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Feb. 2, 2011 Rosseland Mean Absorption Poynting Vector Plane EM Waves The Radiation Spectrum: Fourier Transforms PowerPoint PPT Presentation


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Feb. 2, 2011 Rosseland Mean Absorption Poynting Vector Plane EM Waves The Radiation Spectrum: Fourier Transforms. Rosseland Mean Opacity. Recall that for large optical depth . In a star, . is large, but there is a temperature gradient. Plane parallel atmosphere.

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Feb. 2, 2011 Rosseland Mean Absorption Poynting Vector Plane EM Waves The Radiation Spectrum: Fourier Transforms

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Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

Feb. 2, 2011Rosseland Mean AbsorptionPoynting VectorPlane EM WavesThe Radiation Spectrum: Fourier Transforms


Rosseland mean opacity

Rosseland Mean Opacity

Recall that for large optical depth

In a star,

is large, but there is a temperature gradient


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

Plane parallel atmosphere

How does Fn(r) relate to T(r)?

z

dz

ds

so

Equation of radiative transfer:

emission

scattering

absorption


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

= Planck function

For thermal emission:

so

Where the source function


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

Rewrite:

(1)

“Zeroth” order approximation:

Independent of m

1st order approximation:

Equation (1) 

Depends on m


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

= 0


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

Integrate over all frequencies:

Now recall:

s = Stefan-Boltzman Constant


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

Define Rosseland mean absorption coefficient:

Combining,

Equation of radiative diffusion

In the Rosseland Approximation

  • Flux flows in the direction opposite the temperature gradient

  • Energy flux depends on the Rosseland mean absorption coefficient,

  • which is the weighted mean of

  • Transparent regions dominate the mean


Conservation of charge

Conservation of Charge

Follows from Maxwell’s Equations

Take

charge density

But

so

current density


Poynting vector

Poynting Vector

One of the most important properties of EM waves is that they transport

energy—

e.g. light from the Sun has traveled 93 million miles and still has enough

energy to do work on the electrons in your eye!

Poynting vector, S: energy/sec/area crossing a surface whose normal

is parallel to S

Poynting’s theorem: relates mechanical energy performed by the E, B

fields to S and the field energy density, U


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

Mechanical energy:

Lorentz force:

work done

by force

rate of

work

=0 since


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

but also

so...


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

More generally,

where U(mech) = mechanical energy / volume


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

Back to Poynting’s Theorem 

Maxwell’s Equation

use the vector identity

But

and


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

(1)

= field energy / volume

Now

So (1) says

rate of change

of field energy

per volume

rate of change of

mechanical energy

per volume

+


Plane electromagnetic waves

Plane Electromagnetic Waves


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

Maxwell’s Equations in a vacuum:

(3)

(1)

(4)

(2)

These equations predict the existence of WAVES

for E and B which carry energy

Curl of (3) 

use (4) 


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

Use vector identity:

=0 from (1)

Vector

Wave

Equation

SO

Similarly, for B:


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

Note:

operates on each component of

so these 2 vector wave equations are actually 6scalar equations

So, for example, one of the equations is

Similarly for Ey, Ez, Bx, By and Bz


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

What are the solutions to the wave equations?

First, consider the simple 1-D case --

Wave equation

A solution is

A = constant (amplitude)

[kx] = radians [kvt] = radians

So the wave equation is satisfied

Ψ is periodic in space (x) and time (t)


Feb 2 2011 rosseland mean absorption poynting vector plane em waves the radiation spectrum fourier transforms

The wavelength λ corresponds to a change in the argument of

the sine by 2π

frequency

angular frequency


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