- 83 Views
- Uploaded on
- Presentation posted in: General

Exponential Function 5 Item MCQ

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Exponential Function5 Item MCQ

ANSILUZ H. BETCO

San Bartolome High School

NEXT

Read and analyze the

following questions

properly. Click on the

correct answer.

BACK

NEXT

BACK

NEXT

a) 2x2 + 3x – 6= 8

b) 2/3 m – 5 = 15

c) y = 2x + 1

d) p3 + 2p -3 = 0

Correct!!

Feedback to Q1

BACK

Definition:

→ If a>0 and a ≠ 1,then the exponential function with the base a is a function defined by f(x) = ax, where x is any real numbers.

→ therefore y= 2x +1 is the only equation wherein the exponent x vary.

NEXT

a)b)

d)

c)

BACK

NEXT

Correct!!

Feedback to Q2

BACK

The graph of y = ax is upward-sloping, and

increases faster as x increases. The graph

always lies above the x-axis but can get

arbitrarily close to it for negative x; thus,

the x-axis is a horizontal asymptote. The

slope of the graph at each point is equal

to its y coordinate at that point.

NEXT

a) x = 1

b) x = -1

c) x = 2

d) x = -2

BACK

NEXT

Correct!!

Feedback to Q3

BACK

3) 93x = (1/3)5-x

- Solution
93x = (1/3)5-x

32(3x)= 3-1(5-x) change the equation with same base

6x = -5+x bring down the exponents

5x = -5 solve for x

x = -1 answer

NEXT

- 24,145
- 23,501
- 23,219
- 22,174

BACK

Correct!!

Feedback to Q4

BACK

The Exponential Growth is in the form

Y = P( 1 + r)xwhere P = original number

r = rate of change

x = unit of time

y = total number after x years

So, P = 20000 r = 3.5% or 0.035 t = 3 years

Substitute Y = P( 1 + r)x

= 20,000 (1 + .035)3

= 20,000 (1.035)3

= 20,000 (1.1087)

= 22,174 expected population after 3 yrs

NEXT

5) If a car depreciates at an annual rate of 15%, how much would be its value at the end of two years if its cost is $450,000 when new? a) $325,125 b) $276,356c) $315,134d) $412,300

BACK

Correct!!

Feedback to Q5

BACK

The Exponential Decay is in the form

Y = P( 1 - r)xwhere P = original amount

r = rate of change

x = unit of time

y = total amount after x years

So, P= $450,000 r = 15% or 0.15 t= 2 years

Substitute Y = P( 1 - r)x

= 450,000 (1 - .15)2

= 450,000 (0.85)2

= 450,000 (0.7225)

= $325,125 amount of car after 2 years

NEXT

i'm sorry

Try again !

i'm sorry

Try again !