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第三篇 变压器 PowerPoint PPT Presentation


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第三篇 变压器. 变压器:是一种静止的电机,它利用电磁感应原理将一种电压、电流的交流电能转换成同频率的另一种电压、电流的电能。换句话说,变压器就是实现电能在不同等级之间进行转换。. 1.1 变压器的基本结构和分类 一、变压器的基本结构: 电力变压器的基本构成部分有:铁心、绕组、绝缘套管、油箱及其他附件等,其中铁心和绕组是变压器的主要部件,称为器身。图1-2是油浸式电力变压器的结构图。. 我们来看一个简化图 :. 1、铁心和绕组:变压器中最主要的部 件,他们构成了变压器的器身。

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第三篇 变压器

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1.1

1-2


:


1

1

0.350.5mm0.020.23mm



:


2


2

1


2:,

3

4

5


610630kVA8006300kVA800063000kVA90000kVA


1SN

VAkVAMVA

2U2NU2N

U2NU2NVkV

3 I2NI2N


A

4 fN


1.2


2 .1

1.

2.


1

2


3.

1


2

3

u1,u2e1,e2u11u11u22e22e2u22


4

1

=msint



90

2


Z1=R1+ 1

I0Z1U10.2%I0Z1


3

E1E2

U1E1 U20E2


4

0

1


357


2 0

=


5 :

1):


Z0

,


R1 Rm mm pFepFe pFe= RmRm ,,Rm , .,()


Rm mRmXm


2.2


0 1 F0 F1=I1N1m:

F1+ F2= Fm


Z2 =R2+ j ,

R2

F1+F2=F0

I1N1+I2N2=I0N1


F1=F0+-F2

I1=I0+-N2/N1I2=I0+-I2/K


12k=


1 :

==


2

3


1

2


3


ZmZ1I1NI0T


  • Zk=Z1+ 2= Rk+j


2.3

RkxkRmxm

:I0k p0Zm=Rm+jxm



Z0=Z1+Zm=R1+j+Rm+jmRmR1mZ0 Zm=Rm+jm


1.2.U1I0p03.p0.

2


Ik1.2I1N

Ik=f(Uk)pk=fUkpkUk


Xk =

1. 2.75

Rk75 =Rk


  • Rk75= Rk

    Zk75=

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    pkIkUk


2.4

=/

1.

2.

3.


Zk*=0.04~0.175 I0*=0.02~0.10

4.Z k*=UKN*


2.5

1


2

U= 100

=Rk*cos2+xk*sin2100%

U1=U1Ncos 2 =U2I2U2=f(I2)


2


1

P1(pcu1=mI12R1)(pFe=mI02Rm)PM(pcu2=mI22R2):


2

1


2 p0pkN

1.p0pFepFe=p0

2.pkN


pkIK=INpkN=(IN/IK)2PK

3. U2=U2N

P2=mU2I2 cos2=mU2NI2N(I2/I2N)cos2

= SN cos 2


= *100%

0.5

3.

cos 2


1.=0

2.

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m=

=


max= 100

m=0.50.6


3


3.1

:

,


1.

2.



3.2---


A

X

A B C

X Y Z

N

a

x

a b c

x y z

n

Nm


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212

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3

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Y,d,1,3,5,7,9,11.


5

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3.3


YNDyd

1Y,y


1

4560%Yy


2

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3.Yd

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3.4


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2

3


1

2

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2)

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2

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:


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U2=U2N,:


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3.5


1200abc1200acb



  • a

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    a1200a21200


,:

1

1200,

A-B-CA-C-BZ-=Z+=ZK


(2):

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1):

a:Y,,,Y,Z0=

b:YN,,YN,


C:D,D,,,,,,D.:


2

Zm0


3

YNdDynZ0=Zk

YynZ0

UIP

Z0=U/3I

R0=P/3I2


YN,y

Yyn

Y,yn:


:

:


,

Y,:


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:

:


:

,:


:

ZK,Z2Zm0,,,:

  • ZKZm0Z2Zm0 ZKZ2:


ZKZ2 ,:

,:


Ea0 Ea0

Zm0 Ea0ZL


  • ZL =0

    3

  • 0 Yyn



4.1

  • 2~10%


4.1.1


t=01 =0

1 =900


  • =0

  • 2 =0

    t=



412


4.2


  • , 1200


  • 2.

    400-900


4.3


1 2

3 4


5.1


C

= kA

kA


A


SN

SN=1-1/KASN

SN---

1/KASN---




5.2

123


= =

U1=K U2


123


k i I2I1=Ki I 2


  • 1


  • 23


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