10320 cow trouble help please
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10320 Cow Trouble! Help Please!! PowerPoint PPT Presentation


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10320 Cow Trouble! Help Please!!. ★★★☆☆ 題組: Contest Archive with Online Judge 題號: 10320 Cow Trouble! Help Please!! 解題者: 郭真爾 解題日期: 20 13 年 4 月 25 日 題意: 有一頭牛被一根長度 R 的繩子拴在一棟建築物 ABCD 的 B 點上 , 草地的範圍為無限大,求牛可以吃到的草的範圍。 Input 會給 l, w  和 R  表示建築物長寬和繩長; l,w,R< 10000 。 Output 要輸到小數點第 10 位。. 題意範例:

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10320 Cow Trouble! Help Please!!

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10320 cow trouble help please

10320 Cow Trouble! Help Please!!

  • ★★★☆☆

  • 題組:Contest Archive with Online Judge

  • 題號:10320 Cow Trouble! Help Please!!

  • 解題者:郭真爾

  • 解題日期:2013年4月25日

  • 題意:有一頭牛被一根長度R的繩子拴在一棟建築物ABCD的B點上,草地的範圍為無限大,求牛可以吃到的草的範圍。Input會給l, w 和R 表示建築物長寬和繩長;l,w,R< 10000。Output要輸到小數點第10位。


10320 cow trouble help please

  • 題意範例:

    10 5 5 → l=10 , w=5 , R=5

    10 4 8 → l=10 , w=4 , R=8

  • 解法:用繩長R來分各種情況利用暴力法去計算面積

  • 解法範例:

    (1) R<=w

    l=10 , w=5 , R=5

    PI*R*R*3/4=58.9048622548


10320 cow trouble help please

(2) w<R<=l

l=10 , w=4 , R=8

PI*R*R*3/4 + PI*(R-w)*(R-w)*1/4

= 163.3628179867

(3) l<R<=l+w

Ans = PI*R*R*3/4

+ PI*(R-w)*(R-w)*1/4

+ PI*(R-l)*(R-l)*1/4


10320 cow trouble help please

(4) l+w<R

Ans= PI*R*R*3/4

+ PI*(R-w)*(R-w)*1/4

+ PI*(R-l)*(R-l)*1/4

-扇形DMK

-扇形AKN

+多邊形ACDK


10320 cow trouble help please

  • 討論:#define PI 2*acos(0)


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