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Medians, Altitudes and Angle Bisectors. Every triangle has 1. 3 medians, 2. 3 angle bisectors and 3. 3 altitudes. BC. AC. AB. B. A. C. Given ABC, identify the opposite side of A. of B. of C. Let L , M and N be the midpoints of AB, BC and AC respectively.
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Every triangle has 1. 3 medians, 2. 3 angle bisectors and 3. 3 altitudes.
BC AC AB B A C • Given ABC, identify the opposite side • of A. • of B. • of C.
Let L, M and N be the midpoints of AB, BC and AC respectively. Hence, CL, AM and NB are medians of ABC. Any triangle has three medians. B L M A N C Definition of a Median of a Triangle A median of a triangle is a segment whose endpoints are a vertex of a triangle and a midpoint of the side opposite that vertex.
BM is a median and BD is an angle bisector of ABC. In the figure, AF, DB and EC are angle bisectors of ABC. Let M be the midpoint of AC. Any triangle has three angle bisectors. B E F A C D M Note: An angle bisector and a median of a triangle are sometimes different. Definition of an Angle Bisector of a Triangle A segment is an angle bisector of a triangle if and only if a) it lies in the ray which bisects an angle of the triangle and b) its endpoints are the vertex of this angle and a point on the opposite side of that vertex.
B C A Any triangle has three altitudes. Definition of an Altitude of a Triangle A segment is an altitude of a triangle if and only if it has one endpoint at a vertex of a triangle and the other on the line that contains the side opposite that vertex so that the segment is perpendicular to this line. ACUTE OBTUSE
BG, AB and BC are its altitudes. Can a side of a triangle be its altitude? YES! A G C B RIGHT If ABC is a right triangle, identify its altitudes.
D Definition of an Equidistant Point A point D is equidistant from B and C if and only if BD = DC. B C If BD = DC, then we say that D is equidistant from B and C.
Let TU be a perpendicular bisector of RS. T V Theorem: If a point lies on the perpendicular bisector of a segment, then the point is equidistant from the endpoints of the segment. M R S U RT = TS RV = VS RU = US Then, what can you say about T, V and U?
Theorem: If a point lies on the perpendicular bisector of a segment, then the point is equidistant from the endpoints of the segment. The converse of this theorem is also true: Theorem: If a point is equidistant from the endpoints of a segment, then the point lies on the perpendicular bisector of the segment.
H F G Given: HF = HG Conclusion: H lies on the perpendicular bisector of FG.
If T is equidistant from R and S and similarly, V is equidistant from R and S, then what can we say about TV? TV is the perpendicular bisector of RS. T V R S Theorem: If two points and a segment lie on the same plane and each of the two points are equidistant from the endpoints of the segment, then the line joining the points is the perpendicular bisector of the segment.
Definition of a Distance Between a Line and a Point not on the Line The distance between a line and a point not on the line is the length of the perpendicular segment from the point to the line.
D Then P is equidistant from AB and AC. B Let AD be a bisector of BAC, P lie on AD, PM AB at M, NP AC at N. M P A Theorem: If a point lies on the bisector of an angle, then the point is equidistant from the sides of the angle. N C
Theorem: If a point lies on the bisector of an angle, then the point is equidistant from the sides of the angle. The converse of this theorem is not always true. Theorem:If a point is in the interior of an angle and is equidistant from the sides of the angle, then the point lies on the bisector of the angle.
