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Parallel Lines and Proportional PartsPowerPoint Presentation

Parallel Lines and Proportional Parts

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## PowerPoint Slideshow about ' Parallel Lines and Proportional Parts' - camden-davenport

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### Parallel Lines and Proportional Parts

Section 7.4

Proportional parts of triangles

- Non parallel transversals that intersect parallel lines can be extended to form similar triangles.
- So, the sides of the triangles are proportional.

Side Splitter Theorem or Triangle Proportionality Theorem

- If a line is parallel to one side of a triangle and intersects the other two sides, it divides those two sides proportionally.
- If BE || CD, then

AB||ED, BD = 8, DC = 4, and AE = 12.

- Find EC
- by ?
- EC = 6

UY|| VX, UV = 3, UW = 18, XW = 16.

- Find YX.
- YX = 3.2

Converse of Side Splitter

- If a line intersects the other two sides and separates the sides into corresponding segments of proportional lengths, then the line is parallel to the third side.
- If
- then BE || CD

Determine if GH || FE. Justify

- In triangle DEF, DH = 18, and HE = 36, and DG = ½ GF.
- To show GH || FE,
- Show
- Let GF = x, then DG = ½ x.

- Substitute
- Simplify
- Simplify

Triangle Midsegment Theorem

- A midsegment of a triangle is parallel to one side of the triangle, and its length is one-half the length of that side.
- If D and E are mid-
- Points of AB and AC,
- Then DE || BC and
- DE = ½ BC

Example

- Triangle ABC has vertices A(-2,2), B(2, 4) and C(4,-4). DE is the midsegment of triangle ABC.
- Find the coordinates of D and E.
- D midpt of AB
- D(0,3)

- E midpt of AC
- E(1, -1)
- Part 2 - Verify BC || DE
- Do this by finding slopes
- Slope of BC = -4 and slope of DE = -4
- BC || DE

- Part 3 – Verify DE = ½ BC
- To do this use the distance formula
- BC = which simplifies to
- DE =
- DE = ½ BC

Corollaries of side splitter thm.

- 1. If three or more parallel lines intersect two transversals, then they cut off the transversals proportionally.

- If three or more parallel lines cut off congruent segments on one transversal, then they cut off congruent segments on every transversal.

Examples on one transversal, then they cut off congruent segments on every transversal.

- 1. In the figure, Larch, Maple, and Nutthatch Streets are all parallel. The figure shows the distance between city blocks. Find x.

- Find x and y. on one transversal, then they cut off congruent segments on every transversal.
- Given: AB = BC
- 3x + 4 = 6 – 2x
- X = 2
- Use the 2nd corollary to say DE = EF
- 3y = 5/3 y + 1
- Y = ¾

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