1 / 5

s MSK (t) =

s MSK (t) =.  k = 0 or  depending on whether m I (t) = +1 to -1 s MSK (t) has constant amplitude to ensure phase continuity at bit interval  select f c = ; n integer. f c -. and. f c +. MSK waveform - as a special case of CPFSK.

Download Presentation

s MSK (t) =

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. sMSK(t) = • k= 0 or depending on whether mI(t) = +1 to -1 • sMSK(t) has constant amplitude • to ensure phase continuity at bit interval  selectfc = ; n integer • fc - and • fc + MSK waveform - as a special case of CPFSK MSK is FSK signal with binary signaling frequencies given by • phase of MSK varies linearly over Tb

  2. sMSK(t) = • Let mI(t) mQ(t) = dk • Possible values for dk ? • k(t) = k - dk t/ 2T • For phase continuity from kT to (k+1)T,  = k+1(t) - k(t) = k+1 – dk+1 t/ 2T – [ k - dk t/ 2T ] = k+1 – k - (t/ 2T).[ dk+1 - dk ] • [ dk+1 - dk ]  0, +2, -2

  3. Phase Continuity of MSK h = ½ θ(t) = θ(0) ± 0 ≤ t ≤ T θ(t) can take on only 2 values at odd or even multiples of T t =even multiple of T θ(T) - θ(0)= πor 0 t = odd multiple of Tθ(T) - θ(0)= ± π/2 assuming θ(0) = 0

  4. π π/2 0 -π/2 -π θ(t) - (0) 1 0 0 1 1 1 0 0 2T 4T 6T t Phase Trellis: path depicts θ(t) corresponding to a binary sequence • for h = ½ ΔF = Rb/4 • minimum ΔF for two binary FSK signals • to be coherently orthogonal • e.g. if Rb = 100Mbps  = ΔF = 25MHz

More Related