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Jeopardy. Chemistry Chapter 11 Review Game **Complete Balancing Formulas Section before moving on to the rest of the questions…. Select a Category. Balancing Formulas. __H 2 SO 4 + __Pb(OH) 4  __Pb(SO 4 ) 2 + __H 2 O. 1 point. Check. Balancing Formulas.

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jeopardy

Jeopardy

Chemistry

Chapter 11 Review Game

**Complete Balancing Formulas Section before moving on to the rest of the questions…

balancing formulas
Balancing Formulas

__H2SO4 + __Pb(OH)4 __Pb(SO4)2 + __H2O

1 point

Check

balancing formulas1
Balancing Formulas

_2_H2SO4 + _1_Pb(OH)4 _1_Pb(SO4)2 + _4_H2O

1 point

Back to Category Slide

balancing formulas2
Balancing Formulas

__Al + __HCl  __AlCl3 + __H2

2 points

Check

balancing formulas3
Balancing Formulas

_2_Al + _6_HCl  _2_AlCl3 + _3_H2

2 points

Back to Category Slide

balancing formulas4
Balancing Formulas

__CO + __H2 __C8H18 + __H2O

3 points

Check

balancing formulas5
Balancing Formulas

_8_CO + _17_H2 _1_C8H18 + _8_H2O

3 points

Back to Category Slide

balancing formulas6
Balancing Formulas

__HClO4 + __P4O10 __H3PO4 + __Cl2O7

4 points

Check

balancing formulas7
Balancing Formulas

_12_HClO4 + _1_P4O10 _4_H3PO4 + _6_Cl2O7

4 points

Back to Category Slide

balancing formulas8
Balancing Formulas

Ammonium Phosphate reacts with Lead IV Nitrate in a double replacement reaction.

5 points

Check

balancing formulas9
Balancing Formulas

_4_(NH4)3PO4 + _3_Pb(NO3)4 _1_Pb3(PO4)4 + _12_NH4NO3

5 points

Back to Category Slide

easy stoichiometry 2 h 2 so 4 1 pb oh 4 1 pb so 4 2 4 h 2 o
Easy Stoichiometry_2_H2SO4 + _1_Pb(OH)4 _1_Pb(SO4)2 + _4_H2O

The mole to mole ratio between lead IV hydroxide and dihydrogen monoxide.

1 point

Check

easy stoichiometry
Easy Stoichiometry

What is 1 to 4?

1 point

Back to Category Slide

easy stoichiometry 2 h 2 so 4 1 pb oh 4 1 pb so 4 2 4 h 2 o1
Easy Stoichiometry_2_H2SO4 + _1_Pb(OH)4 _1_Pb(SO4)2 + _4_H2O

2.5 moles of sulfuric acid are used with excess reactants. This many moles of lead IV sulfate will be produced.

2 points

Check

easy stoichiometry1
Easy Stoichiometry

What is 1.3 (sf) moles of lead IV sulfate?

2 points

Back to Category Slide

easy stoichiometry 2 h 2 so 4 1 pb oh 4 1 pb so 4 2 4 h 2 o2
Easy Stoichiometry_2_H2SO4 + _1_Pb(OH)4 _1_Pb(SO4)2 + _4_H2O

The number of grams of water that are produced when 2.5 moles of lead IV hydroxide are used with excess sulfuric acid.

3 points

Check

easy stoichiometry2
Easy Stoichiometry

What is 180 g of H2O?

3 points

Back to Category Slide

easy stoichiometry 2 h 2 so 4 1 pb oh 4 1 pb so 4 2 4 h 2 o3
Easy Stoichiometry_2_H2SO4 + _1_Pb(OH)4 _1_Pb(SO4)2 + _4_H2O

The number of mL of sulfuric acid that are needed to produce 15.7 grams of water.

4 points

Check

easy stoichiometry3
Easy Stoichiometry

What is 9770 mL?

