drill calculate the ph of 0 10 m h 2 z in 0 50 m khz k a1 2 0 x 10 5 k a2 5 0 x 10 9
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Drill: Calculate the pH of 0.10 M H 2 Z in 0.50 M KHZ. K a1 = 2.0 x 10 -5 K a2 = 5.0 x 10 -9

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Drill: Calculate the pH of 0.10 M H 2 Z in 0.50 M KHZ. K a1 = 2.0 x 10 -5 K a2 = 5.0 x 10 -9 - PowerPoint PPT Presentation


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Drill: Calculate the pH of 0.10 M H 2 Z in 0.50 M KHZ. K a1 = 2.0 x 10 -5 K a2 = 5.0 x 10 -9. Hydrolysis Reactions. Hydrolysis. Any reaction in which water is decomposed with all or part of its decomposition portions combining with the products. Hydrolysis.

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hydrolysis
Hydrolysis

Any reaction in which water is decomposed with all or part of its decomposition portions combining with the products

slide4

Hydrolysis

Water is added to decompose something

slide5

Hydrolysis

MX + HOH

HX + MOH

salts1
Salts
  • Ionic compounds that dissolve ~ 100 % in water
slide8

Salts of Acids

  • Salts of acids are negative

(A-)

slide9

Salts of Bases

  • Salts of bases are Positive

(M+ or B+)

slide10

Salt Solutions

  • When salts dissolve, their ions can recombine with water
salt solutions
Salt Solutions
  • The salts of weak acids can recombine with water producing basic solutions
slide12

Salt Solutions

  • The salts of weak bases can recombine with water producing acidic solutions
slide13

Salt Solutions

  • A- + H2O HA + OH-
  • B+ + H2O H+ + BOH
slide14
Drill: Calculate the salt/acid ratio of a solution of benzoic acid & sodium benzoate at a pH of 5.00.KaHBz = 6.4 x 10-5
slide17

Salt Problem

  • Calculate the pH of a 0.20 M solution of NaBz
  • Ka = 6.4 x 10-5
slide18

Salt Problem

  • Calculate the pH of a 0.10 M solution of R-NH3Cl
  • Kb = 2.5 x 10-5
slide19

Drill:

Calculate the pH of a 0.18 M solution of KC2H3O2

  • Ka = 1.8 x 10-5
ap chm hw
AP CHM HW
  • Read: Chapter 14
  • Problems: 43
  • Page: 422
slide21

CHM II HW

  • Read: Chapter 18
  • Problems: 83
  • Page: 790
slide22

Drill:

Calculate the pH of a 0.16 M solution of KC7H5O2

  • Ka = 6.4 x 10-5
slide24

Salt Applications

  • Salts of strong acids & weak bases make acidic solutions
slide25

Salt Applications

  • Salts of strong bases & weak acids make basic solutions
slide26

Salt Applications

  • Salts of strong acids & strong bases make neutral solutions
slide27

Predict Relative pH

  • NaAc MnCl2
  • KNO3 NH4Br
  • KHSO4 NH4Ac
slide28

Predict Relative pH

  • KAc NaCl
  • KClO2 NH4Cl
  • K2SO4 NaI
slide29

Anhydrides

  • Compounds without water; that when added to water, form other compounds
slide30

Acid Anhydrides

  • Non-metal oxides that form acids when added to water
slide31

Basic Anhydrides

  • Metal oxides that form bases when added to water
slide32

Predict Relative pH

  • Na2O SO2
  • NO2 CO2
  • CaO Al2O3
ap chm hw1
AP CHM HW
  • Read: Chapter 14
  • Problems: 35
  • Page: 422
slide35

CHM II HW

  • Read: Chapter 18
  • Problems: 67 & 75
  • Page: 789-790
ap test
AP Test
  • Thursday
slide39

11.2 g of KOH was added to 2.0 L of 0.075 M H2CO3. Calculate the molarity of all ions present in the solution.Ka1 = 4.4 x 10-7Ka2 = 4.8 x 10-11

slide40

You need to make a buffer solution with its greatest buffering capacity at pH ~ 5.4. In general terms, describe what acid or base you would chose, & how you would make the buffer.

slide42

Calculate [H3PO4], [H2PO4-1], [HPO4-2], [PO4-3], [K+], [H+], & pH of 1.0 M KH2PO4 in 0.50 M K2HPO4. Ka1 = 7.5 x 10-3Ka2 = 6.2 x 10-8Ka3 = 4.2 x 10-13

slide45

Calculate pH of:

0.20 M MOHin

0.50 M MCl

Kb = 5.0 x 10-5

slide46

Calculate pH of:

0.20 M MCl

Kb = 5.0 x 10-5

slide48

1.5 L of 0.25 M Ba(OH)2 was added to 1.0 L of 0.60 M H2SO3. Calculate [H2SO3], [HSO3-], [SO3-2], [H+], [OH-], & pH of the solution.Ka1 = 1.7 x 10-2Ka2 = 6.0 x 10-8

slide51

Strong Acids

Strong Bases

slide52

Acid rxns

Base rxns

slide53

A/B Equilibrium Constants

KW, KA, KB, & pH

calculate ph of
Calculate pH of:
  • 0.025 M HNO3
  • 0.020 M KOH
slide55

Calculate pH of:

  • 0.20 M HNO2
  • Ka = 2.0 x 10-4
slide56

Calculate pH of:

  • 3.0 M HZin
  • 2.0 M KZ
  • Ka HZ = 3.0 x 10-5
slide57

Calculate pH of:

  • 0.20 M KR
  • Ka HR = 2.0 x 10-5
slide58

150 mL of 0.10 M KOH was added to 100.0 mL of 0.10 M H2CO3. Calculate [H2CO3], [HCO3-], [CO3-2], [H+], [OH-], & pH of the solution.Ka1 = 4.4 x 10-7Ka2 = 4.7 x 10-11

slide59

Calculate [H3A], [H2A-1], [HA-2], [A-3], [K+], [H+],[OH-], & pH of 2.0 M KH2A. Ka1 = 4.0 x 10-3Ka2 = 5.0 x 10-8Ka3 = 2.5 x 10-13

slide60

Calculate pH of:

  • 2.0 M HQ
  • Ka = 2.0 x 10-6
slide61

Calculate pH of:

  • 0.60 M HZin
  • 0.90 M KZ
  • Ka HZ = 3.0 x 10-5
slide62

Calculate pH of:

  • 0.20 M KQ
  • Ka HQ = 2.0 x 10-7
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