3 + 6 = 17 minutes to mine all the gold!

Path 2: ABDEC

(Class) How long would this take

4min

4min

B

C

A

5min

2min

2min

7min

3min

E

6min

D

Path 1: ABCDE

A-B = 4min, B-C = 4min, C-D = 3 min, D-E = 6 min

4 + 4 + 3 + 6 = 17 minutes to mine all the gold!

Path 2: ABDEC

A-B = 4min, B-D = 5min, D-E = 6 min, E-C = 7 min

4 + 5 + 6 + 7 = 22 minutes to mine all the gold

Which path is better?

- Search space grows enormously with each visited node
- nodeCount!

- Example GA
- http://dandeblasio.com/cot4810/

- How can we encode this using GAs?

- How can we encode this using GAs?
- Need chromosome!

- How can we encode this using GAs?
- Need chromosome!
- Path = ABCDE

- Then what?

- Need chromosome!

- How can we encode this using GAs?
- Need chromosome!
- Path = ABCDE

- Then what?
- Randomize the initial population!
- Path 1 = ABCDE
- Path 2 = ABCED
- Path 3 = ABECD
- Path 4 = AEBCD
- Path 5 = EABCD
…

- Randomize the initial population!
- Then what?

- Need chromosome!

- How can we encode this using GAs?
- Calculate the fitness of each individual
- Path 1 = ABCDE = ?
- Path 2 = ABCED = ?
- Path 3 = ABECD = ?
- Path 4 = AEBCD = ?
- Path 5 = EABCD = ?

- Calculate the fitness of each individual

- How can we encode this using GAs?
- Calculate the fitness of each individual
- Keep in mind we want to get the most gold in the LEAST amount of time so we can go do other fun stuff
- Path 1 = ABCDE = 17 minutes
- Path 2 = ABCED = 22 minutes
- Fitness = 100 – 22 = 78
- Path 3 = ABECD = 4 +2 + 7 + 3 = 16 minutes
- Path 4 = AEBCD = 2 + 2 +4 + 3 = 11 minutes
- Fitness = 100 - 11 = 89
- Path 5 = EABCD = 2 + 4 + 4 + 3 = 13 minutes

- How can we encode this using GAs?
- Calculate the fitness of each individual
- Keep in mind we want to get the most mithril in the LEAST amount of time so we can go do other fun stuff
- Path 1 = ABCDE = 17 minutes
- Path 2 = ABCED = 22 minutes
- Path 3 = ABECD = 4 +2 + 7 + 3 = 16 minutes
- Path 4 = AEBCD = 2 + 2 +4 + 3 = 11 minutes
- Path 5 = EABCD = 2 + 4 + 4 + 3 = 13 minutes

- Who should reproduce?
- Path 1 = ABCDE = 17 minutes
- Path 2 = ABCED = 22 minutes
- Path 3 = ABECD = 4 +2 + 7 + 3 = 16 minutes
- Path 4 = AEBCD = 2 + 2 +4 + 3 = 11 minutes
- Path 5 = EABCD = 2 + 4 + 4 + 3 = 13 minutes

- Problems Arise With Crossover (A doesn’t have 2 sets of gold!)
- “ABCDEF” “ABCFAE”
- “CDBFAE” “CDBDEF”

- 2 Options
- Modify Our Representation
- Modify Our Crossover Operator