Exponential Function 5 Item MCQ

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# Exponential Function 5 Item MCQ - PowerPoint PPT Presentation

Exponential Function 5 Item MCQ. ANSILUZ H. BETCO San Bartolome High School. NEXT. Directions. Read and analyze the following questions properly. Click on the correct answer. BACK. NEXT. 1 . Which of the following define an exponential function?. BACK. NEXT.

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### Exponential Function5 Item MCQ

ANSILUZ H. BETCO

San Bartolome High School

NEXT

Directions

following questions

properly. Click on the

BACK

NEXT

BACK

NEXT

a) 2x2 + 3x – 6= 8

b) 2/3 m – 5 = 15

c) y = 2x + 1

d) p3 + 2p -3 = 0

Correct!!

Feedback to Q1

BACK

Exponential Function

Definition:

→ If a>0 and a ≠ 1,then the exponential function with the base a is a function defined by f(x) = ax, where x is any real numbers.

→ therefore y= 2x +1 is the only equation wherein the exponent x vary.

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2) Which of the following graphs represent an exponential function?

a)b)

d)

c)

BACK

NEXT

Correct!!

Feedback to Q2

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Graph of Exponential Function

The graph of y = ax is upward-sloping, and

increases faster as x increases. The graph

always lies above the x-axis but can get

arbitrarily close to it for negative x; thus,

the x-axis is a horizontal asymptote. The

slope of the graph at each point is equal

to its y coordinate at that point.

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3) Solve for x: 93x = (1/3)5-x

a) x = 1

b) x = -1

c) x = 2

d) x = -2

BACK

NEXT

Correct!!

Feedback to Q3

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3) 93x = (1/3)5-x

• Solution

93x = (1/3)5-x

32(3x)= 3-1(5-x) change the equation with same base

6x = -5+x bring down the exponents

5x = -5 solve for x

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4) A certain city has a population of 20000 and a growth rate of 3.5%.What will be the expected population after 3 years?
• 24,145
• 23,501
• 23,219
• 22,174

BACK

Correct!!

Feedback to Q4

BACK

The Exponential Growth is in the form

Y = P( 1 + r)xwhere P = original number

r = rate of change

x = unit of time

y = total number after x years

So, P = 20000 r = 3.5% or 0.035 t = 3 years

Substitute Y = P( 1 + r)x

= 20,000 (1 + .035)3

= 20,000 (1.035)3

= 20,000 (1.1087)

= 22,174 expected population after 3 yrs

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5) If a car depreciates at an annual rate of 15%, how much would be its value at the end of two years if its cost is \$450,000 when new? a) \$325,125 b) \$276,356c) \$315,134d) \$412,300

BACK

Correct!!

Feedback to Q5

BACK

The Exponential Decay is in the form

Y = P( 1 - r)xwhere P = original amount

r = rate of change

x = unit of time

y = total amount after x years

So, P= \$450,000 r = 15% or 0.15 t= 2 years

Substitute Y = P( 1 - r)x

= 450,000 (1 - .15)2

= 450,000 (0.85)2

= 450,000 (0.7225)

= \$325,125 amount of car after 2 years

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