This presentation is the property of its rightful owner.
Sponsored Links
1 / 65

第十章 离散时间系统及卷积 PowerPoint PPT Presentation


  • 44 Views
  • Uploaded on
  • Presentation posted in: General

第十章 离散时间系统及卷积. 10.1 离散时间系统. 输入 si(n). 输出 so(n). 系统. 1 、离散系统的概念. 离散时间系统是指输入及输出信号均是离散信号的系统。. 系统 1. 输入. 输入. 输出. 系统 1. 系统 2. 系统 2. 系统 1. 系统 2. 输出. 输入. 系统 4. 系统 3. 2 、离散系统的互联. 输出. a. 系统的级联. b. 系统的并联. c. 系统的混联. 3 、离散时间系统的模型. 10.2 离散时间系统的分类. 1 、线性系统. 2 、时不变系统. 3 、因果系统.

Download Presentation

第十章 离散时间系统及卷积

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Presentation Transcript


6313916


6313916

10.1


6313916

si(n)

so(n)

1


6313916

1

1

2

2

1

2

4

3

2

a.

b.

c.


6313916

3


6313916

10.2


6313916

1


6313916

2


6313916

3


6313916

4


6313916

10.3


6313916

1

  • h(t)h(n)


6313916

2


6313916

3

h(n)

(n)

n

n

f(n)

T


6313916

s(t)

f(t)

h(n)f(0)

t

T

h(n-1)f(1)

f(n)h(n)

t

h(n-k)f(k)

t


6313916

  • -


6313916

4

  • s(n)h(n)= h(n) s(n)

  • s(n)[h1(n)+h2(n)]= s(n) h1(n)+ s(t) h2(n)


6313916

5


6313916

  • h(n)=(n)


6313916

10.4


6313916

1

1

2

h1(n)

h2(n)

h(n)

h(n)=h1(n)h2(n)


6313916

2

1

h1(n)

2

h2(n)

h(n)

h(n)=h1(n)+h2(n)


6313916

1

2

4

3

h(t)

3

h1(t)

h2(t)

h4(t)

h3(t)

h(t)={[h1(t)h2(t)]+ h3(t)} h4(t)


6313916

10.5


6313916

1


6313916


6313916

1

1

2

h1(n)

h2(n)

h(n)

h(n)=h1(n)h2(n)H()=H1()H2()


6313916

2

1

h1(n)

2

h2(n)

h(n)

h(n)=h1(n)+h2(n) H()=H1()+H2()


6313916

1

2

4

3

h(n)

3

h1(n)

h2(n)

h4(n)

h3(n)

h(n)={[h1(n)h2(n)]+ h3(n)} h4(n)

H()={H1()H2()+H3()} H4()


6313916

2


6313916


6313916


6313916

si(0)=2h(n)

si(n)

3

4

2

2

2

n

si(0)

si(1)

n

h(n)

si(1)=3h(n-1)

2

1

1

6

n

3

3

n

=2h(n)+3h(n-1)

8

7

3

2

n


6313916

3

  • h(n)


6313916

10.6


6313916

  • H()h(n)


10 7 dft

10.7 DFT


6313916

1

  • x(n)n=0,1,2,N-1<x(n-k)>N

<X(n-1)>N

<X(n-2)>N

X(n)

3

n

3

n

3

n

<X(n-4)>N

<X(n-3)>N

3

n

3

n


6313916

2

  • x(n)h(n)y(n)Y()=X()H()y(n)

  • Y(k)y(n)


6313916

  • FFTIFFT

  • x(n)h(n)n[0,N)(DFT)X(k)H(k) k[0,N)

  • Y(k)=X(k)H(k)

  • Y(k)(IDFT)y(n)


6313916

h(n)

3

n

3

n

n

3

[0,N-1]=

<h(n-1)>N

3

n


6313916

n

3

n

3

n

n

3

3

[0,N-1]=

<h(n-2)>N

[0,N-1]=

<h(n-m)>N


6313916

  • Kh(n)Lx(n)y(n)

  • K+L-1


6313916

h(n)=[1,2,3,4]

h(0-m)

3

n

3

m

x(n)=[1,2,2,1]

x(m)

3

n

3

m


6313916

h(1-m)

3

m

x(m)

3

m


6313916

  • y(n)=[1,4,9,15,16,11,4]7


6313916

<h(0-m)>N

3

m

x(m)

3

m


6313916

  • <h(0-m)>N

h(m)

<h(0-m)>N

<h(n-m)>N

3

m

<h(0-m)>N

h(-m)

0~N-1

3

m

3

m

3

m


6313916

<h(1-m)>N

3

m

x(m)

3

m


6313916

  • y(n)=[17,15,13,15]y(n)

  • y(n)=y(n)??

  • Kx(n)Lh(n)0K+L-1


6313916

h(n)=[1,2,3,4,0,0,0]

0

7

n

x(n)=[1,2,2,1, 0,0,0]

7

n


6313916

<h(0-m)>N

7

m

x(m)

<h(0-m)>N

7

m


6313916

<h(1-m)>N

7

m

x(m)

7

m


6313916

  • y(n)=[1,4,9,15,16,11,4]=y(n)

  • Kx(n)Lh(n)K+L-1

    X(k)H(k)

    X(k)H(k)Y(k)

    Y(k)y(n)


6313916

  • K+L-12MK+L-1K+L-122K+L-1

  • FFTIFFT


6313916

Kx(n)Lh(n)K+L-12M

FFTX(k)H(k)

X(k)H(k)Y(k)

Y(k)IFFTy(n)


6313916

10.8


6313916


6313916

  • 02


  • Login