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-2,820 -2,795 -188 -2,818 -2,828 -2,824

Find an approximation to {image} Use a double Riemann sum with m = n = 2 and the sample point in the lower left corner to approximate the double integral, where {image}. -2,820 -2,795 -188 -2,818 -2,828 -2,824.

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-2,820 -2,795 -188 -2,818 -2,828 -2,824

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  1. Find an approximation to {image} Use a double Riemann sum with m = n = 2 and the sample point in the lower left corner to approximate the double integral, where {image} • -2,820 • -2,795 • -188 • -2,818 • -2,828 • -2,824

  2. Let V be the volume of the solid that lies under the graph of {image} and above the rectangle given by {image} We use the lines x = 0 and y = 2 to divide R into subrectangles. Find the Riemann sum using lower left corners. Select the correct answer. The choices are rounded to the nearest hundredth. • 83.42 • 31.46 • 10.34 • 114.75 • 10.3

  3. Evaluate the double integral by first identifying it as the volume of a solid. {image} {image} • 180 • 5,040 • -118 • 90

  4. Use the Midpoint Rule with one square of to estimate {image} where {image} Use 2.72 to approximate e. • 0.000092 • 0.548132 • 0.274066 • 0 • 0.924334

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