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CIRCUITE NUMERICE

t n. t n+1. J n. K n. Q n. Q n+1. 0. 0. 0. 0. 0. 0. 1. 1. 0. 1. 0. 0. Q n+1 =Q n. Q n+1 =Q n. Q n+1 =0. Q n+1 =1. 0. 1. 1. 0. 1. 0. 0. 1. 1. 0. 1. 1. 1. 1. 0. 1. 1. 1. 1. 0. CIRCUITE NUMERICE. 1. III.1.2 CBB tip JK. III.1.2.1 CBB tip JK asincron.

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CIRCUITE NUMERICE

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  1. tn tn+1 Jn Kn Qn Qn+1 0 0 0 0 0 0 1 1 0 1 0 0 Qn+1=Qn Qn+1=Qn Qn+1=0 Qn+1=1 0 1 1 0 1 0 0 1 1 0 1 1 1 1 0 1 1 1 1 0 CIRCUITE NUMERICE 1 III.1.2 CBB tip JK III.1.2.1 CBB tip JK asincron Tabelul de adevăr: CURS NR. 9

  2. JnKn Qn JnKn Qn 00 00 01 01 11 11 10 10 0 0 0 1 0 1 1 0 0 1 Jn·Qn Qn+1= + Jn·Qn 1 1 0 1 0 1 0 1 0 1 + Kn·Qn CIRCUITE NUMERICE 2 Qn+1= Qn·Kn CURS NR. 9

  3. S J Q R K Q S J Q R K Q CIRCUITE NUMERICE 3 CURS NR. 9

  4. R J Q K Q Ck Ck S K J Q Q Presupunem Q=1 şi Q=0 R=1 R=0 Q=0 Q=1 S=0 S=1 Q=1 Q=0 CIRCUITE NUMERICE 4 J=K=Ck=1 CURS NR. 10

  5. Q Q’ R S J Q Q’ J J S Q Ck K R Q Ck Ck K K S’ S” R’ R” CIRCUITE NUMERICE 5 III.1.2.2 CBB JK master-slave Schema logică a CBB JK master-slave este următoarea: CURS NR. 10

  6. P1 Jn Kn Ck Qn+1 0 0  Qn P2 0 1  0 1 0  1 Q Q’ R S 1 1  Qn J Q Q’ J Ck Ck K K S’ R’ S” R” CIRCUITE NUMERICE 6 Tabelul de adevăr: CURS NR. 10

  7. P1 P2 Q Q’ R S J Q Q’ J Ck Ck K K S’ R’ S” R” CIRCUITE NUMERICE 7 CURS NR. 10

  8. P1 P2 Q Q’ R S J Q Q’ J Ck Ck K K S’ R’ S” R” CIRCUITE NUMERICE 8 CURS NR. 10

  9. T t T Ck Qn+1 T J S Q Ck K R Q Ck Ck 0  Qn t 1  Qn Q t CIRCUITE NUMERICE 9 III.1.3 CBB tip T CURS NR. 10

  10. D S Q Ck R Q R Q Ck S Q T Ck tn tn+1 Dn Qn Qn+1 0 0 0 0 1 0 1 0 1 1 1 1 CIRCUITE NUMERICE 10 III.1.4 CBB tip D Tabelul de adevăr: CURS NR. 10

  11. Dn Qn Rn Sn Jn Kn Qn+1 0 0 X 0 0 X 0 0 1 1 0 X 1 0 1 0 0 1 1 X 1 1 1 0 X X 0 1 Qn Dn 0 1 Qn Dn 0 1 D D K Q Ck J Q R Q Ck S Q Ck Ck 0 X 1 0 0 0 1 0 0 1 1 X Dn Dn Qn Dn 0 1 Qn Dn 0 1 0 X 1 0 0 X 1 X 0 1 1 X CIRCUITE NUMERICE 11 CBB RS în CBB D: Dn Rn= Sn= CBB JK în CBB D: Dn Kn= Jn= CURS NR. 10

  12. Jn Kn Qn Qn+1 Dn 0 0 0 0 J 0 0 1 1 ? D Q K 0 1 0 0 Ck Q 0 1 1 0 Ck 1 0 0 1 1 0 1 1 1 1 0 1 1 1 1 0 CBB dorit CBB existent CIRCUITE NUMERICE 12 III.1.5 Conversia CBB a) D în JK 0 1 0 0 1 1 1 0 CURS NR. 10

  13. JnKn Qn 00 01 11 10 0 0 0 1 1 Jn·Qn 1 1 0 0 1 J D Q K Ck Q Ck + Kn·Qn CIRCUITE NUMERICE 13 Dn= Schema de conversie: CURS NR. 10

  14. Dn Qn Qn+1 Tn 0 0 0 ? D T Q 0 1 0 Ck Q 1 0 1 Ck 1 1 1 Dn Qn 0 1 0 0 1 T Q D 1 1 0 Ck Q Ck Qn ·Dn + Qn ·Dn CIRCUITE NUMERICE 14 a) T în D Tabelul de adevăr: 0 1 1 0 Diagrama VK = DnQn Tn= CURS NR. 10

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