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Mechanics of Materials – MAE 243 (Section 002) Spring 2008

Mechanics of Materials – MAE 243 (Section 002) Spring 2008. Dr. Konstantinos A. Sierros. General info. M, W, F 8:00-8:50 A.M. at Room G-83 ESB Office: Room G-19 ESB E-mail: kostas.sierros@mail.wvu.edu Tel: 304-293-3111 ext.2310

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Mechanics of Materials – MAE 243 (Section 002) Spring 2008

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  1. Mechanics of Materials – MAE 243 (Section 002) Spring 2008 Dr. Konstantinos A. Sierros

  2. General info • M, W, F 8:00-8:50 A.M. at Room G-83 ESB • Office: Room G-19 ESB • E-mail: kostas.sierros@mail.wvu.edu • Tel: 304-293-3111 ext.2310 • Course notes: http://www.mae.wvu.edu/~cairns/teaching.html • USER NAME: cairns PASSWORD: materials • Facebook : Konstantinos Sierros (using courses: Mechanics of Materials) • Office hours: M, W 9:00-10:30 A.M. or by appointment

  3. Course textbook Mechanics of Materials, 6th edition, James M. Gere, Thomson, Brooks/Cole, 2006

  4. Why do we study Mechanics of Materials? Anyone concerned with the strength and physical performance of natural/man-made structures should study Mechanics of Materials

  5. Why do we study Mechanics of Materials? SAFETY and COST !!

  6. Structural integrity of materials is important…

  7. 1.1: Introduction to Mechanics of Materials Definition: Mechanics of materials is a branch of applied mechanics that deals with the behaviour of solid bodies subjected to various types of loading Compression   Tension (stretched)   Bending   Torsion (twisted)       Shearing

  8. 1.1: Introduction to Mechanics of Materials • Fundamental concepts • stress and strain • deformation and displacement • elasticity and inelasticity • load-carrying capacity Design and analysis of mechanical and structural systems

  9. 1.1: Introduction to Mechanics of Materials • Examination of stresses and strains inside real bodies of finite dimensions that deform under loads • In order to determine stresses and strains we use: • Physical properties of materials • Theoretical laws and concepts

  10. Problem solving • Draw the free-body diagram • Check your diagram • Calculate the unknowns • Check your working • Compute the problem • Check your working • Write the solution • Check your working

  11. Free body diagrams I

  12. Free body diagrams II

  13. Statics example 4 3 2m 200kN A steel beam with a tensile strength of 700 MPA is loaded as shown. Assuming that the beam is made from hollow square tubing with the dimensions shown will the loading in the x direction exceed the failure stress? 0.01m 0.02m

  14. Step 1: Free body diagram 4 3 2m 240kN.m 200kN 120N 160kN 160kN 120kN

  15. Step 2: Calculate moment of inertia I=1/12 x (0.024)- 1/12 x (0.014) m4 =1.25 x 10-8 m4 A=0.022-0.012 m2 =0.0003 m2 0.01m 0.02m 0.02m

  16. Step 3: Shear and moment diagrams 4 3 V 2m 120 200kN x M x -240

  17. Step 4: Calculation of maximum tensile stress • Stress due to axial loading • Stress due to bending • ANS: Total stress greater than failure stress therefore failure will occur

  18. Key to success Ask questions and seek help if you feel like it!!!

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