Loading in 5 sec....

2.5 Apply the Remainder and Factor Theorems p. 120PowerPoint Presentation

2.5 Apply the Remainder and Factor Theorems p. 120

- 129 Views
- Uploaded on

Download Presentation
## PowerPoint Slideshow about ' 2.5 Apply the Remainder and Factor Theorems p. 120' - carter-morse

**An Image/Link below is provided (as is) to download presentation**

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Presentation Transcript

### 2.5 Apply the Remainder and Factor Theorems p. 120

How do you divide polynomials?

What is the remainder theorem?

What is the difference between synthetic substitution and synthetic division?

What is the factor theorem?

When you divide a Polynomial f(x) by a divisor d(x), you get a quotient polynomial q(x) with a remainder r(x) written:f(x) = q(x) + r(x)d(x) d(x)

Polynomial Long Division: the divisor!

- You write the division problem in the same format you would use for numbers. If a term is missing in standard form …fill it in with a 0 coefficient.
- Example:
- 2x4 + 3x3 + 5x – 1 =
- x2 – 2x + 2

2x the divisor!2

+7x

+10

-( )

2x4

-4x3

+4x2

7x3

- 4x2

+5x

-( )

7x3 - 14x2 +14x

10x2 - 9x

-1

7x3 = 7x

x2

-( )

10x2 - 20x +20

11x - 21

remainder

The answer is written: the divisor!

- 2x2 + 7x + 10 + 11x – 21 x2 – 2x + 2
- Quotient + Remainder over divisor

Now you try one! the divisor!

- y4 + 2y2 – y + 5 = y2 – y + 1
- Answer: y2 + y + 2 + 3 y2 – y + 1

2. the divisor!(x3–x2 + 4x – 10) (x + 2)

SOLUTION

Write polynomial division in the same format you use when dividing numbers. Include a “0” as the coefficient of x2 in the dividend. At each stage, divide the term with the highest power in what is left of the dividend by the first term of the divisor. This gives the next term of the quotient.

quotient the divisor!

)

x + 2

x3 – x2 + 4x – 10

x3 + 2x2

– 3x2– 6x

10x + 20

remainder

x2 – 3x + 10

Multiply divisor byx3/x = x2.

Subtract. Bring down next term.

–3x2 + 4x

Multiply divisor by –3x2/x= –3x.

Subtract. Bring down next term.

10x – 1

Multiply divisor by10x/x = 10.

– 30

Use Synthetic Division the divisor!

- (x3–x2 + 4x – 10) (x + 2)
- Set x + 2 = 0.
- Solve for x x = −2
- Use − 2 as the divisor for synthetic division which is the same as synthetic substitution.
- Synthetic division can be used to divide any polynomial by a divisor of the form “x −k”

Remainder Theorem: the divisor!

- If a polynomial f(x) is divisible by (x – k), then the remainder is r = f(k).
- Now you will use synthetic division (like synthetic substitution)
- f(x)= 3x3 – 2x2 + 2x – 5
- Divide by x - 2

– 2 the divisor!1 −1 4 −10

– 2 6 – 20

1 – 3 10 – 30

ANSWER

SOLUTION

F(x) = x3–x2 + 4x – 10 (x + 2)

f(x)= 3x the divisor!3 – 2x2 + 2x – 5 Divide by x - 2

- Long division results in ?......
- 3x2 + 4x + 10 + 15 x – 2
- Synthetic Division:
- f(2) = 3 -2 2 -5 2

6

8

20

3

4

10

15

Which gives you:

+ 15

x-2

3x2

+ 10

+ 4x

Synthetic Division the divisor!

- Divide x3 + 2x2 – 6x -9 by (a) x-2 (b) x+3
- (a) x-2
- 1 2 -6 -9 2

8

4

2

1

4

2

-5

Which is x2 + 4x + 2 + -5 x-2

Factor Theorem: the divisor!

- A polynomial f(x) has factor x-k if f(k)=0
- note that k is a ZERO of the function because f(k)=0

Factoring a polynomial the divisor!

- Factor f(x) = 2x3 + 11x2 + 18x + 9
- Given f(-3)=0
- Since f(-3)=0
- x-(-3) or x+3 is a factor
- So use synthetic division to find the others!!

Factoring a polynomial cont. the divisor!

- 2 11 18 9
- -3

-15

-9

-6

2

5

3

0

So…. 2x3 + 11x2 + 18x + 9 factors to:

(x + 3)(2x2 + 5x + 3)

Now keep factoring-- gives you:

(x+3)(2x+3)(x+1)

4 the divisor! 1 – 6 512

4– 8 –12

1 – 2 – 3 0

Your Turn…Factor the polynomial completely given that x –4 is a factor.

f (x) = x3– 6x2 + 5x + 12

SOLUTION

Because x – 4 is a factor of f (x), you know that f (4)= 0. Use synthetic division to find the other factors.

Use the result to write the divisor!f (x) as a product of two factors and then factor completely.

f (x) = x3– 6x2+ 5x + 12

Write original polynomial.

= (x – 4)(x2– 2x – 3)

Write as a product of two

factors.

= (x – 4)(x –3)(x + 1)

Factor trinomial.

Your turn! the divisor!

- Factor f(x)= 3x3 + 13x2 + 2x -8
- given f(-4)=0
- (x + 1)(3x – 2)(x + 4)

Finding the zeros of a polynomial function the divisor!

- f(x) = x3 – 2x2 – 9x +18.
- One zero of f(x) is x=2
- Find the others!
- Use synthetic div. to reduce the degree of the polynomial function and factor completely.
- (x-2)(x2-9) = (x-2)(x+3)(x-3)
- Therefore, the zeros are x=2,3,-3!!!

Your turn! the divisor!

- f(x) = x3 + 6x2 + 3x -10
- X=-5 is one zero, find the others!
- The zeros are x=2,-1,-5
- Because the factors are (x-2)(x+1)(x+5)

- How do you divide polynomials? the divisor!
By long division

- What is the remainder theorem?
If a polynomial f(x) is divisible by (x – k), then the remainder is r = f(k).

- What is the difference between synthetic substitution and synthetic division?
It is the same thing

- What is the factor theorem?
If there is no remainder, it is a factor.

Assignment the divisor!

Page 124, 7, 9, 11-15 odd, 21-23 odd, 29-33 odd, 35- 37 all

Download Presentation

Connecting to Server..