Key Concepts: The pendulum Damped and driven oscillation Traveling waves Standing waves. Physics 221, March 29. The simple pendulum. Hooke’s law: F = - kx x(t) = x max cos ( ω t + φ)) Masses on springs obey Hooke’s law and their motion is simple harmonic motion. The pendulum:
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Hooke’s law: F = -kx x(t) = xmaxcos(ωt + φ)) Masses on springs obey Hooke’s law and their motion is simple harmonic motion.
For a given displacement from equilibrium s = Lθ, the net force on the pendulum bob is F =-mgsinθ.
For small displacements sinθ ~ θ, so we can write F =-mgθ = - (mg/L)*Lθ = -ks, with k = (mg/L)
F obeys Hooke’s law.Hooke’s law simple harmonic motion
s(t) = smaxcos(ωt + φ)) ω2 = k/m = g/L
, f = 1/T
Extra credit:A simple pendulum consists of a point mass m suspended by a massless, unstretchable string of length L. If the mass is doubled while the length of the string remains the same, the period of the pendulum
A simple pendulum of length L oscillates back and forth 10 times per second. By what factor do you have to change its length to make it oscillate back and forth only 5 times per second.
A simple pendulum of length L oscillates back and forth 10 times per second.
By what factor do you have to change its length to make it oscillate back and
forth only 5 times per second.
You want to double the period.
You must increase L by a factor of 4.
Link: Pendulum Waves
Free oscillations of macroscopic systems damp out.
If the total force on the damped system is
F = -kx – bv,
then the motion of the system is given by
x(t) = A0exp(-bt/2m)cos(ωdampt + φ),
with ωdamp2 = k/m - (b/2m)2.
The energy stored in the system is proportional to the square of its amplitude, it decreases as E = E0exp(bt/m).
A -> A0/2 implies E -> E0/4
You are watching a mass oscillate on a spring. times per second. The initial amplitude is 10 cm. You measure the period to be a constant 1.1 s. The energy E stored in the oscillating system halves after 10 s. How long does it take for the amplitude of the oscillation to decrease to 5 cm?
Assume we have a damped harmonic oscillator acted on by a driving force F0cos ωextt .
The net force acting on the oscillator is
F = F0cosωextt - kx – bv.
The resulting motion is
x(t) = Acos(ωextt + φ).
The amplitude of forced oscillations is small unless the driving frequency
is close to the natural frequency.
When the driving frequency is equal to the natural frequency the amplitude of
the oscillations can be become very large - this is called resonance.
Consider a tractor driving across a field that has undulations at regular intervals. The distance between the bumps is about 4.2 m. Because of safety reasons, the tractor does not have a suspension system but the driver’s seat is attached to a spring to absorb some of the shock as the tractor moves over rough ground. The natural frequency of the driver and the seat is f = 2 Hz. At what speed does the drive become dangerous?
The distance between the bumps is about undulations at regular intervals. The distance between the bumps is about 4.2 m. The natural frequency of the driver and the seat is f = 2 Hz. At what speed does the drive become dangerous?
The drive becomes dangerous when the frequency with which the tractor encounters the bumps equals the natural frequency of the driver and the seat, or when the time interval between hitting the bumps equals the natural period.
f = 2 Hz = 2/s, T = 0.5 s.
v = 4.2 m / T = 8.4 m/s.
Periodic, sinusoidal waves in one dimension:
The displacement as a function of position and time is given by
y(x,t) = A sin(kx-ωt + φ)
for a wave traveling in the +x direction, and by
y(x,t) = A sin(kx+ωt + φ)
for a wave traveling in the -x direction.
k is the wavenumber, k = 2π/λ.
ω = 2π/T = 2πf is the angular frequency.
φ is called the phase constant.
λ = wavelength, f = frequency, T = period, v = λ/T = λf = ω/k = speed.
The energy E transported by the wave is proportional to A2.
The power P is proportional to A2v.
For waves on a string:
Extra credit: undulations at regular intervals. The distance between the bumps is about A wave travelling in the +x direction is described by the equationy = 0.1 sin (10 x − 100 t)where x and y are in meters and t is in seconds.Calculate(i) the wavelength, (ii) the period,(iii) the speed, and(iv) the amplitude of the wave
Extra point: undulations at regular intervals. The distance between the bumps is about If you double the wavelength λ of a wave on a string under fixed tension, what happens to the wave speed v and the wave frequency f?
A travelling wave is described by the equation undulations at regular intervals. The distance between the bumps is about y(x,t) = (0.003) cos(20 x + 200 t )where y and x are measured in meters and t in secondsWhat is the direction in which the wave is travelling?
The four strings of a musical instrument are all made of the same material and are under the same tension, but have different thicknesses. Waves travel
For a string fixed on both endsa standing waveforms when
an integral number of half wavelengths fit into the length of