# Quiz 10.18.2012 - PowerPoint PPT Presentation

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Quiz 10.18.2012. Given the information above calculate: E[X ] = 30 + 7 = 37 Var [X ] = 510.3+1190.7 = 1701 (bonus) Let Y and Z be random variables. Let E[Y] = 2, Var [Y] = 1, E[Z] = 1, and Var [Z] = 1. Find: E[Y + Z ] = E[Y] + E[Z] = 2 + 1 = 3 Var [2Y ] = 2 2 Var[Y] = 2 2 (1) = 4.

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Quiz 10.18.2012

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### Quiz 10.18.2012

• Given the information above calculate:

• E[X] = 30 + 7 = 37

• Var[X] = 510.3+1190.7 = 1701 (bonus)

• Let Y and Z be random variables. Let E[Y] = 2, Var[Y] = 1, E[Z] = 1, and Var[Z] = 1. Find:

• E[Y + Z] = E[Y] + E[Z] = 2 + 1 = 3

• Var[2Y] = 22Var[Y] = 22(1) = 4