1 / 5

Problem 2-26 - Northside Rifle Team

Problem 2-26 - Northside Rifle Team. Jan White BUS 340 October 31, 2006 Slide #1. Dick and Sally are markspersons on the Northside Rifle Team – their statistics are:. Dick hits the bull’s-eye 90% of the time Sally hits the bull’s-eye 95% of the time Jan White BUS340 Slide #2.

byron-maynard
Download Presentation

Problem 2-26 - Northside Rifle Team

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Problem 2-26 - Northside Rifle Team Jan White BUS 340 October 31, 2006 Slide #1

  2. Dick and Sally are markspersons on the Northside Rifle Team – their statistics are: • Dick hits the bull’s-eye 90% of the time • Sally hits the bull’s-eye 95% of the time • Jan White • BUS340 • Slide #2

  3. Part A.What is the probability that either Dick or Sally or both will hit the bull’s-eye if each takes one shot? • Dick = Event A, Sally = Event B • P(A) + P(B) - P(A and B) = P(A or B) • Not mutually exclusive (there are other outcomes) • .9 + .95 - .855 = .995, or 99.5% of the time either Dick or Sally or both will hit the bull’s-eye. • Can also be shown in terms of “misses”, as 1 – {P(NA) x P(NB)} = 1 – (.1 x .05) = 1 - .005 = .995, or 99.5% chance of not missing • Jan White • BUS340 • Slide #3

  4. Part B. What is the probability that Dick and Sally will both hit the bull’s-eye? • P(A) x P(B) = .9 x .95 = .855, or 85.5% of the time Dick and Sally will both hit the bull’s-eye • Joint probability of multiple, independent events occurring at the same time. • Jan White • BUS 340 • Slide #4

  5. Part C. Did I have any assumptions in answering the questions in parts A and B? If so, do I think I was justified? • Yes, I had the assumption that the events were completely independent. • My justification is that Dick’s marksmanship would not affect Sally’s, and vice-versa, as they each had a record of performance. • Jan White • BUS 340 • Slide #5

More Related