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Enrichment - Rate Equations to Determine Reaction Order PowerPoint Presentation

Enrichment - Rate Equations to Determine Reaction Order

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Enrichment - Rate Equations to Determine Reaction Order

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The equation for a straight line is:. Compare this equation to the rearranged first order rate-law. Enrichment - Rate Equations to Determine Reaction Order . Enrichment - Rate Equations to Determine Reaction Order . Now we can interpret the parts of the equation as follows:

Enrichment - Rate Equations to Determine Reaction Order

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The equation for a straight line is:

Compare this equation to the rearranged first order rate-law.

- Now we can interpret the parts of the equation as follows:
- y can be identified with ln[A] and plotted on the y-axis.
- m can be identified with –ak and is the slope of the line.
- x can be identified with t and plotted on the x-axis.
- b can be identified with ln[A]0and is the y-intercept.

- Example 16-9: Concentration-versus-time data for the thermal decomposition of ethyl bromide are given in the table below. Use the following graphs of the data to determine the rate of the reaction and the value of the rate constant.

- We will make three different graphs of the data.
- Plot the [C2H5Br] (y-axis) vs. time (x-axis)
- If the plot is linear then the reaction is zero order with respect to [C2H5Br].

- Plot the ln [C2H5Br] (y-axis) vs. time (x-axis)
- If the plot is linear then the reaction is first order with respect to [C2H5Br].

- Plot 1/ [C2H5Br] (y-axis) vs. time (x-axis)
- If the plot is linear then the reaction is second order with respect to [C2H5Br].

- Plot of [C2H5Br] versus time.
- Is it linear or not?

- Plot of ln [C2H5Br] versus time.
- Is it linear or not?

- Plot of 1/[C2H5Br] versus time.
- Is it linear or not?

- Note that the only graph which is linear is the plot of ln[C2H5Br] vs. time.
- Thus this is a first order reaction with respect to [C2H5Br].

- Next, we will determine the value of the rate constant from the slope of the line on the graph of ln[C2H5Br] vs. time.
- Remember slope = y2-y1/x2-x1.

- From the equation for a first order reaction we know that the slope = -a k.
- In this reaction a = 1.

The integrated rate equation for a reaction that is second order in reactant A and second order overall.

This equation can be rearranged to:

Compare the equation for a straight line and the second order rate-law expression.

Now we can interpret the parts of the equation as follows:

y can be identified with 1/[A] and plotted on the y-axis.

m can be identified with a k and is the slope of the line.

x can be identified with t and plotted on the x-axis

b can be identified with 1/[A]0 and is the y-intercept.

- Example 16-10: Concentration-versus-time data for the decomposition of nitrogen dioxide are given in the table below. Use the graphs to determine the rate of the reaction and the value of the rate constant

- Once again, we will make three different graphs of the data.
- Plot [NO2] (y-axis) vs. time (x-axis).
- If the plot is linear then the reaction is zero order with respect to NO2.

- Plot ln [NO2] (y-axis) vs. time (x-axis).
- If the plot is linear then the reaction is first order with respect to NO2.

- Plot 1/ [NO2] (y-axis) vs. time (x-axis).
- If the plot is linear then the reaction is second order with respect to NO2.

- Plot of [NO2] versus time.
- Is it linear or not?

- Plot of ln [NO2] versus time.
- Is it linear or not?

- Plot of 1/[NO2] versus time.
- Is it linear or not?

- Note that the only graph which is linear is the plot of 1/[NO2] vs. time.
- Thus this is a second order reaction with respect to [NO2].
- Next, we will determine the value of the rate constant from the slope of the line on the graph of 1/[NO2] vs. time.

- From the equation for a first order reaction we know that the slope = a k
- In this reaction a = 2.