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Chapter 10 Review

Find the area of the Base. Round to the nearest tenth, if necessary.

Chapter 10 Review

What is the area of the Base? Round to the nearest tenth, if necessary.

B = 9.1 x 8 = 72.8in²

Chapter 10 Review

Find the volume. Round to the nearest tenth, if necessary.

Chapter 10 Review

Find the volume. Round to the nearest tenth, if necessary.

V = lwh

V = 9.1x 8 x 8 = 582.4in³ or

V = Bh = 72.8 · 8 = 582.4in³

Chapter 10 Review

Find the area of the Base. Round to the nearest tenth, if necessary.

Chapter 10 Review

Find the area of the Base. Round to the nearest tenth, if necessary.

B = 18 x 9 = 162mm²

Chapter 10 Review

Find the volume. Round to the nearest tenth, if necessary.

Chapter 10 Review

Find the volume. Round to the nearest tenth, if necessary.

V = lwh

V = 18 x 9 x 36 = 5832mm³ or

V = Bh = 162 · 36 = 5832mm³

Chapter 10 Review

Find the area of the Base. Round to the nearest tenth, if necessary.

Chapter 10 Review

Find the area of the Base. Round to the nearest tenth, if necessary.

B = 10 x 6 ÷ 2 = 30cm²

Chapter 10 Review

Find the volume. Round to the nearest tenth, if necessary.

Chapter 10 Review

Find the volume. Round to the nearest tenth, if necessary.

V = lwh ÷ 2

V = 10 x 6 x 4 ÷ 2 = 120cm³ or

V = Bh = 30 · 4 = 120cm³

Chapter 10 Review

Find the Area of the Base. Round to the nearest tenth, if necessary.

Chapter 10 Review

Find the Area of the Base. Round to the nearest tenth, if necessary.

B = 3 x 4 ÷ 2 = 6cm²

Chapter 10 Review

Find the volume. Round to the nearest tenth, if necessary.

Chapter 10 Review

Find the volume. Round to the nearest tenth, if necessary.

V = lwh ÷ 2

V = 4x 3 x 8 ÷ 2 = 48cm³ or

V = Bh = 6 · 8 = 48cm³

Chapter 10 Review

Find the surface area. Round to the nearest tenth, if necessary.

Chapter 10 Review

Find the surface area. Round to the nearest tenth, if necessary.

A = 7 x 4 = 28

A = 4 x 10 = 40

A = 10 x 7 = 70

28 + 28 + 40 + 40 + 70 + 70 =276in²

Chapter 10 Review

Find the surface area. Round to the nearest tenth, if necessary.

Chapter 10 Review

Find the surface area. Round to the nearest tenth, if necessary.

SA = 2B + hp

B = 72.8

h = 8

p = 34.2

SA = 2 x 72.8 + 8 x 34.2 =

= 145.6 + 273.6 = 419.2in²

Chapter 10 Review

Find the surface area. Round to the nearest tenth, if necessary.

Chapter 10 Review

Find the surface area. Round to the nearest tenth, if necessary.

SA = 2B + hp

B = 162

h= 36

p = 54

SA = 2 x 162 + 36 x 54 =

= 324 + 1944 = 2268mm²

Chapter 10 Review

Find the surface area. Round to the nearest tenth, if necessary.

Chapter 10 Review

Find the surface area. Round to the nearest tenth, if necessary.

SA = 2B + hp

B = 3 x 4 ÷ 2 = 6

h= 8

p = 12

SA = 2 x 6 + 8 x 12 =

= 12 + 96 = 108cm²

Chapter 10 Review

Find the surface area. Round to the nearest tenth, if necessary.

Chapter 10 Review

Find the surface area. Round to the nearest tenth, if necessary.

SA = 2B + hp

B = 10 x 6 ÷ 2 = 30

h= 4

p = 25.6

SA = 2 x 30 + 4 x 25.6 =

= 60 + 102.4 = 162.4cm²

Chapter 10 Review

A special box designed to hold an antique artifact is shaped like a triangular prism. The height of the box is 6.9 inches, the length is 8 inches and the width is 7.1 inches. What is the volume of box?

Chapter 10 Review

A special box designed to hold an antique artifact is shaped like a triangular prism. The height of the box is 6.9 inches, the length is 8 inches and the width is 7.1 inches. What is the volume of box?

V = lwh ÷ 2

V = 8x 7.1 x 6.9 ÷ 2 = 195.96in³

Chapter 10 Review

There is a sale at the candy store. They have two containers that can be filled with candy and they are the same price. One container is 5in by 6in by 9in. The other container is 4in by 8in by 8in. Which container would hold more candy?

Chapter 10 Review

There is a sale at the candy store. They have two containers that can be filled with candy and they are the same price. One container is 5in by 6in by 9in. The other container is 4in by 8in by 8in. Which container would hold more candy?

V = lwh

V₁ = 5 x 6 x 9= 270in³

V₂ = 4 x 8 x 8 = 256in³

Chapter 10 Review

You are painting a room that is a rectangular prism and is 20ft by 35ft and 10ft high. You are painting the walls, floor and ceiling. A gallon of paint will cover 1250ft². How many gallons will you need?

Chapter 10 Review

You are painting a room that is a rectangular prism and is 20ft by 35ft and 10ft high. You are painting the walls, floor and ceiling. A gallon of paint will cover 1250ft². How many gallons will you need?

SA = 2B + hp

B = 20 · 35 = 700

h = 10

p = 20+35+20+35=110

SA = 2 x 700 + 110 x 10 = 2500ft²

2500 ÷ 1250 = 2 gallons

Chapter 10 Review

Formulas you will need to have memorized for tomorrow:

Volume of a rectangular prism

V = lwh and V = Bh

Volume of a triangular prism

V = lwh ÷ 2 and V = Bh

Surface Area of a prism

SA = 2B + hp

Chapter 10 Review

Agenda Notes

Homework –

Chapter 10 Review Homework-

(extra credit for 4th period)

Due Wednesday, Feb 26

Chapter 10 Test - Wednesday, Feb 26

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