1 / 8

The Volume of the Classroom

The Volume of the Classroom. Answer from Bucharest. Description. This is what Marius wrote:

Download Presentation

The Volume of the Classroom

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. The Volume of the Classroom Answer from Bucharest

  2. Description This is what Marius wrote: “All the corners of our classroom have right angles, so we can call it a big cuboid (not as big as the French one, as we’ll see later). As we measured it, we noticed that there are several beams: 3 on the ceiling, 3 on the widow wall, 3 on the opposite wall and a narrow one in a corner. The volume of the beams must be subtracted from the volume of the classroom. Fotunately, they all are shaped as cuboids, so we only need to use one formula: the volume is length by width by height.”

  3. 3D model These are the 3D models made by Justinian. He used a tool called Google SketchUp.

  4. 3D model

  5. Dimensions Anca and Cristina were in charge with measuring the classroom. Here are the measurements they have taken: Room: l=8,1m, w=6,32 m, h=2,75 m Beam no. 1 (the small one): l=19 cm, w=14 cm, h=2,75 m Beam no. 2 (the horizontal one ones): w=30 cm, h=15,5 cm, l=the width of the room- 2 times the length of beam no.3 Beam no. 3 (the vertical ones): l=29,5 cm, w=35 cm, h=2,75 m We decided to calculate the volume of the air like this: V=Vclass-(V1+3V2+6V3)

  6. At work

  7. Results After using the formula for each volume, this is what we obtained: Vclass=140,778 m3 V1=0,073 m3 V2=0,261 m3 V3=0,284 m3 V= 140,778-(0,073+3x0,261+6x0,284)=138,218 m3 The weight of the air is 179,683 kg

  8. Thank you and good-bye!

More Related