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第三篇 变压器 PowerPoint PPT Presentation


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第三篇 变压器. 变压器:是一种静止的电机,它利用电磁感应原理将一种电压、电流的交流电能转换成同频率的另一种电压、电流的电能。换句话说,变压器就是实现电能在不同等级之间进行转换。. 1.1 变压器的基本结构和分类 一、变压器的基本结构: 电力变压器的基本构成部分有:铁心、绕组、绝缘套管、油箱及其他附件等,其中铁心和绕组是变压器的主要部件,称为器身。图1-2是油浸式电力变压器的结构图。. 我们来看一个简化图 :. 1、铁心和绕组:变压器中最主要的部 件,他们构成了变压器的器身。

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第三篇 变压器

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6631075


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1.1

1-2


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:


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1

1

0.350.5mm0.020.23mm


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:


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2


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2

1


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2:,

3

4

5


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610630kVA8006300kVA800063000kVA90000kVA


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1SN

VAkVAMVA

2U2NU2N

U2NU2NVkV

3 I2NI2N


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A

4 fN


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1.2


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2 .1

1.

2.


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1

2


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3.

1


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2

3

u1,u2e1,e2u11u11u22e22e2u22


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4

1

=msint


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90

2


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Z1=R1+ 1

I0Z1U10.2%I0Z1


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3

E1E2

U1E1 U20E2


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4

0

1


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357


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2 0

=


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5 :

1):


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Z0

,


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R1 Rm mm pFepFe pFe= RmRm ,,Rm , .,()


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Rm mRmXm


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2.2


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0 1 F0 F1=I1N1m:

F1+ F2= Fm


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Z2 =R2+ j ,

R2

F1+F2=F0

I1N1+I2N2=I0N1


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F1=F0+-F2

I1=I0+-N2/N1I2=I0+-I2/K


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12k=


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1 :

==


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2

3


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1

2


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3


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ZmZ1I1NI0T


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  • Zk=Z1+ 2= Rk+j


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2.3

RkxkRmxm

:I0k p0Zm=Rm+jxm


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Z0=Z1+Zm=R1+j+Rm+jmRmR1mZ0 Zm=Rm+jm


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1.2.U1I0p03.p0.

2


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Ik1.2I1N

Ik=f(Uk)pk=fUkpkUk


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Xk =

1. 2.75

Rk75 =Rk


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  • Rk75= Rk

    Zk75=

    750C

    pkN= Rk75

    UkN=I1NZk75

    pkIkUk


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2.4

=/

1.

2.

3.


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Zk*=0.04~0.175 I0*=0.02~0.10

4.Z k*=UKN*


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2.5

1


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2

U= 100

=Rk*cos2+xk*sin2100%

U1=U1Ncos 2 =U2I2U2=f(I2)


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2


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1

P1(pcu1=mI12R1)(pFe=mI02Rm)PM(pcu2=mI22R2):


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2

1


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2 p0pkN

1.p0pFepFe=p0

2.pkN


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pkIK=INpkN=(IN/IK)2PK

3. U2=U2N

P2=mU2I2 cos2=mU2NI2N(I2/I2N)cos2

= SN cos 2


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= *100%

0.5

3.

cos 2


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1.=0

2.

3. =0maxm

m=

=


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max= 100

m=0.50.6


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3


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3.1

:

,


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1.

2.


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3.2---


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A

X

A B C

X Y Z

N

a

x

a b c

x y z

n

Nm


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()


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1

212

3

II0IIII6


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YD

XYZABCY

D

y,d


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1Yy


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Yy

1Yy0

2Yy6


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bacbacyxzyxzYy4Yy8Yy10Yy2

2Yd


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1

2AB

3

4ABCabc


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5)Y,y,0,2,4,6,8,10.

Y,d,1,3,5,7,9,11.


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5

YyDd02468106YdDd13579116125Yyn0Yd11YNd11YNy0Yy03II0


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3.3


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YNDyd

1Y,y


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1

4560%Yy


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2

YyYyn1800KVA


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3.Yd

Yd


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3.4


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1

2

3


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1

2

3

1

2)

3

2


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1

2

3


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13 100% 1%10%

:


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,,,, :

:


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,.,,,:

U2=U2N,:


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:

.


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3.5


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1200abc1200acb


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  • a

    a3=1 , a2+a+1=0

    a1200a21200


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,:

1

1200,

A-B-CA-C-BZ-=Z+=ZK


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(2):

:.,,.

1):

a:Y,,,Y,Z0=

b:YN,,YN,


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C:D,D,,,,,,D.:


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2

Zm0


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3

YNdDynZ0=Zk

YynZ0

UIP

Z0=U/3I

R0=P/3I2


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YN,y

Yyn

Y,yn:


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:

:


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,

Y,:


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  • . , ,


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:

:


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:

,:


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:

ZK,Z2Zm0,,,:

  • ZKZm0Z2Zm0 ZKZ2:


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ZKZ2 ,:

,:


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Ea0 Ea0

Zm0 Ea0ZL


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  • ZL =0

    3

  • 0 Yyn


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4.1

  • 2~10%


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4.1.1


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t=01 =0

1 =900


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  • =0

  • 2 =0

    t=


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412


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4.2


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  • , 1200


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  • 2.

    400-900


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4.3


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1 2

3 4


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5.1


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C

= kA

kA


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A


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SN

SN=1-1/KASN

SN---

1/KASN---


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5.2

123


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= =

U1=K U2


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123


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k i I2I1=Ki I 2


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  • 1


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  • 23


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