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2.5 Apply the Remainder and Factor Theorems p. 120. How do you divide polynomials? What is the remainder theorem? What is the difference between synthetic substitution and synthetic division? What is the factor theorem?.

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2.5 Apply the Remainder and Factor Theorems p. 120

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2 5 apply the remainder and factor theorems p 120

2.5 Apply the Remainder and Factor Theorems p. 120

How do you divide polynomials?

What is the remainder theorem?

What is the difference between synthetic substitution and synthetic division?

What is the factor theorem?


2 5 apply the remainder and factor theorems p 120

When you divide a Polynomial f(x) by a divisor d(x), you get a quotient polynomial q(x) with a remainder r(x) written:f(x) = q(x) + r(x)d(x) d(x)


The degree of the remainder must be less than the degree of the divisor

The degree of the remainder must be less than the degree of the divisor!


Polynomial long division

Polynomial Long Division:

  • You write the division problem in the same format you would use for numbers. If a term is missing in standard form …fill it in with a 0 coefficient.

  • Example:

  • 2x4 + 3x3 + 5x – 1 =

  • x2 – 2x + 2


2 5 apply the remainder and factor theorems p 120

2x2

2x4 = 2x2

x2


2 5 apply the remainder and factor theorems p 120

2x2

+7x

+10

-( )

2x4

-4x3

+4x2

7x3

- 4x2

+5x

-( )

7x3 - 14x2 +14x

10x2 - 9x

-1

7x3 = 7x

x2

-( )

10x2 - 20x +20

11x - 21

remainder


The answer is written

The answer is written:

  • 2x2 + 7x + 10 + 11x – 21 x2 – 2x + 2

  • Quotient + Remainder over divisor


Now you try one

Now you try one!

  • y4 + 2y2 – y + 5 =y2 – y + 1

  • Answer: y2 + y + 2 + 3 y2 – y + 1


2 5 apply the remainder and factor theorems p 120

2. (x3–x2 + 4x – 10)  (x + 2)

SOLUTION

Write polynomial division in the same format you use when dividing numbers. Include a “0” as the coefficient of x2 in the dividend. At each stage, divide the term with the highest power in what is left of the dividend by the first term of the divisor. This gives the next term of the quotient.


2 5 apply the remainder and factor theorems p 120

quotient

)

x + 2

x3 – x2 + 4x – 10

x3 + 2x2

– 3x2– 6x

10x + 20

remainder

x2 – 3x + 10

Multiply divisor byx3/x = x2.

Subtract. Bring down next term.

–3x2 + 4x

Multiply divisor by –3x2/x= –3x.

Subtract. Bring down next term.

10x – 1

Multiply divisor by10x/x = 10.

– 30


2 5 apply the remainder and factor theorems p 120

ANSWER

x3 – x2 +4x – 10

– 30

= (x2 – 3x +10)+

x + 2

x + 2

OR…


Use synthetic division

Use Synthetic Division

  • (x3–x2 + 4x – 10)  (x + 2)

  • Set x + 2 = 0.

  • Solve for xx = −2

  • Use − 2 as the divisor for synthetic division which is the same as synthetic substitution.

  • Synthetic division can be used to divide any polynomial by a divisor of the form “x −k”


Remainder theorem

Remainder Theorem:

  • If a polynomial f(x) is divisible by (x – k), then the remainder is r = f(k).

  • Now you will use synthetic division (like synthetic substitution)

  • f(x)= 3x3 – 2x2 + 2x – 5

  • Divide by x - 2


2 5 apply the remainder and factor theorems p 120

– 21 −1 4 −10

– 2 6 – 20

1 – 3 10 – 30

ANSWER

SOLUTION

F(x) = x3–x2 + 4x – 10  (x + 2)


F x 3x 3 2x 2 2x 5 divide by x 2

f(x)= 3x3 – 2x2 + 2x – 5 Divide by x - 2

  • Long division results in ?......

  • 3x2 + 4x + 10 + 15 x – 2

  • Synthetic Division:

  • f(2) = 3-22-52

6

8

20

3

4

10

15

Which gives you:

+ 15

x-2

3x2

+ 10

+ 4x


Synthetic division

Synthetic Division

  • Divide x3 + 2x2 – 6x -9 by (a) x-2 (b) x+3

  • (a) x-2

  • 12-6-9 2

8

4

2

1

4

2

-5

Which is x2 + 4x + 2 + -5 x-2


Synthetic division practice cont

Synthetic Division Practice cont.

  • (b) x+3

  • 12-6-9 -3

3

9

-3

1

-1

-3

0

x2 – x - 3


Factor theorem

Factor Theorem:

  • A polynomial f(x) has factor x-k if f(k)=0

  • note that k is a ZERO of the function because f(k)=0


Factoring a polynomial

Factoring a polynomial

  • Factor f(x) = 2x3 + 11x2 + 18x + 9

  • Given f(-3)=0

  • Since f(-3)=0

  • x-(-3) or x+3 is a factor

  • So use synthetic division to find the others!!


Factoring a polynomial cont

Factoring a polynomial cont.

  • 211189

  • -3

-15

-9

-6

2

5

3

0

So…. 2x3 + 11x2 + 18x + 9 factors to:

(x + 3)(2x2 + 5x + 3)

Now keep factoring-- gives you:

(x+3)(2x+3)(x+1)


Your turn

4 1 – 6 512

4– 8 –12

1 – 2 – 3 0

Your Turn…

Factor the polynomial completely given that x –4 is a factor.

f (x) = x3– 6x2 + 5x + 12

SOLUTION

Because x – 4 is a factor of f (x), you know that f (4)= 0. Use synthetic division to find the other factors.


2 5 apply the remainder and factor theorems p 120

Use the result to write f (x) as a product of two factors and then factor completely.

f (x) = x3– 6x2+ 5x + 12

Write original polynomial.

= (x – 4)(x2– 2x – 3)

Write as a product of two

factors.

= (x – 4)(x –3)(x + 1)

Factor trinomial.


Your turn1

Your turn!

  • Factor f(x)= 3x3 + 13x2 + 2x -8

  • given f(-4)=0

  • (x + 1)(3x – 2)(x + 4)


Finding the zeros of a polynomial function

Finding the zeros of a polynomial function

  • f(x) = x3 – 2x2 – 9x +18.

  • One zero of f(x) is x=2

  • Find the others!

  • Use synthetic div. to reduce the degree of the polynomial function and factor completely.

  • (x-2)(x2-9) = (x-2)(x+3)(x-3)

  • Therefore, the zeros are x=2,3,-3!!!


Your turn2

Your turn!

  • f(x) = x3 + 6x2 + 3x -10

  • X=-5 is one zero, find the others!

  • The zeros are x=2,-1,-5

  • Because the factors are (x-2)(x+1)(x+5)


2 5 apply the remainder and factor theorems p 120

  • How do you divide polynomials?

    By long division

  • What is the remainder theorem?

    If a polynomial f(x) is divisible by (x – k), then the remainder is r = f(k).

  • What is the difference between synthetic substitution and synthetic division?

    It is the same thing

  • What is the factor theorem?

    If there is no remainder, it is a factor.


Assignment

Assignment

Page 124, 7, 9, 11-15 odd, 21-23 odd, 29-33 odd, 35- 37 all


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