4 points

Back to Category Slide

easy stoichiometry 2 h 2 so 4 1 pb oh 4 1 pb so 4 2 4 h 2 o4
Easy Stoichiometry_2_H2SO4 + _1_Pb(OH)4 _1_Pb(SO4)2 + _4_H2O

The number of hydrogen atoms that are found in 4.5 moles of water.

5 points

Check

easy stoichiometry4
Easy Stoichiometry

What is 5.4 x 1024 H atoms?

5 points

Back to Category Slide

hard stoichiometry 12 hclo 4 1 p 4 o 10 4 h 3 po 4 6 cl 2 o 7
Hard Stoichiometry_12_HClO4 + _1_P4O10 _4_H3PO4 + _6_Cl2O7

The number of moles of tetraphosphorus decaoxide that are needed to react completely with 1.4 mol of HClO4 (perchloric acid)

1 point

Check

hard stoichiometry
Hard Stoichiometry

What is 0.12 moles?

1 point

Back to Category Slide

hard stoichiometry 12 hclo 4 1 p 4 o 10 4 h 3 po 4 6 cl 2 o 71
Hard Stoichiometry_12_HClO4 + _1_P4O10 _4_H3PO4 + _6_Cl2O7

The number of moles produced of Cl2O7 when 4.5 g P4O10 react with 85 g of HClO4.

2 points

Check

hard stoichiometry1
Hard Stoichiometry

What is 0.095 mol Cl2O7?

2 points

Back to Category Slide

hard stoichiometry 12 hclo 4 1 p 4 o 10 4 h 3 po 4 6 cl 2 o 72
Hard Stoichiometry_12_HClO4 + _1_P4O10 _4_H3PO4 + _6_Cl2O7

The number of Cl atoms that are produced when 23.5 g of HClO4 react with 22.5 g of P4O10.

3 points

Check

hard stoichiometry2
Hard Stoichiometry

What is 1.41 x 1023 Cl atoms?

3 points

Back to Category Slide

hard stoichiometry 12 hclo 4 1 p 4 o 10 4 h 3 po 4 6 cl 2 o 73
Hard Stoichiometry_12_HClO4 + _1_P4O10 _4_H3PO4 + _6_Cl2O7

The number of oxygen atoms that will be found in products when 2.5 g of both HClO4 and P4O10 react together.

4 points

Check

hard stoichiometry3
Hard Stoichiometry

What is 7.2 x 1022 O atoms?

5 points

Back to Category Slide

yield
% Yield

Three reasons when % composition can never be greater than 100%.

1 point

Check

yield1
% Yield

What is:

1) impure reactants

2) Competing side reactions

3) Loss of reactants and products during transfer

1 point

Back to Category Slide

yield 4 nh 4 3 po 4 3 pb no 3 4 1 pb 3 po 4 4 12 nh 4 no 3
% Yield_4_(NH4)3PO4 + _3_Pb(NO3)4 _1_Pb3(PO4)4 + _12_NH4NO3

The % composition when 12.5 grams of lead IV nitrate are produced in a lab, but mathematically was supposed to produce 13.4 g.

2 points

Check

yield2
% Yield

What is 93.3% yield?

2 points

Back to Category Slide

yield3
% Yield

Determine the percent yield for the reaction between 2.80 g Al(NO3)3 and excess NaOH if 0.966 g Al(OH)3 is recovered.

3 points

Check

yield4
% Yield

What is 93.8%?

3 points

Back to Category Slide

yield5
% Yield

Determine the percent yield for the reaction between 15.0 g N2 and 15.0 g H2 if 10.5 g NH3 are produced.

4 points

Check

yield6
% Yield

What is 57.7%?

4 points

Back to Category Slide

yield7
% Yield

A piece of copper with a mass of 5.00 g is placed in a solution of silver nitrate containing excess AgNO3. The silver metal produced has a mass of 15.2 g. This is the percent yield for this reaction.

5 points

Check

yield8
% Yield

What is 89.4%?

5 points

Back to Category Slide

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